PHYSICS MIDDLE SCHOOL

A spring (k = 20 N/m) sits on a frictionless surface. The spring is compressed 20 cm and a 2 kg mass is placed before the spring and released from rest. How much time passes between the time that the mass is at the point x = 0 m and x = 2.0 m? A.) 4.34s B.) 1.42s C.) 2.48s D.)0.23s E.)none of the above

Answers

Answer 1

Answer:

Answer:

E.)none of the above

Explanation:

Elastic energy = kinetic energy

½ kx² = ½ mv²

v = x √(k / m)

v = 0.2 m √(20 N/m / 2 kg)

v = 0.632 m/s

Time to travel 2.0 m:

t = (2.0 m) / (0.632 m/s)

t = 3.16 s

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sla’s change in velocity is 30 m/s, and Hazel has the same change in velocity. Which best explains why they would have different accelerations?

Answers

Because acceleration depends not only on the change in velocity.
It also depends on the time during which the change occurs.
The formula is

Acceleration = (change in velocity) divided by (time for the change) .

Maybe Sla changed his velocity in 3 seconds, but Hazel
took all morning to change hers. In that case, even though
the amounts of change were equal, the times were different,
so the quotients of (change/time) were different.

Describe one behavior that shows that light is a wave

Answers

All waves are known to undergo reflection or the bouncing off of an obstacle. Most people are very accustomed to the fact that light waves also undergo reflection. The reflection of light waves off of a mirrored surface results in the formation of an image.

when you look directly at a light and start to turn your eyes you can see the waves comming out

Mrs. Patil travels from her home to work in 0.25 hours. The direct distance between her home and work is 8.0 miles. If Mrs. Patil travels 12.4 miles from home to her job, what is her average velocity during the trip?

Answers

Regardless of the path taken, at the end of the trip Mrs. Patil will be 8.0 miles away from home. If the path taken involves a trip lasts 0.25 hours, then the average velocity over the trip is

$\frac{8.0\,\mathrm{mi}}{0.25\,\mathrm h}=32\,\frac{\mathrm{mi}}{\mathrm h}$

The orientation of which of the following does not influence the phases of the moon?a.
Earth

c.
Sun

b.
the moon

d.
Stars

Answers

So we want to know what is not influencing the phases of the Moon. What influences Moon phases are celestial bodies that are close enough to have enough gravitational force to have an influence. Those celestial bodies would be the Earth and the Sun, since moon itself cant influence itself and all other stars are too far to exert gravitational force. So the correct answer would be the Moon and the stars do NOT have an influence on the Moon phases.

Answer:

So the correct answer would be the stars do NOT have an influence on the Moon phases.

Instead of rolling down the ramp over the step, imagine the ball falls off the back of the ramp directly to the ground. What is the amount of potential energy remaining after the ball lands on the ground?

Answers

According to the law of conservation of energy, the potential energy is converted to kinetic energy. Remember, potential energy is calculated using height and weight. If the ball is on the ground, height is 0.

Assuming the ground has 0 height, than there would be no potential energy.

What is the unit for electric charge?
Kilogram
Newton
Electron
Coulomb

Answers

Answer:coulomb

Explanation:

The unit of electric charge is coulomb

Answer:

Coulomb.

Explanation:

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