Determine the mass of oxygen in a 5.8 g sample of sodium bicarbonate (NaHCO3).
Answers
Answer is: the mass of oxygen is 3.31 grams.
m(NaHCO₃) = 5.8; mass of sodium bicarbonate.
n(NaHCO₃) = m(NaHCO₃) ÷ M(NaHCO₃).
n(NaHCO₃) = 5.8 g ÷ 84 g/mol.
n(NaHCO₃) = 0.07 mol; amount of sodium bicarbonate.
In one molecule of sodium bicarbonate there are three oxygen atoms:
n(NaHCO₃) : n(O) = 1 : 3.
n(O) = 3 · 0.07 mol.
n(O) = 0.21 mol.
m(O) = 0.21 mol · 16 g/mol.
m(O) = 3.31 g.
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C8H18 + 25/2O2 -> 9H2O + 8CO2
You are given 10 moles of octane and you are required to find the volume of octane
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Explanation:
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Answers
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Answer : The mass of iodine extracted can be 9796.7 mg
Explanation : Given,
Mass of thryoxine = 15.0 g
Molar mass of thryoxine = 776.86 g/mole
The molecular formula of thryoxine is,
In compound, there are 15 moles of carbon, 11 moles of hydrogen, 1 mole of nitrogen, 4 moles of oxygen and 4 moles of iodine.
First we have to determine the moles of thryoxine.
Now we have to determine the moles of iodine.
As, 1 mole of thryoxine has 4 moles of iodine
So, 0.0193 mole of thryoxine has moles of iodine
Now we have to determine the mass of iodine.
conversion used : (1 g = 1000 mg)
Therefore, the mass of iodine extracted can be 9796.7 mg
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