What play did Mr. and Mrs. Lincoln plan to see at Ford's Theater on the night Mr. Lincoln was assassinated?

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Answer 1
Answer: Our American Cousin was the play he was watching when he was shot.

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If a force does not act parallel to the resulting displacement, what is the effect on the work done by the force?
4. A 1500 kg car is rolling at 2.0 m/s. You would like to stop the car by firing a 10 kg blob ofsticky clay at it. How fast should you fire the clay?
Adam applies an input force to the pulley as he pulls down to lift the object. As he does this, Adam wonders about how the pulley is helping him. How is the pulley helping Adam lift the object?a. All of these answers are correct. b. A fixed pulley lowers the amount of force needed to do the same amount of work. c. A fixed pulley increases the distance over which the force is applied. d. A fixed pulley helps Adam change the direction of the effort force.
6. State whether each of the following is an example of conduction, convection, and/or radiation. Explain if you think there is more than one possibility. (a)You are cooking, and the handle of the spoon you are using to stir the soup starts to feel hot. (b)A pail of hot water is added to a child’s inflatable pool. After a while, the pool is warm. (c)You go to the park, and when you sit on a metal bench, it is hot. (d)You are standing near a barbecue, and you feel the heat on your face.
A disturbance that transfers energy from place to place is called aa. wave.b. medium.c. vibration.d. compression.

The process shown in this diagram contributed great amounts of heat to the young planet Earth and is best known as radioactive A) decay.
B) fission.
C) fusion.
D) isotope.

Answers

The process shown in this diagram contributed great amounts of heat to the young planet Earth and is best known as radioactive decay. Decay is known to release large amounts of heat.
Hey there

I believe the correct answer is (A) 

(A) = Decay 

Two harmonic waves moving in the same direction are described by y1(x,t)=10.2sin(4x-700t) and y2(x,t)=10.2sin(4x-700t-7.9). What is the amplitude of the resultant wave at interference

Answers

Answer:

14.42 units

Explanation:

The waves are given as follows :

y_1(x,t)=10.2\sin(4x-700t)\n\ny_2(x,t)=10.2\sin(4x-700t-7.9)

We need to find the amplitude of the resultant wave at interference. Let it be A. So,

A=√(10.2^2+10.2^2) \n\n=14.42\ units

So, the amplitude of the resultant wave is equal to 14.42 units.

When particles move past each other with ease it is called _____.a. effusion
b. fluidity
c. density
d. compressibility

Answers

fluidity is the answer
B. its fluidity, particles of a gas move freely

What type of heat transfer is used to fry an egg in a pan and how can you tell?A) It is conduction because the egg gets cooked.
B) It is conduction because the egg is touching the pan.
C) It is convection because you put oil in a frying pan to cook in it.
D) It is convection because you can feel the heat a few inches away from the pan.

Answers

Answer: Option (B) is the correct answer.

Explanation:

A process in which transfer of heat occurring when one object touches another object is known as conduction.  

For example, when a pan is heated and then an egg is placed over the pan. Then there will be transfer of heat from pan towards the egg.

As a result, the egg gets cooked because the egg was touching the pan.

Hence, we can conclude that it is conduction because the egg is touching the pan.

Heat transfer is used to fry an egg in a pan, It is conduction because the egg is touching the pan. Hence the correct option is option (B).

When frying an egg in a pan, the primary mode of heat transfer is conduction. Conduction is the transfer of heat through direct contact between two objects or substances.

The pan is heated on a stovetop or a heat source, which causes the pan to become hot. When the egg is placed in the pan, the heat from the pan is transferred to the egg through the process of conduction.

Option A suggests that it is conduction because the egg gets cooked, but this answer does not explain the specific mechanism of heat transfer involved.

Option C mentions convection because oil is used in frying. While oil can enhance the cooking process, convection is not the primary mode of heat transfer in this scenario.

Option D states it is convection because you can feel the heat a few inches away from the pan.

Therefore, option B is the correct answer, as it correctly identifies that the heat transfer involved in frying an egg in a pan is conduction because the egg is touching the pan.

