How many atoms are in 45.6 g gold, Au

Answers

Answer 1

Answer: Avogadro's numberrepresents the number of units in one mole of any substance. This has the valueof 6.022 x 10^23 units / mole. This number can be used to convert the number ofatoms or molecules into number of moles.

45.6 g Au ( 1 mol / 196.97 g ) ( 6.022 x 10^23 atoms / mole ) = 1.39x10^23 atoms Au

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A beaker contains 47.0 mL of a 0.47 M HI solution and is titrated with 25.0 mL of a 0.25 M of KOH. What is the final pH, and where is this point in the titration?

Answers

Answer: -

1.8

End point passed.

Explanation: -

Volume of HI solution = 47.0 mL = 0.047 L

Strength of HI solution = 0.47 M

Since HI is a strong acid, all of HI will dissociate to give H +.

[H+ ] =0.47 M x 0.047 L

= 0.02209 mol

Volume of KOH = 25.0 mL = 0.025 L

Strength of KOH = 0.25 M

Since KOH is a strong base, all of KOH will dissociate to give OH-.

[OH-] = 0.25 M x 0.025L

= 0.00625 mol

Since [H+] and [OH-] react to form water,

[H+] unreacted = 0.02209 – 0.00625 = 0.01584 mol

Using the formula

pH = - log [H+]

= - log 0.01584

= 1.8

As the strong acid HI is being titrated by strong base KOH, the pH at the end point should be 7.

The pH has already crossed that. Thus the titration end point has already passed

Final answer:

After titration, there are more moles of HI than KOH, implying excess HI (acid) is present. The remaining acid concentration is 0.2 M and consequently, the final pH of the solution is approximately 0.70.

Explanation:

In the case of the titration of a 47.0 mL of 0.47 M HI solution with 25.0 mL of 0.25 M KOH, we first need to understand that HI is a strong acid and KOH is a strong base. When we titrate a strong acid with a strong base, the equivalence point occurs at a pH of 7.0.

First, we calculate the moles of the acid and the base: moles of HI = 0.47 mol/L * 0.047 L = 0.02209 mol, and moles of KOH = 0.25 mol/L * 0.025 L = 0.00625 mol. Since there are more moles of HI than KOH, we will have extra HI left after the titration. Hence, it is a strong acid-strong base titration before the equivalence point i.e. when we have excess acid.

The remaining acid concentration is (0.02209 mol - 0.00625 mol) / (0.047 L + 0.025 L) = 0.2 M and pH of a strong acid is basically the negative logarithm of the acid's concentration. Therefore, the pH is -log[H+] = -log(0.2) = approx. 0.70.

Learn more about Acid-Base Titration here:

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What is the golden rule of solubility?

Answers

like disolves like is the golden rule

Like dissolves like I believe

Why do plants grow faster without sun?

Answers

Plants rely on photosynthesis to create energy for all of their cellular functions. The more sun the plant takes in, the more energy it is able to produce, thus allowing it to grow faster.

The plant won't be strong though it will be weak and pale trying to find that light and absorb the rays that help build it's chlorophyll to make it strong.

The measurement of moles of solute per kilogram of solvent is known asa. molarity.
b. molality.
c. parts per million.

Answers

Option b: molality

That is the definition of molality.

The standard unit for density is g/cm3 or g/mL.

Answers

it’s g/cm3 for solids & liquids, and g/ml for gases

When a 1.0 M solution of HCl is titrated with a 1.0 M solution of KOH, which is the approximate pH at the equivalent point?

Answers

The equivalence point is when the concentration of H⁺ in solution is equal to the concentration of OH⁻ in solution. Since H⁺ and OH⁻ react with each other to make water (H⁺(aq)+OH⁻(aq)→H₂O(l)) the pH at the equivalence point is 7 due to everything being neutralized. (The equivalence point only has a pH of 7 when a strong acid is being titrated with a strong base).

I hope this helps. Let me know if anything is unclear.

Answer:

Decreases abs basicity decrease

Explanation:

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