MATHEMATICS HIGH SCHOOL

The length, 18 meters, is the answer to the following question."The length of a rectangle is three meters longer than its width. The area of the rectangle is 270 square meters. What is the length of the rectangle?"
Rework this problem: Write an equation using ???? as the length (in meters) of the rectangle that would lead to the solution of the problem. Check that the answer above is correct by substituting 18 for ???? in your equation.

Answers

Answer 1

Answer:

Answer:

L = B + 3 ..................(1)

L × B = 270 m² .................(2)

on solving we get

L = 18 m, B = 15 m

Step-by-step explanation:

Let the length of the rectangle be L

and,

Width of the rectangle be 'B'

thus,

according to the question

L = B + 3 ..................(1)

And, area of the rectangle = 270 m²

also,

Area of the rectangle = L × B = 270 m² ...........(2)

on substituting 'L' from equation 1 in equation 2, we get

( B + 3 ) × B = 270

B² + 3B - 270 = 0

B² + 18B - 15B - 270 = 0

B( B + 18 ) - 15(B + 18) = 0

( B - 15 ) × ( B + 18 ) = 0

thus, we get

B = 15 m (accepted ) and B = -18 m (neglected : since the length cannot be negative)

therefore,

From 1, we get

L = 15 + 3 = 18 m

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Need answer ASAP will give brainliest check out the picture the answrs: 2, 65, 69, 60, 120, 89, and 30

Answers

I think it is 120

The total of the shape is 180 so it telling us to take away 1/3 of it so 60 away from 180 is 120

Explain how to find 40x50 using mental math

Answers

Bscically DO 4x5 which is 20
NEXT add the two zeros
NOW you have 2,000
40x50=2,000

First, do 4*5=20

Then, add two zeros...

So the answer is 2000

What is 12.7 12 3/5 and 12 3/4 from ordered from least to greatest

Answers

12 3/5 = 12.612.712 3/4 = 12.75Thus, 12 3/5, 12.7, 12 3/4

Find the equation of the line that passes through the point (7,5) and is perpendicular to the line 2x - 3y=6

Answers

$(7,5);\ \ \ \ 2x - 3y=6 \ \ / subtract \ 2x \ from \ each \ side \n \n-3y = -2x + 6\ \ / divide \ each \term \ by \ (-3) \n \n y = \frac{2} {3}x -2\n \n The \ slope \ is :m _(1) = ( 2)/(3) \n \n If \ m_(1) \ and \ m _(2) \ are \ the \ gradients \ of \ two \ perpendicular \n \n lines \ we \ have \n\n\ m _(1)*m _(2) = -1$

$(2)/(3)\cdot m_(2)=-1\ \ / \cdot ((3)/(2))\n\nm_(2)=-(3)/(2)\n\nNow \ your \ equation \ of \ line \ passing \ through \ (7,5) would \ be: \n \n y=m_(2)x+b \n \n5=-(3)/(2)\cdot 7 + b \n \n 5= -(21)/(2)+b\n \nb=5+(21)/(2) \n \nb= (10)/(2)+(21)/(2)\n \nb= (31)/(2)\n\nb=15.5 \n \n y = -(3)/(2)x +15.5$

Question number 4 please help

Answers

$(x^2+x-30)/(x^2-3x+2)\n\nx^2-3x+2=0\n\nx^2-x-2x+2=0\n\nx(x-1)-2(x-1)=0\n\n(x-1)(x-2)=0\iff x-1=0\ \vee\ x-2=0\n\nx=1\ \vee\ x=2\n\nAnswer:For\ x=1\ or\ x=2.$