The combining of atoms together is known as nuclear

Answers

Answer 1

Answer: The correct word to fill the statement is fusion. The combining of atoms together is known as nuclear fusion. This reaction happens where two or more nuclei of an atom comes very close at a very high speed and joins to form a new nucleus.

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Before arc welding was developed, a displacement reaction involving aluminum and iron(III) oxide was commonly used to produce molten iron (the thermite process). This reaction was used, for example, to connect sections of iron railroad track. Calculate the mass of molten iron produced when 2.28 kg of aluminum reacts with 17.2 mol of iron(III) oxide.

Answers

Answer: The mass of molten iron formed will be 1.92 kg

Explanation:

We are given:

Moles of iron (III) oxide = 17.2 moles

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of aluminium = 2.28 kg = 2280 g (Conversion factor: 1 kg = 1000 g)

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium}=(2280g)/(27g/mol)=84.44mol$

The chemical equation for the reaction of aluminium and iron (III) oxide follows:

$2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe$

By Stoichiometry of the reaction:

1 mole of iron (III) oxide reacts with 2 moles of aluminium

So, 17.2 moles of iron (III) oxide will react with = $(2)/(1)* 17.2=34.4mol$ of aluminium

As, given amount of aluminium is more than the required amount. So, it is considered as an excess reagent.

Thus, iron (III) oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of iron (III) oxide produces 2 moles of iron

So, 17.2 moles of iron (III) oxide will produce = $(2)/(1)* 17.2=34.4mol$ of iron

Now, calculating the mass of iron by using equation 1, we get:

Molar mass of iron = 55.8 g/mol

Moles of iron = 34.4 moles

Putting values in equation 1, we get:

$34.4mol=\frac{\text{Mass of iron}}{55.8g/mol}\n\n\text{Mass of iron}=(34.4mol* 55.8g/mol)=1919.5g=1.92kg$

Hence, the mass of molten iron formed will be 1.92 kg

How many grams of water will form if 10.54 g H2 react with 95.10 g O2

Answers

Answer : The amount of water will be, 94.86 grams

Solution :

First we have to calculate the moles of $H_2$ and $O_2$ .

$\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=(10.54g)/(2g/mole)=5.27moles$

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=(95.10g)/(32g/mole)=2.97moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced reaction we conclude that

As, 2 moles of $H_2$ react with 1 mole of $O_2$

So, 5.27 moles of $H_2$ react with $(5.27)/(2)=2.63$ moles of $O_2$

That means, in the given balanced reaction, $H_2$ is a limiting reagent because it limits the formation of products and $O_2$ is an excess reagent.

The excess reagent remains $(O_2)$ = 2.97 - 2.63 = 0.34 moles

Now we have to calculate the moles of $H_2O$ .

As, 2 moles of $H_2$ react with 2 moles of $H_2O$

So, 5.27 moles of $H_2$ react with $(2)/(2)* 5.27=5.27$ moles of $H_2O$

Now we have to calculate the mass of $H_2O$ .

$\text{Mass of }H_2O=\text{Moles of }H_2O* \text{Molar mass of }H_2O$

$\text{Mass of }H_2O=(5.27mole)* (18g/mole)=94.86g$

Therefore, the amount of water will be, 94.86 grams

Answer:

94.03

Explanation:

edge 2023

Some scientific evidence suggests that our universe is ever-expanding from a hot and dense initial state. Briefly describe at least one piece of evidence that supports the theory known as the Big Bang.

Answers

cosmic microwave background radiation (CMBR) is one piece of evidence for the big bang

Answer:

Cosmic microwave background and Hubble's Law.

Explanation:

Microwave background is basically electromagnetic radiation, but it's the remanent from earlier periods of the universe, they are the oldest electromagnetic wave in the Universe. Also, Hubble's Law says that the Universe faster galaxies are those are further away, because they belong to the first period of the explosion.

When are conservation efforts most effective? a. Conservation efforts are most effective when multiple groups cooperate. b. Conservation efforts are most effective when government is solely responsible for them. c. Conservation efforts are most effective with individual efforts. d. Conservation efforts are always effective.

Answers

Conservation efforts most effective if Conservation efforts are most effective when multiple groups cooperate. The answer is letter A. The rest of the choices do not answer the question above

Answer: Option (a) is the correct answer.

Explanation:

Conservation efforts means to carefully preserve or protect something. These efforts are fruitful when a majority of people or communities come together in order to preserve something good for the betterment of environment.

As when maximum number of people come lend their hands for help only then conservation efforts can be achieved.

For example, a city with maximum pollution can only be conserved when maximum groups of people decide to conserve plants or plant more number of trees.

Thus, we can conclude that conservation efforts are most effective when conservation efforts are most effective when multiple groups cooperate.

What happens in a reduction half-reaction?elements gain electrons
elements lose electrons
oxygen is added
oxygen is lost

Answers

Answer: Option (a) is the correct answer.

Explanation:

A reduction-half reaction is defined as the reaction in which there occurs gain of one or more number of electrons by a specie or element.

Or, in a reduction-half reaction there occurs loss of oxygen if it is present in a reaction.

But in a reduction-half reaction loss of electrons will always take place.

For example, $CuO + Mg \rightarrow Cu + MgO$

Reduction-half reaction: $Cu^(2+) + 2e^(-) \rightarrow Cu$

So here, oxidation state of copper is changing from +2 to 0. Also, loss of oxygen is occurring in the reaction equation.

Oxidation-half reaction: $Mg \rightarrow Mg^(2+) + 2e^(-)$

Thus, we can conclude that in a reduction half-reaction elements gain electrons.

The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.

1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus, a. the strong nuclear force is much greater than the electric force.
b. the electric force is much greater than the strong nuclear force.
c. the strong nuclear force equals the electric force.
d. the strong nuclear force and the electric force are both attractive.
9. Uranium-238 undergoes alpha decay. Therefore, uranium-238 will
a. remain stable.
b. change into a different element altogether.
c. emit neutral particles and no energy.
d. none of the above

Answers

1. Answer;

a. the strong nuclear force is much greater than the electric force.

Explanation;

For an atom to be stable it means it has enough amount of binding energy to hold its nucleus together permanently.
Therefore, an unstable atom lacks enough amount of binding energy to hold its nucleus permanently and thus undergoes decay to achieve stability. Unstable atoms are therefore referred to being radioactive.
Small atoms are stable; this is because they have equal number of protons and neutrons and thus the protons and neutrons fill up energy levels while maximizing the strong force binding the nucleus together.

9. Answer;

b. change into a different element altogether.

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will change into a different element altogether.

Explanation;

Unstable atoms undergo radioactive decay in order to achieve stability of their nucleus.
Uranium-238 is an example of such atom, which may undergo decay to achieve stability.
Alpha decay is one of the types of decays, others being beta decay and gamma decay. In alpha decay the radioactive isotope undergoes decay such that its mass number is decreased by four and its atomic number is decreased by two.
Therefore, Uranium-238 undergoes alpha decay to form a different element whose mass number is 234 and atomic number is 90, known as thorium-234.

1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus,

a. the strong nuclear force is much greater than the electric force.

9. Uranium-238 undergoes alpha decay. Therefore, uranium-238 will

b. change into a different element altogether.

Hope these answer the questions. Have a nice day.

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