A volume of a fixed gas is doubled and the temperature is doubled. What happens to the pressure of the gas?

Answers

Answer 1
Answer: We first assume that this gas is an ideal gas where it follows the ideal gas equation. The said equation is expressed as: PV = nRT. From this equation, we can predict the changes in the pressure, volume and temperature. If the volume and the temperature of this gas is doubled, then the pressure still stays the same.

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Explain why ionic compounds are formed when a metal bonds with a nonmetal but covalent compounds are formed when two nonmetals bond.

Answers

Two nonmetals have enough electrons to share some for completing, so the bonds are covalent. A metal doesn't have that much, so it gives the few electrons on its outer layer more easily than a nonmetal (there must be a nonmetal to get them). This bond is ionic.
I'm still unaware of possible bonds between 2 metals (are there any? :) )

Final answer:

Ionic compounds form when a metal and nonmetal bond, as the metal loses its valence electrons which the nonmetal gains, resulting in an ionic bond. Covalent compounds form when two nonmetals bond, as they tend to share electrons allowing them to complete their valence shells resulting in a covalent bond.

Explanation:

The formation of ionic and covalent compounds depends on the elements involved and their properties. Metals, generally, have few valence (outer shell) electrons, while nonmetals have more. When a metal and nonmetal bond, the metal tends to lose its valence electrons, becoming a positively charged ion or cation, and the nonmetal gains these electrons, becoming a negatively charged ion or anion. This transfer of electrons results in an ionic bond.

On the other hand, when two nonmetals bond, they tend to share electrons because neither atom can completely overcome the other's attraction for electrons. These shared electrons allow them to complete their valence shells. This sharing of electrons results in a covalent bond.

Learn more about Ionic and Covalent Compounds here:

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tert-Butyl alcohol is a solvent with a Kf of 9.10 ∘C/m and a freezing point of 25.5 ∘C. When 0.807 g of an unknown colorless liquid was dissolved in 11.6 g of tert-butyl alcohol, the solution froze at 15.3 ∘C.Which of the following is most likely the identity of this unknown liquid?tert-Butyl alcohol is a solvent with a of 9.10 and a freezing point of 25.5 . When 0.807 of an unknown colorless liquid was dissolved in 11.6 of tert-butyl alcohol, the solution froze at 15.3 .Which of the following is most likely the identity of this unknown liquid?ethylene glycol (molar mass = 62.07 g/mol)1-octanol (molar mass = 130.22 g/mol)glycerol (molar mass = 92.09 g/mol)2-pentanone (molar mass = 86.13 g/mol)1-butanol (molar mass = 74.12 g/mol)

Answers

Answer: ethylene glycol (molar mass = 62.07 g/mol)

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

\Delta T_f=k_f* m

or,

\Delta T_f=k_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}

where,

T_f = change in freezing point

k_f = freezing point constant= 9.10^0C/m

m = molality

Given mass of solute = 0.807 g

Molar mass of solute=? g/mol

weight of solvent in kg= 11.6 g=0.0116 kg

\Delta T_f=T^(o)_f-T_f=25.5^0C-15.3^0C)=10.2^0C

10.2=9.10* \frac{0.807}{\text{molar mass of solute}* 0.0116kg}

{\text{molar mass of solute}}=62.07 g/mol

Thus the solute is ethylene glycol which has same molecular mass as calculated, i.e 62.07 g/mol.

Provide a balanced equation for the reaction between lead nitrate and sodium chloride

Answers

Answer:

Pb(NO3)2 + 2NaCl = PbCl2 + 2NaNO3

Explanation:

Lead nitrate is Pb(NO3)2

Sodium Chloride is NaCl

The basic reaction is:  

Pb(NO3)2 + NaCl = PbCl2 + NaNO3

Now we need to balance the equation.  Note that the lead nitrate contributes 2 (NO3) units, but there is only 1 NO3 on the product side.  So start by adding a second NaNO3:

Pb(NO3)2 + NaCl = PbCl2 + 2NaNO3

Now we have 2 Na atoms on the right side, so add a "2" to the NaCl:

Pb(NO3)2 + 2NaCl = PbCl2 + 2NaNO3

This is starting to look good.  Lets check the atom/unit counts on both sides of the equation:

             Reactants     Products

Pb                 1                  1

NO3              2                 2

Na                 2                 2

Cl                   2                2

The equation is now balanced.  Pb(NO3)2 + 2NaCl = PbCl2 + 2NaNO3

If a catalyst is used in a reaction:a. the energy of activation increases.
b. the reaction rate does not change.
c. the reaction rate increases.
d. the equilibrium shifts.

Answers

the purpose of catalyst is to speed up so it increases the rate of rxn and lower the activation energy

Physical signs of stress typically include ________.a. Stomach growling
b. Tense muscles
c. Tickling sensation
d. All of the above

Answers

This answer was pretty obvious, if you think about it....Your answer is B.

How many electrons can the n=4 shell hold?
a. 8
b.16
c.32
d.64

Answers

Answer:

             32 Electrons

Explanation:

                    In statement the letter "n" specifies the Principle Quantum Number. Principle Quantum number is main energy level of an atom. Hence, n = 4 means we are talking about the fourth energy level or fourth shell of an atom.

                    Also, the number of electrons present in any main energy level are calculated by using following formula,

                                                         2n²

Hence, as,

                 n = 4

So, by putting this value in above formula,

                                                         2 (4)²

                                                         2 (16)

                                                         32

The maximum number of electrons that can be accommodated in the n=4 shell is 32.

(Option C).

How many electrons can the n=4 shell hold?

The maximum number of electrons that can be accommodated in the n=4 shell can be determined using the following formula.

maximum electrons = 2n²

where;

  • n is the orbital level

The given parameters include;

n = 4

The maximum number of electrons that can be accommodated in the n=4 shell is calculated as;

maximum electrons = 2n²

maximum electrons = 2 (4²)

maximum electrons = 32

Learn more about maximum electron in shell here: brainly.com/question/4177923

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