What is the cause of rising surface temperatures of the pacific ocean, drought in the western united states, and flooding on the pacific coast of south america?

Answers

Answer 1
Answer:

The main cause of rising the surface temperature of the pacific ocean drought in the western united states, and flooding on the pacific coast of south america is the phenomenon called El-nino.

What is El-nino ?

Surface temperatures in the equatorial Pacific rise during El Nino, while the east-west trade winds that blow close to the equator diminish. Typically, trade winds from the Americas move eastward towards Asia.

They sputter and alter course because of El Nino, becoming westerlies and carrying warm water from the western Pacific to the Americas.

Deeper seas are typically nutrient-richer, however under El Nino upwelling is limited, which reduces phytoplankton along the coast. Deeper waters typically rise to the surface.

Fish that consume phytoplankton are the first to be impacted, then organisms farther up the food chain. Additionally, tropical animals are transported by warmer water to colder regions, upsetting numerous ecosystems.

To find more on El-Nino, refer here:

brainly.com/question/28301099

#SPJ2

Answer 2
Answer:

What is the cause of rising surface temperatures of the pacific ocean, drought in the western united states, and flooding on the pacific coast of south america?

The cause of rising surface temperatures of the pacific ocean, drought in the western united states, and flooding on the pacific coast of south America is the carbon – producing companies.


Related Questions

Whats the primary reason for the rapid growth of cancer?
What is the volume of 0.30 M NaOH(aq) neededto completely neutralize 15.0 milliliters of0.80 M HCl(aq)?(1) 3.6 mL (3) 20. mL(2) 5.6 mL (4) 40. mL
What is the mass of an aluminum cylinder that has a volume of 1.50m3
In a reaction progress curve, which point on the curve corresponds to an intermediate of the reaction?
A container is filled with 4.0 g H2 and 5.0 02. How much water is produced

Aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients? Aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal. What is the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients? 3. 1. 4. 2.

Answers

The stoichiometric coefficient for aluminum, Al when the chemical equation is balanced is 2.

To obtain the stoichiometric coefficient for aluminum, we shall write and balance the equation for the reaction. This is illustrated below:

Aluminum => Al

Iron (II) chloride => FeCl₂

Aluminum chloride => AlCl₃

Iron => Fe

Aluminum + Iron (II) chloride —> Aluminum chloride + Iron

Al + FeCl₂ –> AlCl₃ + Fe

There are 3 atoms of Cl on the right side and 2 atoms on the left side. It can be balance by writing 3 before FeCl₂ and 2 before AlCl₃ as shown below:

Al + 3FeCl₂ –> 2AlCl₃ + Fe

There are 2 atoms of Al on the right side and 1 atom on the left. It can be balance by writing 2 before Al as shown below:

2Al + 3FeCl₂ –> 2AlCl₃ + Fe

There are 3 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 3 before Fe as shown below:

2Al + 3FeCl₂ –> 2AlCl₃ + 3Fe

Now, the equation is balanced.

The coefficient of Aluminum, Al in the balanced equation is 2.

Learn more about balancing equation:

brainly.com/question/2399130

Answer:

2.

Explanation:

  • The balanced chemical equation for the reaction of aluminum metal reacts with aqueous iron(II) chloride to form aqueous aluminum chloride and iron metal is:

2Al(s) + 3FeCl₂(aq) → 2AlCl₃(aq) + 3Fe(s).

It is clear that 2 mol of Al react with 3 mol of FeCl₂ to produce 2 mol of AlCl₃ and 3 mol of Fe.

  • So, the the stoichiometric coefficient for aluminum when the chemical equation is balanced is 2.

If a solid, a liquid, and a gas of a substance are each in separate covered jars, then the amount of kinetic energy of the particles of the substances decreases from solid to liquid to gas.True
False

Answers

Answer:

false

Explanation:

i had the same thing to do

Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.

Answers

Answer : The percent yield of CO_2 is, 68.4 %

Solution : Given,

Mass of CH_4 = 0.16 g

Mass of O_2 = 0.84 g

Molar mass of CH_4 = 16 g/mole

Molar mass of O_2 = 32 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of CH_4 and O_2.

\text{ Moles of }CH_4=\frac{\text{ Mass of }CH_4}{\text{ Molar mass of }CH_4}=(0.16g)/(16g/mole)=0.01moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=(0.84g)/(32g/mole)=0.026moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 0.026 moles of O_2 react with (0.026)/(2)=0.013 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO_2

From the reaction, we conclude that

As, 2 mole of O_2 react to give 1 mole of CO_2

So, 0.026 moles of O_2 react to give (0.026)/(2)=0.013 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2* \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(0.013moles)* (44g/mole)=0.572g

Theoretical yield of CO_2 = 0.572 g

Experimental yield of CO_2 = 0.391 g

Now we have to calculate the percent yield of CO_2

\% \text{ yield of }CO_2=\frac{\text{ Experimental yield of }CO_2}{\text{ Theretical yield of }CO_2}* 100

\% \text{ yield of }CO_2=(0.391g)/(0.572g)* 100=68.4\%

Therefore, the percent yield of CO_2 is, 68.4 %

Corn, Cotton, Tobacco, and Wheat are examples of what?Question 3 options:

Plantations


Economies


Colonies


Cash Crops

Answers

Answer: cash crops

Explanation:

trust

Answer: Cash Crops

Explanation: These crops were used in the south to make loads of money before the civil war in southern plantations so they were known as cash crops

Which of the following would most likely happen if water did not form hydrogen bonds?A) Water would exist only as a solid.

B) Water would be able to dissolve all ionic compounds.

C) Water would not expand when it freezes.

D) Water would not exist on Earth.

Answers

The hydrogen bond is a secondary bond formed between a hydrogen (attached to an highly electronegative element ,: F, O or N) and another atom of an highly electronegative element ,: F, O or N.

In case of water hydrogen bond helps water

a) to dissolve certain substances which can make hydrogen bond

b) it makes it liquid and room temperature unlike H2S which is a gas at room temperature due to absence of hydrogen bond

c) higher volume and low density of ice as compared to liquid water. Due to hydrogen bond ice forms open cage like structure which increases its volume and decreases its density. Thus water expands on freezing

So in absence of hydrogen bond Water would not expand when it freezes.

Water would not expand when it freezes. 

Hypobromite is used to purify contaminated water. what is the formula for hypobromite

Answers

Answer: The formula for hypobromite BrO^-.

Explanation:

Hypobromite is also called as alkaline bromine water with molecular formula of BrO^-. It is used as germicide and antiparasitic

It is prepared by reacting bromine gas and alkali at 20 °C .

Br_2+2OH^-\rightarrow Br^-+BrO^-+H_2O

Oxidizing action of hypobromite ions.

OBr^-+2H^++e^-\rightarrow (1)/(2)Br_2+H_2O

The formula for Hypobromite is BrO