There are two alloys, one is 1 part silver and 5 parts copper and the other 3 parts silver and 1 part copper are mixed to form 350 pounds of an alloy that is equal in silver and copper content.How many pounds of each should be used?

Answers

Answer 1

Answer: Lets make x equal the number times you use the 1/5 ratio alloy and y equal the number of times you use the 3/1 ratio alloy. You can make the equation (x+3y)-(5x+y)=0 and (x+3y)+(5x+y)=350
Then you can make the system of equation of:
-4x+2y=0 (this is y=2x)
6x+4y=350
You can make 6x+8x=350 by through substitution and solve of x.
14x=350
x=25 (which means y=50)

that means that the weight of the 1/5 ratio alloy is 150 pounds.
(25+(5x25))=150
the weight of the 3/1 ratio alloy is 200 pounds.
((50x3)+50)=200

I hope this helps.

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A student determines that according to the reaction N2(g) + 3H2(g) --> 2NH3(g), if 34g of nitrogen gas is reacted with excess hydrogen, 41g of ammonia can be produced. When the actual reaction was complete, only 38g of ammonia formed. Determine the percent yield for the reaction.

Answers

Answer:

The percent yield of this reaction is 92.7 %

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 34.0 grams

Mass of ammonia (NH3 produced = 41.0 grams

Molar mass of N2 = 28.0 g/mol

Molar mass of NH3 = 17.02 g/mol

Actual yield of ammonia = 38 grams

Step 2: The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 34.0 grams / 28.0 g/mol

Moles N2 = 1.214 moles

Step 4: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 1.214 moles N2 we'll have 2* 1.214 = 2.428 moles NH3

Step 5: Calculate mass NH3

Mass NH3 = moles * molar mass

Mass NH3 = 2.428 moles * 17.02 g/mol

Mass NH3 = 41 grams

Step 6: Calculate percent yield for the reaction

Percent yield = (actuald yield / theoretical yield) * 100 %

Percent yield = (38 grams / 41 grams ) * 100 %

Percent yield = 92.7 %

The percent yield of this reaction is 92.7 %

Answer:

$Y=92\%$

Explanation:

Hello,

In this case, by considering the given chemical reaction, with given mass of nitrogen, one could compute the theoretical yield of ammonia as shown below and considering their 1 to 2 molar relationship in the chemical reaction:

$m_(NH_3)^(theoretical)=34gN_2*(1molN_2)/(28gN_2)*(2molNH_3)/(1molN_2)*(17gNH_3)/(1molNH_3) \nm_(NH_3)^(theoretical)=41.3gNH_3$

In such a way, the percent yield is obtained as shown below:

$Y=(m_(NH_3)^(actual))/(m_(NH_3)^(theoretical)) *100\%=(38g)/(41.3g) *100\%\n\nY=92.0\%$

Best regards.

Which of these would be easily soluble in water?a. salt
b. oil
c. aluminum foil

Answers

A) Salt, because salt can easily dissolve in water. Oil would not dissolve or evaporate in water (think of an oil spill - does that oil dissappear?). Aluminum foil would definitely not dissolve in water, so it is not soluble.

Answer:

salt

Explanation:

because is logic sense lol

The reaction between an organic acid and an alcohol produces(1) an aldehyde (3) an ether
(2) a ketone (4) an ester

Answers

Answer : The correct option is, (4) an ester.

Explanation :

As we know that an organic acid is an organic compound that has the properties of an acid. For example : Acetic acid.

And the alcohol is an organic compound that contains one or more hydroxyl groups attached to a carbon atom. Fro example : Ethanol.

When an organic acid react with an alcohol the it produces an ester.

For example : when an organic acid (acetic acid) react with an alcohol (ethanol) to gives an ester (methoxyethane).

The balanced chemical reaction will be,

$CH_3COOH+CH_3OH\rightarrow CH_3C-O-O-CH_3+H_2O$

Hence, the reaction between an organic acid and an alcohol produces an ester.

The reaction between an organic acid and an alcohol produces an Ether.

State the characteristics of transition metals

Answers

Answer:

Conductivity, Malleability, High Melting Point, Luster

Explanation:

Transition metals have the following properties:

Conductivity (Electrical and Thermal)

Malleability (You can hit it with a hammer to mold it)

High melting point

Luster (Shininess)

An example of a decomposer is a:

rabbit
mushroom
tulip

Answers

Answer:

mushroom

Explanation:

Several substances are labeled on the pH scale below.A p H scale is shown ranging from 0 the top to 14 at the bottom. The approximate locations of substances are: gastric fluid, 1.2; lemon juice, 2.2; milk, 6.5; blood, 7.5; seawater, 8; milk of magnesia, upper M g (upper O upper H) subscript 2 solution, 10.5; household lye, upper N a upper O upper H solution, 13.5.

Which substance has the lowest [H+] concentration but is still considered an acid?

Answers

Answer:

(A) - Milk

Explanation:

Acids cannot go below the 7 mark, and milk is the last one right before 7

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