I need help !!!!! Show the work plz!!!!
I need help !!!!! Show the work plz!!!! - 1

Answers

Answer 1
Answer:

Answer:

26) 2 meters a second

27) 2 meters a second

28) 5 meters a second

29) 8 km

Explanation:

1/.5 =2

8/4=2

50/10=5

8km×1= 8


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Magali exerts a force of 4.5N to slide her blackberry across the table.If she does 2.7J of work in the process,how far has the blackberry moved?

Answers

divide 4.5 by 2.7 if you revers ops

Suppose you see two stars that have the same apparent magnitude if one star is actually four times as far away as the other how much brighter would be the farther star really be?

Answers

1/4 brighter hope this helps

A car traveling with constant speed travels 150 km in 7200 s. What is the speed of the car?Express the speed to two significant figures and include the appropriate units.

Answers

The speed of the car is 75 km/h

Further explanation

These are the formulas that we have to remember before solving the problem.

Speed is the rate of change of distance.

\large { \boxed {v = (d)/(t)}}

v = speed ( m/s )

d = distance ( m )

t = time ( s )

Acceleration is the rate of change of velocity.

\large { \boxed {a = (\Delta v)/(t)}}

a = acceleration ( m/s² )

Δv = change in speed ( m/s )

t = time ( s )

Let us now tackle the problem!

Given:

distance = d = 150 km

time taken = t = 7200 s = 2 hours

Unknown:

velocity = v = ?

Solution:

v = (d)/(t)

v = (150)/(2)

\large {\boxed {v = 75~km/h} }

The acceleration of the car is 0 m/s² because it travels with constant speed.

We could also plot the distance vs time graph as shown in the attachment.

Learn more

Answer details

Grade: Middle School

Subject: Physics

Chapter: Kinematics

Keywords: indycar top speed of a fastest police car has ever gone

Final answer:

The car's speed is 75 km/hour, as determined by dividing the total distance travelled (150 km) by the total time taken (2 hours).

Explanation:

To answer this question, we use the

formula for speed

, which is distance traveled divided by the time taken. Here, the distance travelled by the car is 150 km and the time taken is 7200 s (which is equal to 2 hours). Therefore, the speed will be 150 km divided by 2 hours, resulting in a speed of

75 km/hour

, stated to the correct number of significant figures.

Learn more about Speed Calculation here:

brainly.com/question/35969362

#SPJ6

The amount of work done on an object is found by multiplying what and what

Answers


           (the distance the object moves)
times
           (the force in the direction of motion that made it move) .

Why is the work output always less than the work input?

Answers

because energy is wasted either in the form of heat energy or something else (like friction)

1. The force between a pair of charges is 100 newtons. The distance between the charges is 0.01 meter. If one of the charges is 2 u 10-10 C, what is the strength of the other charge?2. The force between two charges is 2 newtons. The distance between the charges is 2 u 10-4 m. If one of the charges is 3 u 10-6 C, what is the strength of the other charge?

Answers

Answer:

1. Q = 5.56 * 10^(-3) C

2.Q = 2.97 * 10^(-12) C

Explanation:

1. Electrostatic force is given as:

F = (kqQ)/(r^2)

where k = Coulombs constant

q = charge of first charge

Q = charge of the second charge

r = distance between them

From the question:

F = 100 N

q  = 2 * 10^(-10) C

r = 0.01 m

We need to find Q.

From the formula of force, we have that Q is:

Q = (Fr^2)/(kq)

Q = (100 * 0.01^2)/(8.99 * 10^9 *2 * 10^(-10)) \n\n\nQ = (0.01)/(1.798)\n \n\nQ = 0.00556 C = 5.56 * 10^(-3) C

This is the charge, Q, of the second charge.

2. From the question:

F = 2 N

q  = 3 * 10^(-6) C

r = 2 *10^(-4) m

We need to find Q.

Using the same formula for Q as in 1. above, we have that:

Q = (2 * (2 *10^(-4))^2)/(8.99 * 10^9 *3 * 10^(-6)) \n\n\nQ = (8 * 10^(-8))/(26970)\n \n\nQ = 2.97 * 10^(-12) C

This is the charge, Q, of the second charge.

Answer:

(1)  4.4835*10^(17)C

(2)2.9748*10^(-12)C

Explanation:

Force Between two charges is give by.

F=k(Q_1 *Q_2)/(r^2) , here k is called coulomb constant and has value = 8.967*10^9Nm^2/C.

(1) case, F =100N, r = 0.1m and Q_1=2*10^(-10)C substituting these values in above equation and solving for unknown gives us.

Q_2 = 4.4835*10^(17)C.

(2) Case, F = 2N, r = 2*10^(-4)m and Q_1=3*10^(-6)C.

again by substituting these in above equation and solving for unknown gives us.

Q_2=2.9748*10^(-12)C.