PHYSICS HIGH SCHOOL

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary, the tension in the cable was 7000 N {\rm N}. When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N {\rm N} drag force.Part AWhat was the tension in the cable when the craft was being lowered to the seafloor?Express your answer to two significant figures and include the appropriate units.Part BWhat was the tension in the cable when the craft was being raised from the seafloor?Express your answer to two significant figures and include the appropriate units.

Answers

Answer 1
Answer:

Answer:

Explanation:

When the craft was stationary , weight will be balanced by tension

T = mg

T = 7000 N

A)

when the craft was being lowered to the seafloor

drag force will act in upper direction , so

T₁ + 1800 = mg

T₁  = mg - 1800

= 7000 - 1800

= 5200 N

52 X 10² N

B)

when the craft was being raised from the seafloor , Tension will act in downward direction

T₂ = mg+ 1800

T₂  = 7000 - 1800

= 8800N

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Answers

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What is force?

Force acting on a system can be described as the effect that can change the state of the body of motion or rest. The SI measurement unit of force is Newton (N) and force can be described as a vector quantity. Force can change the direction or the speed of the moving object.

The force can be evaluated from the multiplication of the mass (m) with acceleration (a) of an object. The mathematical second law of motion can be used for force:

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Therefore, the magnitude of the pushing force applied by the boy is equal to 12 N.

Learn more about force, here:

brainly.com/question/13191643

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The correct answer is 12N

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Answers

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