In a transverse wave ,if you increase of the wave you will get what kind of wavelength

Answers

Answer 1
Answer: using the formula v = f λ, 
where v is the velocity of the wave, f is the frequency of the wave and λ is the wavelength of the wave. 

assuming that the velocity of the wave remains constant, by increasing the wavelength the frequency must decrease.

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How do I use the equation E=MC^2 in relation to atoms to find the amount of energy of a reaction?

Answers

-- Find the mass of all the pieces before the reaction.

-- Find the mass of all the pieces after the reaction.

-- Find the difference . . . (mass before) minus (mass after)

-- If any mass is missing, either you lost track of it, or else
it was converted to energy.

How much energy ?

(the missing mass) times c² .

The force of gravity between two objects is directly proportional to which of the following? a. the masses of each object.
b. the velocity of each object.
c. the distance between the objects squared.
d. the mass of one object and the distance between the objects.

Answers

Force of gravity =Gxm1xm2 /r^2G= gravitational constantm1 and m2 are massesr is the distance between masses.So a is the correct option
The force of gravity between two objects is directly proportional to the
product of the two masses, and to the mass of each object individually.

a person runs 27.0km west then turns around and runs 13.0km east what's the distance and displacement ?

Answers

Answer:

See below

Explanation:

Distance = 27 + 13 = 40 km

Displacement = 27 - 13 = 14 km

An electron that has an instantaneous velocity of ???? = 2.0 × 106 m ???? ???? + 3.0 × 106 m ???? ???? is moving through the uniform magnetic field ???? = 0.030T ???? − 0.15T ???? . (a) Find the force on the electron due to the magnetic field (b) Repeat your calculation for a proton having the same velocity.

Answers

Explanation:

It is given that,

Velocity of the electron, v=(2* 10^6i+3* 10^6j)\ m/s

Magnetic field, B=(0.030i-0.15j)\ T

Charge of electron, q_e=-1.6* 10^(-19)\ C

(a) Let F_e is the force on the electron due to the magnetic field. The magnetic force acting on it is given by :

F_e=q_e(v* B)

F_e=1.6* 10^(-19)* [(2* 10^6i+3* 10^6j)* (0.030i-0.15j)]

F_e=-1.6* 10^(-19)* (-390000)(k)

F_e=6.24* 10^(-14)k\ N

(b) The charge of electron, q_p=1.6* 10^(-19)\ C

The force acting on the proton is same as force on electron but in opposite direction i.e (-k). Hence, this is the required solution.

In an engine governor, the two spheres (total mass of 1.0kg) are at 0.05m and rotating at 37rad/s If the engine increases the angular velocity to 58rad/s what is the new location of the spheres?

Answers

Here we can say that there is no external torque on this system

So here we can say that angular momentum is conserved

so here we will have

I_1\omega_1 = I_2\omega_2

now we have

I_1 = mr^2

I_1 = (1kg)(0.05^2)

I_1 = 25* 10^(-4) kg m^2

similarly let the final distance is "r"

so now we have

I_2 = mr^2

I_2 = 1r^2

now from above equation we have

(25* 10^(-4))37 = (r^2)(58)

r = 0.04 m

so final distance is 0.04 m between them

A sound wave travels at 330 m/sec and has a wavelength of 2 meters. Calculate its frequency and period.

Answers

The frequency of the wave with a speed of 330 m/s and 2 meter wavelength is 165 Hz. The time period of the wave is then, 0.006 seconds.

What is frequency ?

Frequency of a wave is the number of wave cycles per second. Frequency of a wave is the inverse of its time period. It is inversely proportional to the wavelength and directly proportional to the speed.

Hence, ν = c/λ, where c is the speed.

The frequency of a sound wave is called its pitch.

Given that, c = 330 m/s

wavelength λ = 2 meters.

frequency = 330/2 = 165 s⁻¹ or 165 Hz.

The time period of a wave  = 1/ frequency.

T = 1/165 = 0.006 s or 6 milliseconds.

Therefore, the frequency of the wave is 165 Hz and time period is 0.006 seconds.

Find more on sound waves:

brainly.com/question/11797560

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frequency=velocity/wavelength 330/2=165 hertz period=1/frequency=1/165 second