The driver of a 1500 kg car, travelling on a highway, hits the brakes. A force of 12000 N stops the car in a distance of 64 m. how fast was the car going when the driver hit the brakes?

Answers

Answer 1
Answer:

Answer:

v = 32 m/s

Explanation:

As per work energy theorem we know that work done by all the forces must be equal to change in kinetic energy of the car

So here when brakes are applied then work is done by the brakes which is equal to change in kinetic energy of the car

so we know that work done by the brakes is given as

W = -12000 * 64

W = -768000 J

now we will have

W = 0 - (1)/(2)mv^2

-768000 = - (1)/(2)(1500) v^2

v = 32 m/s


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A thin rod rotates at a constant angular speed. Consider the tangential speed of each point on the rod for the case when the axis of rotation is perpendicular to the rod at its center and at one end. Explain for each case whether there are any points on the rod that have the same tangential speeds.

Answers

Answer:

    v = R w    

With this expression we see that for each point at different radius the tangential velocity is different

Explanation:

They indicate that the angular velocity is constant, that is

            w = dθ / dt

Where θ is the radius swept angle and t the time taken.

The tangential velocity is linear or

           v = dx / dt

Where x is the distance traveled in time (t)

 

In the definition of radians

          θ = s / R

Where s is the arc traveled and R the radius vector from the pivot point, if the angle is small the arc (s) and the length (x) are almost equal

         θ = x / R

We substitute in the speed equation

         v = d (θ R) / dt

The radius is a constant for each point

         v = R dθ / dt

         v = R w

With this expression we see that for each point at different radius the tangential velocity is different

A truck on a straight road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 20.0 m/s. Then the truck travels for 20.0 s at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional 5.00 s. (a) How long is the truck in motion? (b) What is the average velocity of the truck for the motion described?

Answers

You can use the equation
V_xf = V_xi + a_x(t)

V_xf = 20.0m/s
V_xi = 0m/s
ax = 2.0t

Thus, solve for t and get 10secondsand then take 5 seconds to break after 20 seconds of drivingso for

a) 10 + 20 + 5 = 35 seconds

for part b)
You can use the formula
Delta x/Delta t = average velocity
 
Need to find xf, knowing xi = 0

Thus, use the formula
 x_f = x_i + V_xi(t) + (1/2)a_x(t)^(2)
x_f = 0 + 0(10) + (1/2)(2.0)(10)^(2)
 x_f = 100m
 
so for the first 10 seconds the truck traveled 100msAt a speed of 20m/s

20m/s = xm/20s20*20 = x
x = 400
 
thus we have 100+400 = 500mthen it slows down from 500m to x_f
 
thus I use the equation
x_f = x_i + (1/2)(V_xf + V_xi)t
x_f = 500 + (1/2)(0 + 20)(5)x_f = 500 + 50
x_f = 550
 
therefore the total distance traveled is 550m

to calculate average velocity
550/35 = 16m/s

thusV_xavg = 16m/s

This image shows the direction of the flow of water through a constricted pipe. Which of the following happens as you move from position A to position B in the water pipe? A.The velocity of the water decreases.
B.The pressure of the water decreases.
C.The flow rate of the water decreases.
D.The density of the water increases.

Answers

The flow rate of the water decreases as the cross section is decreases. So, the correct option is C.

What is Bernoulli's equation?

Bernoulli’s principle states that the total mechanical energy of a moving fluid, which includes the gravitational potential energy of height, the energy associated with fluid pressure, and the kinetic energy of fluid motion, remains constant.

The formula for Bernoulli’s principle is given as follows:

p+(1)/(2) pv^2+ pgh= constant

From the equation of continuity for incompressible fluids which is Bernoulli's equation

a v = constant

where, a is the area and v is the velocity.

Pressure is inversely proportional to the velocity.

a_Av_A= a_Bv_B

From the image we can see that area of cross-section at A is greater than at B,

a_A > a_B

thus,

v_A < v_B

which means velocity of water will increase at B and water pressure will decrease.

Hence, the correct option is C, i.e. the flow rate of water decreases.

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C. The flow rate of the water decreases

The Ptolemaic theory of the universe was disproved bya. Descartes.
b. Kepler.
c. Copernicus.
d. Newton.

Answers

The Ptolemaic theory of the universe wasdisproved by Nicolaus Copernicus (1473–1543), letter C and followed by JohannesKepler (1571–1630). Geocentrictheory suggested that the Sun and moon orbited Earth, and the rest of theplanets orbited the Sun is Heliocentric theory. Heliocentric theory of NicolausCopernicus during the Scientific Revolution on 17th and 18thcentury while Geocentric theory was proposed by Ptolemy (AD 150) and Aristotle.Today, we believe more on the Heliocentric theory and it has been proven aswell. 

A 70kg divers steps off of a 10m tower and drops from rest straight into the water. If he comes to rest 5m beneath the surface, determine the average resistance force exerted on him by the water.

Answers

Kinetic Energy:
K E= m g h
h = 10 m,  d = 5 m.
m g ( h + d ) - F d = 0
m g ( h + d ) = F d
70 * 9.8 * 15 = F * 5
10,290 = 5 F
F = 10,290 : 5
F = 2,058 N

First, we need to calculate the total distance that the diver travelled. The diver jumped off a 10-meter tower and went 5 meters under the water. Therefore, the total distance travelled by the diver is 10 meters (from the tower) plus 5 meters (underwater), which equals 15 meters.

Next, we will determine the work done on the diver. The work done is equal to the change in potential energy, which can be calculated by multiplying the diver's mass by gravity and then by the total distance the diver travelled. Given that the diver's mass is 70kg and the acceleration due to gravity is 9.8m/s², the work done is 70kg * 9.8m/s² * 15m, which equals 10290 Joules.

Finally, we'll find the average resistance force exerted on the diver by the water. The work done on the diver is also equal to the average force times the distance. Therefore, the average force is the work done divided by the distance. When you divide the work done (10290 Joules) by the total distance travelled (15 meters), you get an average force of 686 Newtons.

Hence, the total distance travelled by the diver in water is 5 meters, the work done on the diver is 10290 Joules, and the average resistance force exerted on the diver by the water is 2058 Newtons.

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Why do sound waves move faster through the ground than through the air?Particles of matter are packed more loosely in the ground than in the air.

Particles of matter are packed more tightly in the ground than in the air.

Air doesn’t contain any particles of matter to transmit sound waves.

The elevation of the ground is lower than the elevation of the air space.

Answers

Answer:

Particles of matter are packed more tightly in the ground than in the air.

Explanation:

As we know that velocity of sound in a given medium is given by formula

v = \sqrt{(E)/(\rho)}

here we know that

E = elasticity of the medium

\rho = density of the medium

now we know that if we increase the density of medium then particles of matter are packed more which will decrease the speed of wave.

while is particles are tightly packed then it will increase the elasticity of the medium

So here if all particles are tightly bounded with each other then sound waves will move faster through the medium

Particles of matter are packed more tightly in the ground than the air