It is possible for the mass of the reactants to be greater than the mass of the products during _________.a. phase changes
b. fusion reactions
c. fission reactions
d. physical reactions E. chemical reactions

Answers

Answer 1

Answer: The correct answer is B. It is possible for the mass of the reactants to be greater than the mass of the products during fusion reactions. The mass of the products is less than the mass of the reactants because some of the mass has been converted to energy. Fusion reaction happens when two or more nuclei combine or collide to form an element with a higher atomic number. In this process, some of the matter of the fusing nuclei is converted to energy.

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The most common form of matter in the universe is _____.

Answers

The most common form of matter in the universe is plasma. A plasma is a hot ionized gas consisting of approximately equal numbers of positively charged ions and negatively charged electrons.

The most common form of matter in the universe is _____.

plasma

An energy value of 3.313 × 10^{-19} joules is needed to break a chemical bond. What is the wavelength of energy needed to break the bond? (The speed of light = 3.00 × 10¹⁰ cm/sec; Planck’s constant = 6.626 × 10^{–34} J ⋅sec).A. 5.00 × 10¹⁸ cm
B. 1.00 × 10¹⁵ cm
C. 2.00 × 10⁵ cm
D. 6.00 × 10^{–5}cm
E. 1.20 × 10^{–8} cm
Can someone explain me how to make this one step by step?

Answers

You need two formulas. You need E = hf and v = wavelength x frequency. Plug in the values for the first formula. f = 3.3 x 10^-19/6.63 x 10^-34 and you get f = 0.5 x 10^15. Now plug in this number to the second equation. Wavelength = 3.00 x 10^10 cm/sex/0.5 x 10^15 and you get D) 6.00 x 10^-5 cm.

.During the combustion of methane (CH4), one mole of methane gas combines with two moles of oxygen gas (O2) to produce one mole of carbon dioxide gas (CO2) and two moles of water vapor. Which of the following chemical equations correctly represents the combustion of methane described above?

Answers

Answer:

22.4 L methane reacts with 44.8L of oxygen to give 44.8L of CO

2 and 22.4 L of water

Explanation:

From the balanced reaction: One mole(or 1 molecule or 16 g) of CH

reacts with 2 moles (or 2 molecules or 64 g) of oxygen to give one mole (or 1 molecule or 44 g) of CO

and 2 mole (or 2 molecules or 36 g) of water.

For the gaseous system at STP:

22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO

and 44.8 L of water.

and 2 mole (or 2 molecules or 36 g) of water.

For the gaseous system at STP:

22.4 L methane reacts with 44.8 L of oxygen to give 22.4 L of CO

and 44.8 L of water.

What evidence caused Thomson to change Dalton's solid sphere model into the plum pudding model?

Answers

He found that the cathode ray elements have even negligible mass as compared to atoms. So he found that electrons are actually subatomic particles of an atom. That is why he suggested the plum pudding model.
Explanation:
He discerned that atoms contain charged particles, that he was known as electrons.
In chemist theoryThe indivisibility of associate, degree atom was proved wrong: associate degree atom is often any divided into protons, neutrons and electrons. but associate degree atom is that the smallest particle that takes part in chemical reactions. in step with a chemist, the atoms of the same part are similar all told respects.

The amount of heat energy required to raise the temperature of a unit mass of a material one degree isA. absolute zero.
B. a Joule.
C. its heat capacity.
D. a Btu.

Answers

i think its B- A Joule

If 2.0 moles of a substance are dissolved in 2.0 liters of solution, then the molarity of this solution is:0.5 M

1.0 M

1.5 M

2.0 M

Answers

There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. The concentration of the solution is calculated as follows:

Molarity = 2.0 moles / 2.0 L

Molarity = 1.0 M

Answer:

1.0 M

Explanation:

Hello,

Molarity is a unit of concentration accounting for the amount of the moles of a solute per liter of solution as shown below:

$M=(n_(solute))/(V_(solution))$