PHYSICS MIDDLE SCHOOL

3. The smallest bird is the Cuban bee hummingbird, which has a mass of only1.7 g. If this bird did 8.8 x 10-4 J of work by exerting an upward force of
3.4 x 10-N, how far did it fly?

Answers

Answer 1
Answer:

Answer:

2.6 m

Explanation:

The work done by the bird is given by

W=Fd

where

F is the force exerted

d is the distance covered

In this problem, we know:

W=8.8\cdot 10^(-4) J is the work

F=3.4\cdot 10^(-4) N is the force

Solving the equation for d, we find the distance covered by the bird:

d=(W)/(F)=(8.8\cdot 10^(-4))/(3.4\cdot 10^(-4))=2.6 m
Answer 2
Answer:

Final answer:

The Cuban bee hummingbird flew approximately 2.59 x 10^-2 meters.

Explanation:

To determine the distance the bird flew, we can use the equation: work = force x distance. Rearranging the equation, distance = work / force. Plugging in the values, we have distance = (8.8 x 10-4 J) / (3.4 x 10-2 N). Solving this equation gives us a distance of approximately 2.59 x 10-2 meters.

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Which object moves in simple harmonic motion?\a stretched rubber band with an mass
b rolling ball going down a hill
c moving car
d orbiting satellite

Answers

Answer:Stretched rubber band with an mass

Explanation:

Simple harmonic motion requires a restoring force.

Simple harmonic motion should be periodic.

Option A:

When a rubber band is stretched,the internal forces of the rubber band pulls the band inside.So,internal forces are the restoring forces in a rubber band.

The motion is periodic as well since the the rubber band makes to an fro motion expanding ans contracting.

So,this performs SHM.

Option B:

There is no restoring force and no periodicity.

So,this is not SHM.

Option C:

There is no restoring force and no periodicity.

So,this is not SHM.

Option D:

There is periodicity but no restoring force.

So,this is not SHM.

Scientists studied predator-prey relationships in a habitat. The diagram below shows the feeding relationships among organisms that a scientist might find in a certain environment.Which animal is both a predator and prey?


owl
plant
snake
cricket

Answers

the cricket is a predator and a prey

Answer:

snake

Explanation:

The KE of a body becomes 2 times of its original value then the new momentum will be more than its initial momentum by​

Answers

Answer:

√2

Explanation:

If the final kinetic energy is 2 times the initial kinetic energy:

KE = 2 KE₀

½ mv² = 2 (½ mv₀²)

v² = 2 v₀²

v = √2 v₀

Therefore, the ratio of the final momentum to the initial momentum is:

p / p₀

mv / (mv₀)

v / v₀

√2

Question 1
Which compounds are both classified as electrolytes?

Answers

The answer is in the picture down \/

Hope this helps you !!!!

Have a nice day/night

A merry -go-round rotates at the rate of 0.4rev / s with an 78 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point m from the center? Consider the merry-go-round is a solid 11 kg cylinder of radius of 1,5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement ? Answer in units of

Answers

1) Final angular velocity is 5.22 rad/s

2) Change in kinetic energy: 639.8 J

Explanation:

1)

In absence of external forces, the angular momentum of the merry-go-round must be conserved.

So we can write:

L_1 = L_2\nI_1\omega_1 = I_2 \omega_2

where

I_1 is the initial moment of inertia

I_2 is the final moment of inertia

\omega_1 is the initial angular velocity

\omega_2 is the final angular velocity

At the beginning, we have:

\omega_1=0.4 rev/s \cdot 2\pi = 2.51 rad/s

The moment of inertia is the sum of the moment of inertia of the cylinder + the moment of inertia of the man, therefore:

I_1 = (1)/(2)MR^2+mr^2=(1)/(2)(11)(1.5)^2+(78)(1.5)^2=187.9 kgm^2

The man later walks to a point 1 m from the centre, so the final moment of inertia is:

I_2 = (1)/(2)MR^2+mr^2=(1)/(2)(11)(1.5)^2+(78)(1)^2=90.4 kgm^2

Therefore, the final angular velocity is

\omega_2 = (I_1 \omega_1)/(I_2)=((187.9)(2.51))/(90.4)=5.22 rad/s

2)

The angular velocity of the merry-go-round rotating is given by

K=(1)/(2)I\omega^2

In the  first situation, we have

I_1 = 187.9 kg m^2\n\omega=2.51 rad/s

Therefore

K_1 = (1)/(2)(187.9)(2.51)^2=591.8 J

In the second situation, we have

I_2= 90.4 kg m^2\n\omega_2=5.22 rad/s

Therefore

K_2=(1)/(2)(90.4)(5.22)^2=1231.6 J

So the change in kinetic energy is

\Delta K = K_2 - K_1 = 1231.6-591.8=639.8 J

Learn more about circular motion:

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a 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. what force was necessary for this change in velocity?

Answers

Answer: 90N

Explanation:

Mass of ball = 0.45 kg

Change in velocity = 20.0 m/s

Time = 0.10 seconds

Force required for change = ?

Since force refers to the change in momentum per unit time, hence

Force = Momentum / Time

i.e Force = Mass x (change in velocity / time)

Force = 0.45kg x (20.0m/s /0.10second)

= 0.45kg x (200 m/s^2)

= 90N

Thus, 90N of force was necessary for this change in velocity
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