MATHEMATICS HIGH SCHOOL

Which statement about square root x-5 - square root x = 5 is true?a) x = –3 is a true solution.
b) x = –3 is an extraneous solution.
c) x = 9 is a true solution.
d) x = 9 is an extraneous solution.

Answers

Answer 1
Answer: Hello,

Answer D

√(x-5) - √(x) =5
==>(x-5) -2*√((x-5)x)+x =25
==>2x-30=√(x(x-5))
==>x-15=√(x(x-5))
==>x^2-30x+225=x(x-5)
==>225=-5x+30x
==>25x=225
==>x=9
But:

√(9-5) - √(9)=√(4) - √(9)=2-3=-1≠5

Explanation:

\lim_(x \to \infty) √(x-5)- √(x)

= \lim_(x \to \infty) \frac{(√(x-5)- √(x))*(√(x-5)+ √(x))} {√(x-5)+ √(x)}

= \lim_(x \to \infty) ((-5))/(√(x-5)+ √(x))

= \lim_(x \to \infty) (-5)/(\infty)=0

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THE ANSWER IS

<UTW and <XWY

THANKU

Need help with the question

Answers

Answer:

  a = -21

Step-by-step explanation:

Multiply the equation by the reciprocal of the coefficient of 'a'.

  (-7/6)(-6/7)a = (-7/6)(18)

  a = (-7)(18/6) = (-7)(3)

  a = -21

Answer:

I think the answer is a=-1/21

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Answers

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Answers

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Answers

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