MATHEMATICS MIDDLE SCHOOL

The relationship between the number of 12$ DVDs you by and the total cost

Answers

Answer 1

Answer:

Answer:

C = 12n

Step-by-step explanation:

Let C = the total cost

and n = the number of DVDs

Then

C = 12n

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Pleasr help me
5u + 3v + 6u - v = ?

Answers

$5u+3v+6u-v=(5u+6u)+(3v-v)=11u+2v$

Give an example of a real-world situation that could be represented by an algebraic expression

Answers

Gas is $2.53⁹ per gallon today, at that filling station
down the street from my house.
I have $10 in my pocket.

a). How much gas can I put in the car if I go there ?

b). My car gets 25 miles per gallon. How many 'miles' will my $10 buy ?

c). In Calgary (Alberta, Canada) today, gas is selling for
89¢ (Canadian) per liter. What is the percentage more or less,
compared to the price of gas down the street from my house ?

If I posted this problem on Brainly, I'd probably give it
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and 10 or 15 for part-c because in addition to math,
that part takes some research.

Which of the following statements about cartography and the creation of maps is false?A.
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B.
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Answers

Answer:

Step-by-step explanation:

What are these fractions in simplest form? ( when I do a / it means a "fraction bar" or " over" like 16/30 or 16 over 30, just incase any of you get confused) but if you could help me simplify these that would be great!!

16y3/20y4 (that's a y to the third power for sixteen and a y to the fourth power for twenty)

6xy/16y

Abc/10abc

Mn2/pm5n (that's an n to the second power for nm and a m to the fifth power on pmn)

12h3k/16h2k2 ( that's a h to the third power for 12hk and a h to the second power and k to the second power for 16hk

8x/10y

24n2/28n ( that's a n to the second power)

30hxy/54kxy

5jh/15jh3 (that's a h to the third power for 15jh)

20s2t3/16st5 ( that's a a to the second power and t to the third power for 20st and t to the fifth power for 16st)

Answers

$(16y^(3))/(20y^(4)) = (4)/(5y)$
$(6xy)/(16y) = (3x)/(8)$
$(abc)/(10abc) = (1)/(10)$
$(mn^(2))/(pm^(5)n) = (n)/(pm^(4))$
$(12h^(3)k)/(16h^(2)k^(2)) = (3h)/(4k)$
$(8x)/(10y) = (4x)/(5y)$
$(24n^(2))/(28n) = (6n)/(7)$
$(30hxy)/(54kxy) = (5h)/(9k)$
$(5jh)/(15jh^(3)) = (1)/(3h^(2))$
$(20s^(2)t^(3))/(16st^(5)) = (5s)/(4t^(2))$

The output is four times the input

Answers

o=4i (is that was you were asking about)

edit: sorry that wasn't very detailed say if the input is 4 the output will be 16 or if the input is 100 the output will be 400. So mainly what ever the input is multiply it by 4.

I hope this helps :)

60x-3x to the second power divided by 3x

Answers

one way is to find ones or factors
example 4/2=2/2 times 2/1=1 times 2/1

then we undistribute the factor
we want a factor of 3x to make a one
60x=3x times 20
-3x^2=3x tiimes -x
use undistributive property which is
ab+ac=a(b+c)
so
60x-3x=3x(20)+3x(-x)=3x(20-x)
so now we have
[3x(20-x)]/3x=(3x/3x) times (20-x)/1=1 times 20-x=20-x

answer is 20-x

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