When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electron in an He+ ion falls from ????=4, which energy level must it fall to (????1) for blue light of a similar wavelength to be emitted?

Answers

Answer 1
Answer:

Final answer:

Blue light is emitted when an electron in a He+ ion falls from the energy level n=4 to n=1. This is because the energy difference between these levels is similar to that in a hydrogen atom when blue light is emitted (from n=5 to n=2).

Explanation:

The energy of the emitted photon when an electron transitions between energy levels in an atom is determined by the difference between the energy levels it transitions between. This is described by the formula: E = hν, where E stands for energy, h stands for Planck's constant, and ν stands for frequency. The color of the emitted light, or the wavelength, is determined by the energy of the photon.

For blue light to be emitted when an excited electron falls from n=4 in a He+ ion, it must fall into n=1. This is because the energy gap between the n=4 and n=1 levels in a He+ ion is similar to that between the n=5 and n=2 levels in a hydrogen atom, which results in the emission of blue light.

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Answer 2
Answer:

Final answer:

In a helium ion (He+), an electron would need to fall from n=4 to n=1 to emit a photon of blue light, similar to the photon emitted when an electron in a hydrogen atom falls from n=5 to n=2.

Explanation:

According to the Bohr model of atoms, when an electron falls from a higher to a lower energy level, a photon is emitted. The energy (and therefore color) of the photon corresponds to the energy difference between the two energy levels. In the case of your question, an excited electron in a hydrogen atom falls from n=5 to n=2 and emits a photon of blue light.

If an electron in an excited helium ion (He+) falls from the n=4 level, to emit a photon of similar energy (and thus color), it must fall to a level that yields a similar energy difference. Based on the energy levels of helium and hydrogen, the electron in the He+ ion would need to fall to n=1 to emit a photon of similar energy to the blue light from the hydrogen atom, given that the energy difference in He+ ion is larger than in hydrogen atom for the same quantum numbers due to its greater nuclear charge.

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2)A gas forms, and there is a change of color.
3)A solid forms, and light is emitted.
4)A gas forms, and light is emitted.

Answers

Chemical reactions involve the breaking of bonds and forming new bonds. All chemical reactions involves forming of new substances. For this, stuation, it is evident that a chemical reaction occur because a precipitate formed. Therefore the correct answer is stated in statement 1.
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An outline shows __________ among __________. connections . . . vacation destinations bonds . . . atomic elements associations . . . clauses and phrases relationships . . . main points

Answers

An outline shows relationships among main points. It is very important to have an outline when writing an article or an essay because it helps the writer organize the paragraphs in such a way that the idea is clearly conveyed to the audience. In essence, an outline helps the writer give cohesion when it is time for the actual writing of the article or literary work.

Describe the motions of particles in three common states of matter

Answers

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A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is the partial pressure of gas Y?

Answers

The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y. The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an individual gas in a mixture and n is total moles of the gas mixture. We know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole fraction of gas Y (x) and the total pressure (P) to calculate the partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P = 2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm = 1.6 atm.

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The acid-dissociation constant, Ka, for benzoic acid is 6.5 × 10-5. Which will you use to calculate the base-dissociation constant, Kb, for the conjugate base of benzoic acid?

Answers

Answer:

The base-dissociation constant, Kb,for the conjugate base of benzoic acid is :

K_(b)=1.54* 10^(-10)}

Explanation:

The product of acid dissociation constant and base dissociation constant is equal to the water dissociation constant.The general formula for the reaction is:

K_(w)=K_(a)K_(b)

For the acid dissociation reaction:

HA + H_(2)O\rightleftharpoons H^(+)+A^(-)

The conjugate base for the acid is A-

The acid is HA . and its Ka is given.

The value of Kw is fixed  at a given  temperature , which is equal to:

K_(w)=10^(-14)

K_(a)=6.5* 10^(-5)

K_(b)=(10^(-14))/(6.5* 10^(-5))

K_(b)=1.54* 10^(-10)}

Answer:

Ka*kb=kw

Explanation:Got it right