A series circuit contains four light bulbs. The switch is opened and one of the bulbs is removed, but not replaced. Then the switch is closed again. What would you expect to see?A) All three remaining light bulbs will be on.
B) None of the remaining light bulbs will be on.
C) Only the bulb closest to the switch will be on.
D) All three remaining light bulbs will be brighter than before.

Answers

Answer 1

Answer:

The correct answer is option B) None of the remaining light bulbs will be on.

What will happen if one light bulb is removed from a series circuit?

In a series connection when a bulb is removed, it will be creating a open circuit. Since the circuit is series and is open at a point current will not flow and hence the other bulb will not glow.

Why did the series circuit stop working when one of the light bulbs was removed?

That's because the basic requirement for the circuit to operate a continuous, closed-loop path is no longer met. This is the main disadvantage of a series circuit. If any one of the light bulbs or loads burns out or is removed, the entire circuit stops operating.

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Answer 2

Answer: for series circuit, components are in the same path. removing component, the path is broken. so without replacing the bulb, current could not flow -- open circuit. all bulbs are dead.

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How does molecules move in Hot and cold air?

Answers

Answer:

In cold air, the molecules mover slower because of the colder tempature, however, in hot air they move faster this is because the molecules are being heated up. Hot = faster, cold = slower

Explanation:

A 55kg female bungee jumper fastens one end of the cord (made of elastic material) to her ankle and the other end to a bridge. Then she jumps off the bridge. As the cord is stretching it exerts an elastic force directed up on her. Calculate her acceleration at the instant the chord exerts an elastic force of 825N [up] on her.

Answers

Downward force = gorce of gravity (her weight) = 55 x 9.8 = 539 newtons / / / Upward force = 825 newton. / / / Net force = 825 - 539 = 286 newtons upward. / / / F = m a / / / a = f / m = 286 / 55 = 5.2 meters per second squared Upward. / / / Note: We don't know the length of her fall before the bungee kicks in. At the moment we're dealing with, when her acceleration is 5.2 m/s-squared Upward, her velocity can very well be Downward.

When the jumper jumps off , there is always a force of gravity acting on her which is 55*9.8 =539N downwards. (Considering the acceleration due to gravity to be 9.8)
Since the question says that the force exerted by cord is 825N upwards , it is obvious that the pseudo force of acceleration must act downwards and the jumper must be moving upwards.
Assume the acceleration at that instant be 'a' .
Pseudo force = mass * acceleration = 55*a
Since the body is in dynamic equilibrium , all forces must cancel out.
Hence ,
539 +55*a = 825
=> 55*a = 825-539 = 286
=> a = 286/55 = 5.2
So , acceleration at that instant was 5.2 m/s²

The atomic mass of an element is A. twice the number of protons in one atom of the element. B. the sum of the protons and neutrons in one atom of the element. C. a weighted average of the masses of an element’s isotopes. D. a ratio based on the mass of a carbon-12 atom.

Answers

b. the sum of the protons and the neutrons in one atom of the element

Answer:

the answer is b

Explanation:

Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they are separated by 12 cm. (Why can you solve this problem without knowing the magnitudes of the charges

Answers

The force between the two point charges is "5 N".

Force and magnitudes:

The total of almost all of the forces operating on an item is referred to as the magnitude of force. When some of the forces operate in the same direction, this same magnitude rises. Whenever forces occur in opposite directions around an item, the amount of something like the force diminishes.

Distance between charges, d = 6 cm

Attractive force, F = 20 N

Separated, d' = 12 cm

We know the formula,

F = $k (q_1q_2)/(d^2)$

or,

F $\propto (1)/(d^2)$ ...(Equation 1)

New force will be:

F' $\propto (1)/(d'^2)$ ...(Equation 2)

From "Equation 1" and "Equation 2", we get

→ $(F)/(F') =(d'^2)/(d^2)$

By substituting the values,

$(20)/(F') =(12^2)/(6^2)$

$(20)/(F') =(144)/(36)$

F' = 5 N

Thus the approach above is appropriate.

Find out more information about force here:

brainly.com/question/388851

Answer:

The force between them when they are separated by 12 cm is 5 N.

Explanation:

Distance between two point charges, d = 6 cm

The attractive force between them is 20 N, F = 20 N

Let F' is the force between them when they are separated by 12 cm, d' = 12 cm

The force between point charges is given by the formula as :

$F=k(q_1q_2)/(d^2)$

$F\propto (1)/(d^2)$ ........(1)

New force,

$F'\propto (1)/(d'^2)$ ............(2)

From (1) and (2) :

$(F)/(F')=(d'^2)/(d^2)\n\n(20)/(F')=(12^2)/(6^2)\n\nF'=5\ N$

So, the force between them when they are separated by 12 cm is 5 N. Hence, this is the required solution.

Firearms are typically found in which way

Answers

Gunshots Are Found By Fingerprints Or Gunshot Residue Hope It Helps☺️

A force of 2.0 n exerted on an object for 0.1 seconds increases the objects velocity by 1.0 m/s you what is the mass of the object?

Answers

Answer:

The mass of the object is 0.2 kg

Explanation:

The magnitude of the applied force = 2.0 N

The duration of application of the force = 0.1 second

The increase in velocity given to the body by the force = 1.0 m/s

From the equation of motion under acceleration, we have;

v = u + a·t

Therefore;

a = (v - u)/t

Where;

v = The final velocity

u = The initial velocity

t = The time taken for the change in velocity = 0.1 s

Given that the change in velocity = 1 m/s, we have;

v - u = 1 m/s

∴ a = (v - u)/t = 1 m/s/(0.1 s) = 10 m/s²

The acceleration, a = 10 m/s²

The equation for the applied force, F is F = Mass, m × Acceleration, a

Therefore, when the applied force, F = 2.0 N, and the acceleration, a is a = 10 m/s², we have;

F = Mass, m × Acceleration, a

2.0 N = Mass of the object × 10 m/s²

∴ Mass of the object = 2.0 N/10 m/s² = 0.2 kg

The mass of the object = 0.2 kg.

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