(d) You observe someone pulling a block of mass 41 kg across a low-friction surface. While they pull a distance of 4 m in the direction of motion, the speed of the block changes from 5 m/s to 7 m/s. Calculate the magnitude of the force exerted by the person on the block.

Answers

Answer 1

Answer:

Answer:

The magnitude of the force is 124.23 N.

Explanation:

To known the magnitude of the force is necessary to find the acceleration, that can be done by means of the equations for a a Uniformly Accelerated Motion:

$v_(f) = v_(i) + at$ (1)

Where $v_(f)$ is the final velocity, $v_(i)$ is the initial velocity, a is the acceleration and t is the time.

$a = (v_(f)-v_(i))/(t)$ (2)

$d = v_(i)t + (1)/(2)at^(2)$ (3)

By replacing (2) in equation (3) it is gotten:

$d = v_(i)t + (1)/(2)((v_(f)-v_(i))/(t))t^(2)$

$d = v_(i)t + (1)/(2)(v_(f)-v_(i))t$

$d = v_(i)t + (1)/(2)v_(f)t-(1)/(2)v_(i)t$

Therefore, by subtracting the first and third term ( $v_(i)t-(1)/(2)v_(i)t$ ⇒ $(1)/(2)v_(i)t$ ) it is got:

$d = (1)/(2)v_(f)t + (1)/(2)v_(i)t$

Applying common factor for $(1)/(2)t$ :

$d = (1)/(2)(v_(f) + v_(i))t$ (4)

Equation (4) can be rewritten in terms of t:

$t = (2d)/((v_(f) + v_(i)))$

$t = ((2)(4m))/((7m/s + 5m/s))$

$t = (8m)/(12m/s)$

$t = 0.66s$

By knowing the time is possible to determine the acceleration by means of equation (2):

$a = (7m/s-5m/s)/(0.66s)$

$a = (2m/s)/(0.66s)$

$a = 3.03m/s^(2)$

The magnitude of the force exerted by the person on the block can be determine by means of Newton's second law:

$F = ma$ (5)

$F = (41Kg)(3.03m/s^(2))$

$F = 124.23 Kg.m/s^(2)$

$F = 124.23 N$

Hence, the magnitude of the force is 124.23 N.

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The key idea of the transformation called translation is the gliding or sliding of every point in the plane the same direction. a. True b. False
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Which sentence contains italicized words that are used as an infinitive phrase?a. Kelly went to the grocery store.b. Tom went there for some flour.c. Mark wanted to go, but not today.d. Jane parked her car behind a truck. ?

Heat transfer within a fluid takes place bya. convection currents.
b. radiation.
c. conduction.
d. density.

Answers

Heattransfer within a fluid takes place by convectioncurrents. The correct option is a.

Convection currents are principally responsible for heat transmission within a fluid. Heat is transferred through the fluid's own movement through convection.

Heat causes a fluid's particles to gain energy and lose density, which causes them to rise. Heat energy is carried upward by the heated fluid.

A cycle of circulationresults from the movement of colder fluid from the surroundings into its place in the interim.

Through this mechanism, heat can be moved from hotter to cooler areas of the fluid. Convectioncurrents are frequently seen in fluids like air and liquids, and they're important for both engineering and a variety of natural occurrences.

Thus, the correct option is a.

For more details regarding Convection currents, visit:

brainly.com/question/29763773

#SPJ6

Answer:

the answer is A. convection currents

Explanation:Convection currents transfer heat from one place to another by mass motion of a fluid such as water, air or molten rock. The heat transfer function of convection currents drives the earth’s ocean currents, atmospheric weather and geology. Convection is different from conduction, which is a transfer of heat between substances in direct contact with each other.

hopes this helps yall

What conditions are typcial of the soil the deeper we dig into it?

Answers

When we first dig into soil, it's nice and soft.( Depending on what soil it is; usually topsoil)

But when we go deeper into it, there are rocks and the soil is harder. There is bedrock at the bottom, subsoil in the middle, and topsoil at the top, which is where we walk.

