A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and the mass of a the truck is 1,600 kg what's the radius of the curve.

Answers

Answer 1
Answer: The radius of the curve is 81.93 metres. We can work this out byconsidering the centripetal force (Fc) = mass x centripetalacceleration.
Fc = m x u (squared)
R = mu (squared) over Fc = 1600 x (13 squared) over 3300
R = 81.93 metres
Answer 2
Answer:

The Correct answer to this question for Penn Foster Students is: 81.94m


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The kineticmolecular theory of matter states that all particles of matter are in constantbattering motion. It is mostly applied to gaseous particles. This is becausethey have room for movement in that their distance between each particle isgreat. That is why gases has greater volume compared to liquids and solids. Anexample of this is 1 kg of liquid water. It is placed inside the balloon. When heated,you observed that the balloon expands. This is because the particles of liquidwater do not want to be so close with each other. That is why it expands.
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What are the two factors affect the weight of an object?

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Answer:

mass and distance

Explanation:

hope this helped

Is a plasma fluid? explain your answer

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Yes, a plasma is a fluid just like a liquid or a gas, but charged particles within it allow it to react to electromagnetism

The model of the universe that suggests that the sun is the center of the universe was first brought by A. Brahe.
B. Kepler.
C. Ptolemy.
D. Copernicus.
Can also someone add few facts about this suggestion and its author?

Answers

It is D,Copernicus.when he first proposed the idea everyone thought he was nuts and that it was not plausible.even though his theory wasn't so accurate it still helped further scientific research.HE was born February 19,1473 and he published a book about his theory.
The correct answer is D. Copernicus.
Nicolaus Copernicus completed his education in the university of Krakow of Mathematics. He also studied the stars and planets and didn't believe that the earth was the centre of the universe. Copernicus presented his ideas in a book called ON THE REVOLUTION OF CELESTIAL SPHERES. The book wasn't published for 30 years 'cause the Roman Catholic Church opposed it!

Why do you think sound travels faster in steel than it does in wood? (Hint: Think about the densities of the two materials, and how the particles might be arranged.)

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Answer:

If sound waves of the same energy were passed through a block of wood and a block of steel, which is more dense than the wood, the molecules of the steel would vibrate at a slower rate. Sound moves faster through denser air because the molecules are closer together in dense air and sound can be more easily passed on.

Explanation:

What is the density of the block? Assume that the block is 40.0% submerged.First Sketches says block weigh 50g
Express the density numerically in grams per cubic centimeter.

Answers


There are forces are acting on the block: 1. Fs = upward force from scale (up = + Fs) 2. W = downward weight force (down = - W) 3. Fb = upward buoyancy force (up = + Fb) 
Since the block is at rest, (net force = 0), the force equation is: 
Fs + Fb - W = 0 ~(eq1) 
Substituting Fs, Fb and W into ~(eq1): ==> {m (on scale) x g} + {ρ x V x g} - (m (block) x g} = 0 
Dividing both sides of equation by g: m (on scale) + (ρ x V) - m (block) = 0 ~(eq2) 
Given: V = volume of water displaced = 40% volume of the block = 0.40 x V (block) 
Substituting 0.40 x V (block) into ~(eq2): m (on scale) + (ρ x 0.40 x V (block)) - m (block) = 0 ~(eq3) where, m (on scale) = 5.6 g ρ = density of water at 20ºC = 0.99821 g/cm^3 m (block) = 50 g 
Substituting m (on scale), ρ and m (block) into ~(eq3): 5.6 g + (0.99821 g/cm^3 x 0.40 x V (block)) - 50 g = 0 ~(eq4) 
Simplifying ~(eq4) and solving for V (block): ==> 5.6 g + 0.399284 g/cm^3 x V (block) - 50 g = 0 ==> 0.399284 g/cm^3 x V (block) - 44.4 g = 0 ==> 0.399284 g/cm^3 x V (block) = 44.4 g ==> V (block) = 44.4 g / (0.399284 g/cm^3) ==> V (block) = 111.199 cm^3 
ρ (block) = density of block = m (block) / V (block) = 50 g / 111.199 cm^3 = 0.449644 g / cm^3