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A horizontal 20.-newton force is applied to a 5.0-kilogram box to push it across a rough,horizontal floor at a constant velocity of 3.0 meters per second to the right.

Calculate the coefficient of kinetic friction between the box and the floor. [Show all work, including
the equation and substitution with units]

Answers

The formula to work out the coefficient of dynamic (kinetic) friction is F=uR where F is the force applied, u is the coefficient of dynamic friction, and R is the reaction force. This is based on the principle the object is moving at a constant velocity which is the case in this question.

Rearranging this we get u=F/R
Substituting in the values we get u=20/50=2/5=0.4

Therefore the coefficient of kinetic friction between the box and the floor is 0.4

The coefficient of kinetic friction between the box and the floor will be \boxed{0.4} .

Further Explanation:

Given:

The mass of the box is 5\,{\text{kg}} .

The force applied on the box is 20\,{\text{N}} .

The constant velocity at which the box moves is 3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}} .

Concept:

The box is pushed on the rough floor and due to this; the box will experience a friction force acting in the direction opposite to the motion of the box.

Since the box moves with a constant velocity of 3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}} , the acceleration of the box will be considered as zero.

From Newton’s second law of motion, as the acceleration of the box is zero, the net force acting on the box is zero.

\boxed{{F_(net)}=m* a}

The free-body diagram of the box moving on the rough floor is as shown in figure attached below.

From the above explanation, in order to make the net force zero, the friction acting on the box should be equal to the force applied on the box.

{F_(friction)}={F_(applied)}

The friction force acting on the bxlock is:

\begin{aligned}{F_(friction)}&=\mu N\n&=\mu mg\n\end{aligned}

Substitute the value of friction force in the above expression.

\begin{aligned}\mu mg&={F_(applied)}\n\mu\left({5*10}\right)&=20\n\mu &=\frac{{20}}{{50}}\n&=0.4\n\end{aligned}

Thus, the coefficient of kinetic friction between the box and the floor will be  \boxed{0.4}.

Learn More:

1. A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N brainly.com/question/7031524

2. Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off brainly.com/question/4033012

3. Which of the following is not a component of a lever brainly.com/question/1073452

Answer Details:

Grade: High School

Subject: Physics

Chapter: Friction

Keywords:

Horizontal 20N force, 5 kg box, push, a rough horizontal floor, constant velocity, friction force, coefficient of kinetic friction, box and the floor.

A spherical raindrop 2.7 mm in diameter falls through a vertical distance of 3950 m. take the cross-sectional area of a raindrop = πr2, drag coefficient = 0.45, density of water to be 1000 kg/m3, and density of air to be 1.2 kg/m3. (a) calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag.

Answers

Final answer:

The speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag is calculated by firstly finding the time it takes for the raindrop to fall this distance using equations of motion, and then using this time in the equation for final velocity. The calculated speed is approximately 2785.30 m/s.

Explanation:

To calculate the speed a spherical raindrop would achieve falling from 3950 m in the absence of air drag, we must recall the equations of motion. The relevant equation here is Final velocity (v) = Initial velocity (u) + Acceleration (gravity, g) * time (t). However, since initial velocity (u) is 0 (when the drop starts falling, it's stationary), the equation simplifies to Final velocity (v) = g * t.

In free fall, a body accelerates under gravity (approximated as 9.81 m/s^2). In terms of time, difficulties arise because we don't know exactly when the raindrop will hit the ground. We can, however, calculate the time it would take for the raindrop to fall 3950 m by rearranging the equation distance (s) = ut + 0.5 * g * t^2 to solve for time. Removing (u), for the reasons explained earlier, we have the equation s = 0.5 * g * t^2. Solving this for time gives t = sqrt(s / (0.5 * g)). Substituting the given fall distance for s we get t = sqrt(3950 / (0.5 * 9.81)) or approximately 284.10 seconds.

Finally, we use this calculated time in our simplified velocity equation which gives v = g * t or 9.81 * 284.10, which equals approximately 2785.30 m/s.

Learn more about Physics of Free Fall here:

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