Answer:
7200 m
Explanation:
This problem is an example of an uniformly accelerated motion, in which the acceleration remains constant. As such, the formula for the displacement is:
D(t) = D₀ + v₀*t + 0.5*a*t²
Where D₀ is the initial displacement, v₀ is the initial velocity (in this case it's 0 m/s), a is the aceleration (8 m/s²) and t is the time, in seconds.
Using a t=30.0 s, we're left with:
D(t) = 0 m + 0 m/s * 30.0 s + 0.5 * 8.00 m/s² * (30.0 s)²
D(t) = 0.5 * 8.00 m/s² * (30.0 s)²
D(t) = 7200 m
An 'amine' is an organic compound primarily composed of carbon(C), hydrogen(H) and nitrogen (N).
Ammonia is a molecule in which the N atom is attached to 3 H atoms, in addition there is a lone pair of electrons on the central N atom. Amines are essentially derivatives of ammonia where one of more H atoms have been replaced by an alkyl (R) or aryl(Ar) group
For example:
R-NH2 == primary amine
R2-NH == secondary amine
R3N == tertiary amine
Answer:An atom has 5 protons, 5 electrons and 6 neutrons The atomic number = number of protons = number of electrons = 5 The mass number = 5 protons + 6 neutrons = 11
B.) 96 test tubes
C.) 288 test tubes
D.) 384 test tubes
Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, the correct option is option C.
Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.
Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.
So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter.
Total students= number of chemistry classes× number of students
=3 × 24
=72
Each student requires 4 test tubes.
72 ×4 = 288 test tubes.
Therefore, the correct option is option C.
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Answer:
The Barium flame is green because it is a difficult flame to excite, therefore for it to trigger a flame it is necessary that it be too excited for it to occur.
The reddish color of calcium is due to its high volatility and it is sometimes very difficult to differentiate it from strontium.the compression of these elements is due to being able to make them work during combustion
Explanation:
The flame test is a widely used qualitative analysis method to identify the presence of a certain chemical element in a sample. To carry it out you must have a gas burner. Usually a Bunsen burner, since the temperature of the flame is high enough to carry out the experience (a wick burner with an alcohol tank is not useful). The flame temperature of the Bunsen burner must first be adjusted until it is no longer yellowish and has a bluish hue to the body of the flame and a colorless envelope. Then the tip of a clean platinum or nichrome rod (an alloy of nickel and chromium), or failing that of glass, is impregnated with a small amount of the substance to be analyzed and, subsequently, the rod is introduced into the flame, trying to locate the tip in the least colored part of the flame.
The electrons in these will jump to higher levels from the lower levels and immediately (the time that an electron can be in higher levels is of the order of nanoseconds), they will emit energy in all directions in the form of electromagnetic radiation (light) of frequencies characteristics. This is what is called an atomic emission spectrum.
At a macroscopic level, it is observed that the sample, when heated in the flame, will provide a characteristic color to it. For example, if the tip of a rod is impregnated with a drop of Ca2 + solution (the previous notation indicates that it is the calcium ion, that is, the calcium atom that has lost two electrons), the color observed is brick red .
Answer:
The different colours produced come from the different wavelength of the spectrum of light as the excited electrons in the metals return to their original state on cooling down.
Explanation:
The flame test is an analytical procedure used to identify different metals by passing them through a flame.
The flame, which is a source of heat energy heats up the metals and excites their outermost electrons which transit to the next energy level. On cooling down, as the excited electrons return to their original state, they emit different colours corresponding to the spectrum of light. Electrons of larger atoms like Barium emit light of higher frequency and lower wavelength and hence exhibits colours closer to the ultraviolet part of the electromagnetic spectrum while smaller atoms like Calcium emit light of lower frequency and higher wavelength and emit light closer to the infrared part of the spectrum
Baruim (atomic number 56) and Calcium (atomic number 20) are both metals in group two of the periodic table.
They both have two electrons in their outermost shell and are represented by Ba²⁺ and Ca²⁺.
When both metals are passed to through the flame test, the two outermost electrons in both metals are excited.
However because the outermost electrons in Barium are farther to the nucleus than those in Calcium, it takes a lesser amount of heat energy to excite them than that of Calcium which is closer to the nucleus.
The spectrum of light which is usually represented by 'ROYGBIV' has the following colours : Red, Orange,Yellow, Green, Indigo and Violet with Red having their highest wavelength (or shortest frequency) and Violet the shortest wavelength (or highest frequency).
Barium's green colour is because it outermost electrons emit light in the range of the Green spectrum of light and calcium's red colour is because its outermost electrons emit light in the range of the Red spectrum of light