Answers

The swimming pool at perris hill plunge is 50 feet long and 25 feet wide. if the bottom of the pool is slanted so that the water depth is 3 feet at the shallow end and 15 feet at the deep end,the angle of elevation at the bottom of the pool is calculated by Over a 50 foot (surface) length, there is a 12 foot (vertical) drop. tan A = 12/50 = 0.24 A = 13.5 degrees

An oscillating bock-spring system has a mechanical energy of 1.0 J, an amplitude of 0.10 m, and a maximum speed of 1.2 m/s. Find (a) the force constant of the spring, (b) the mass, and (c) the frequency of oscillation.

Answers

Answer:

a) F = 20 N

b) m = 1.39 kg

c) f = 1.909 Hz

Explanation:

Given

E = 1 J

A = 0.1 m

vmax = 1.2 m/s

a) F = ?

b) m = ?

c) f = ?

Solution

a) We apply the equation

E = 0.5*k*A²

then

k = 2*E/A²

k = 2*1 J/(0.1 m)²

k = 200 N/m

then we use the equation

F = kA

F = (200 N/m)(0.1 m)

F = 20 N

b) We use the formula

E = K + U

if U = 0 J

then

E = K = 0.5*m*v²

⇒ m = 2*K/v²

m = 2*1 J/(1.2 m/s)²

m = 1.39 kg

c) we apply the equation

f = (1/2π)√(k/m)

then

f = (1/2π)√(200 N/m/1.39 kg)

f = 1.909 Hz

Answer:

a) $k = 200.016\,(N)/(m)$ , b) $m = 1.389\,kg$ , c) $f = 0.524\,hz$

Explanation:

a) The maximum speed of the oscillating block-spring system is:

$v_(max) = \omega \cdot A$

The angular frequency is:

$\omega = (v_(max))/(A)$

$\omega = (1.2\,(m)/(s) )/(0.1\,m)$

$\omega = 12\,(rad)/(s)$

The mass of the system is:

$E = (1)/(2)\cdot m\cdot v_(max)^(2)$

$m = (2\cdot E)/(v_(max)^(2))$

$m = (2\cdot (1\,J))/((1.2\,(m)/(s) )^(2))$

$m = 1.389\,kg$

The spring constant is:

$\omega = \sqrt{(k)/(m) }$

$k = \omega^(2)\cdot m$

$k = (12\,(rad)/(s) )^(2)\cdot (1.389\,kg)$

$k = 200.016\,(N)/(m)$

b) The mass is:

$m = 1.389\,kg$

c) The frequency of oscillation is:

$\omega = 2\pi\cdot f$

$f = (2\pi)/(\omega)$

$f = (2\pi)/(12\,(rad)/(s) )$

$f = 0.524\,hz$

Which statement describes a characteristiccommon to all electromagnetic waves and
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(1) Both types of waves travel at the same speed.
(2) Both types of waves require a material medium
for propagation.
(3) Both types of waves propagate in a vacuum.
(4) Both types of waves transfer energy.

Answers

"(4) Both types of waves transfer energy." is the best option from the list regarding the characteristics common to all electromagnetic waves and mechanical waves

Answer: The correct answer is (4).

Explanation:

Electromagnetic wave is the transverse wave. It is produced by the moving charged particle. It travels at the speed of the light. It does not require a medium to travel. It can travel through the vacuum.

In mechanical wave, there is an oscillation of matter. It requires a medium to travel.It cannot travel through vacuum. The three types of mechanical waves are longitudinal wave, transverse wave and surface wave.

The common characteristics to all electromagnetic waves and mechanical waves are both can move through matter and both can occur as a result of a disturbance. This disturbance is a result of wave transfer energy.

Therefore, the common characteristic to all electromagnetic and mechanical waves is both types of waves transfer energy.

Why dog pants during summer use the cocept of evaporation

Answers

Every "warm-blooded" living thing needs a way to make heat and keep it
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Moving around (using muscles) makes heat inside, and the animal needs
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Evaporation is a very effective way to get rid of heat.

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They do it through their mouth. They put water in their mouth if it's available,
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