a gas at 155 kPa and 298 K occupies a container with an initial volume of 1.00 L. By changing the volume, the pressure of the gas increases to 605 kPa as the temperature is raised to 398 K. What is the new volume?

Answers

Answer 1
Answer: Given: P1=155kPa P2=605kPa   T1=298K  T2=398K V1=1.00L

Unknown: V2=?

Formula: V2= V1P1T2/P2T1

Solution: V2= 1.00Lx155kPax398K/605kPax298K
               V2= 61,690/180,290=n
Answer: V2= 0.34L is the new volume

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How many grams of CuSO4 are there in 100.0 g of hydrate? How many moles?

Answers

the hydrate form of CuSO4 has 5 water molecules (CuSO4-5H20) copper (II) Sulfate pentahydrate or commonly known as blue vitriol. 

To solve, the following molar masses are to be known. 
CuSO4.5H2O (hydrate)  - 249.7g/mole
CuSO4 (anhydrous) -159.6g/mole
Also there molar ratio of the hydrate and CuSO4 is 1. 

the mass of the hydrate is to be divided by the molar mass of the hydrate then multiplied by the ratio (1) to get the moles of hydrate and multiplied by the molar mass of the anhydrous to get the mass in grams. 

moles = (100g/249.7)*1 =  0.4 moles hydrate
grams = 0.4*159.6 =  64.9 grames hydrate


When K2SO4 is separated into its ions, how is it written?

Answers

Answer: K^+ and SO_4^-^2

Explanation: Potassium is a first group metal with one valence electron and so it has +1 charge. Sulfate ion is a polyatomic ion with -2 charge. The compound potassium sulfate has two potassium ions and one sulfate ion and the below equation shows how the ions are written when the compound is dissociated into its ions.

K_2SO_4\rightarrow 2K^++SO_4^-^2

When K2SO4 is separated into its ions, it is written like this.

K2SO4 -> 2K+ + SO4^-2.

This is a balanced equation.

For an ideal gas, classify the following pairs of properties as directly or inversely proportional.P and T
V and n
T and V
P and V
P and n

Answers

For an ideal gas, the ideal gas equation can be used to relate the changes in the conditions of the system. The equation is expressed as:

PV = nRT

Therefore, the following are classified as:
P and T = directly proportional
V and n = directly proportional
T and V = directly proportional
P and V = inversely proportional
P and n = directly proportional

The following pairs of properties as

  • directly proportional :

P and T

V and n

T and V

P and n

  • inversely proportional :

P and V

Further explanation

Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated), among others

  • Boyle's law at constant T, P = 1 / V
  • Charles's law, at constant P, V = T
  • Avogadro's law, at constant P and T, V = n

So that the three laws can be combined into a single gas equation, the ideal gas equation

In general, the gas equation can be written

\large{\boxed{\bold{PV=nRT}}}

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

Proportional Comparisons / Directly proportional are comparisons of two or more numbers where one number increases, the other numbers also increase at the same rate

Can be formulated  

\displaystyle \frac {x1} {y1} = \frac {x2} {y2}

Inversely proportional is the comparison of two or more numbers where one number increases, the other number decreases in value

Can be formulated  

\displaystyle \frac {x1} {y2} = \frac {x2} {y1}

The following pairs of properties as directly or inversely proportional.(from ideal gas equation)

P and T  : directly proportional

PV=nRT

V and n  : directly proportional

PV=nRT

T and V  : directly proportional

PV=nRT

P and V  : inversely proportional

\displaystyle \bold{P}=\frac{nRT}{\bold{V}}

P and n : directly proportional

PV=nRT

Learn more

Which equation agrees with the ideal gas law

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Which law relates to the ideal gas law

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Keywords : ideal gas law, directly proportional, inversely proportional.

Compared to a 2.0 M aqueous solution of NaCl at 1 atmosphere, a 3.0 M aqueous solution of NaCl at 1 atmosphere has a(1) lower boiling point and a higher freezing point
(2) lower boiling point and a lower freezing point
(3) higher boiling point and a higher freezing point
(4) higher boiling point and a lower freezing point

Answers

The correct answer is option 4. A 3.0 M aqueous solution of NaCl has a higher boiling point and a lower freezing point than a 2.0 M aqueous solution of NaCl where both are at 1 atmosphere. This is explained by the colligative properties of solutions. For the two properties mentioned, the equation for the calculation of the depression and the elevation is expressed as: ΔT = -Km and ΔT = Km, respectively. As we can see, concentration and the change in the property has a direct relationship.

The molar mass of blood sugar, C6H12O6 also known as glucose and dextrose is

Answers

The molar mass is calculated by looking up the relative atomic mass values on a periodic table. The relative atomic mass is a value without units that is calculated on a Carbon-12 scale.

By looking at the periodic table (values will be to 3 significant figures [2 for hydrogen though]):
Molar mass (M) of 1 mole of Carbon = 12.0 g/mol
Molar mass (M) of 1 mole of Hydrogen = 1.0 g/mol
Molar mass (M) of 1 mole of Oxygen = 16.0 g/mol

So the molar mass is essentially the relative atomic mass (RAM), but molar mass has a unit, but RAM doesn't (it is a ratio).

Given the formula is C6H12O6 (without putting the numbers as subscripts), we can calculate as follows:
M (C6H12O6) = (6 x 12.0) + (12 x 1.0) + (6 x 16.0)
                       = 72.0 + 12.0 + 96.0
                       = 180.0 g/mol

Hope it's right :D

Final answer:

The molar mass of glucose, also known as blood sugar and dextrose, is calculated by summing the respective molar masses of carbon, hydrogen, and oxygen in one molecule of glucose. It is approximately 180.16 g/mol.

Explanation:

The molar mass refers to the mass, in grams, of one mole (6.022 x 1023 molecules) of a substance. For glucose (C6H12O6), we calculate it by summing up the molar masses of individual elements, multiplying each by their respective number of atoms in one molecule of glucose.

The molecular masses of carbon (C), hydrogen (H), and oxygen (O) are approximately 12.01 g/mol, 1.008 g/mol, and 16.00 g/mol respectively. So the molar mass of glucose is calculated as follows: (6*12.01 g/mol) + (12*1.008 g/mol) + (6*16.00 g/mol) = 72.06 g/mol + 12.10 g/mol + 96.00 g/mol = 180.16 g/mol.

So, the molar mass of glucose, C6H12O6, also known as blood sugar and dextrose, is approximately 180.16 g/mol.

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Three chromium isotopes are chromium -50, chromium-52, and chromium-53.How many neutrons are in each isotope, given that chromium has an atomic number of 24?

Answers

In  chromium-50 there are 26 neutrons, because 26 + 24 = 50.
In chromium-52 there are 28 neutrons, because 28 + 24 = 52.
In chromium-53 there are 29 neutrons, because 29 + 24 = 53

Remember the atomic number, identifies elements it is different for every element and it is the number of protons in that element. So by adding that to the number of neutrons you can get the mass number.

Final answer:

Chromium-50 has 26 neutrons, chromium-52 has 28 neutrons, and chromium-53 has 29 neutrons.

Explanation:

Chromium has an atomic number of 24, which means it has 24 protons. To determine the number of neutrons in each chromium isotope, subtract the atomic number from the mass number. For chromium-50, subtracting 24 from 50 gives you 26 neutrons. For chromium-52, subtracting 24 from 52 gives you 28 neutrons. And for chromium-53, subtracting 24 from 53 gives you 29 neutrons.

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