Before arc welding was developed, a displacement reaction involving aluminum and iron(III) oxide was commonly used to produce molten iron (the thermite process). This reaction was used, for example, to connect sections of iron railroad track. Calculate the mass of molten iron produced when 2.28 kg of aluminum reacts with 17.2 mol of iron(III) oxide.

Answers

Answer 1
Answer:

Answer: The mass of molten iron formed will be 1.92 kg

Explanation:

We are given:

Moles of iron (III) oxide = 17.2 moles

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ......(1)

Given mass of aluminium = 2.28 kg = 2280 g     (Conversion factor:  1 kg = 1000 g)

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=(2280g)/(27g/mol)=84.44mol

The chemical equation for the reaction of aluminium and iron (III) oxide follows:

2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe

By Stoichiometry of the reaction:

1 mole of iron (III) oxide reacts with 2 moles of aluminium

So, 17.2 moles of iron (III) oxide will react with = (2)/(1)* 17.2=34.4mol of aluminium

As, given amount of aluminium is more than the required amount. So, it is considered as an excess reagent.

Thus, iron (III) oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of iron (III) oxide produces 2 moles of iron

So, 17.2 moles of iron (III) oxide will produce =  (2)/(1)* 17.2=34.4mol of iron

Now, calculating the mass of iron by using equation 1, we get:

Molar mass of iron = 55.8 g/mol

Moles of iron = 34.4 moles

Putting values in equation 1, we get:

34.4mol=\frac{\text{Mass of iron}}{55.8g/mol}\n\n\text{Mass of iron}=(34.4mol* 55.8g/mol)=1919.5g=1.92kg

Hence, the mass of molten iron formed will be 1.92 kg


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A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?

Answers

The concentration of  OH^- ions in the solution is 0.0063 M

What is pH?

pH is a quantitative measure of the acidity or basicity of aqueous or other liquid solutions.

pH or pOH is the measure of acidity or alkalinity of a solution.

pOH is calculated by taking negative logarithm of hydroxide ion concentration.

pH = -log [OH^-]

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Putting in the values:

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Answer:

                 [OH 6.31 × 10⁻³ M

SOlution:

Step 1: Calculate pOH as,

                          pH  +  pOH  =  14

As, pH = 11.8

So,

                          11.8  +  pOH  =  14

Or,

                          pOH  =  14 - 11.8

                         pOH  =  2.2

Step 2: Calculate [OH⁻],

pOH is related to [OH⁻] as,

                          pOH  =  - log [OH⁻]

Putting value of pOH,

                          2.2  =  -log [OH⁻]

Solving for [OH⁻],

                          [OH⁻]  =  10⁻²'²                       ∴ 10  =  Antilog

                          [OH 6.31 × 10⁻³ M

if you are finding the value of a 10 g piece of metal that has a value of 5 dollars/ 1 gram what would be my final unit

Answers

5/1 = 10/x

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Cold packs are used to treat minor injuries. Some cold packs contain NH4NO3(s) and a small packet of water at room temperature before activation. To activate this type of cold pack, the small packet must be broken to mix the water and NH4NO3(s). The temperature of this mixture decreases to approximately 2°C and remains at this temperature for 10 to 15 minutes.State the direction of heat flow that occurs when the activated cold pack is applied to the body.
Identify both types of bonds in the NH4NO3(s).

Answers

These types of reactions are called endothermic reactions. This is when the system absorbs the heat from the surrounding. In this case, the system is the chemical reaction and the environment is the direct vicinity of the chemical reaction. You notice that the pack becomes cold because heat from the surrounding is being absorb. 

The bonds involved in this substance includes ionic bonding and polar covalent. 

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When a mineral cools very quickly, the grain size will be tiny. When a mineral cools very slowly, the grain size will be large.

A 0.8115 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint in the titration. What is the molarity of the NaOH solution?

Answers

Answer:

Molarity of NaOH solution is 1.009 M

Explanation:

Molar mass of HCl is 36.46 g/mol

Number moles = (mass)/(molar mass)

So, 0.8115 g of HCl = (0.8115)/(36.46)moles HCl = 0.02226 moles HCl

1 mol of NaOH neutralizes 1 mol of HCl.

So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is (S* 22.07)/(1000)moles

So, (S* 22.07)/(1000)=0.02226

or, S = 1.009

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