PHYSICS HIGH SCHOOL

A construction worker pushes a wheelbarrow 5.0 m with a horizontal force of 50.0 N. How much work is done by the worker on the wheelbarrow

Answers

Answer 1
Answer:

The work done will be "250 J".

According to the question,

  • Force, F = 50 N
  • Distance, d = 5 m

The work done is:

→ Work \ done = Force* Distance

or,

→                W = F* D

By substituting the values, we get

                      = 50* 5

                      = 250 \ J

Thus the above response is correct.  

Learn more about work done here:

brainly.com/question/21386378
Answer 2
Answer: Work Done = force • distance
Work Done = 5m • 50N
Work Done = 250J

Answer: 250 Joules

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  • According to the plate tectonics theory, the plates making the earth float on the partially molten mantle, moving away from the mid ocean ridges at varying speeds. At a point where the plates pull apart, slide or collide, a tectonic activity will be manifested as earthquakes.
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I think the answer is plate tectonics theory because when the are moving, they sometimes hit each other and it makes earthquakes and volcanic eruptions

But i'm not sure

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Answers

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Answers

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Answers

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