CHEMISTRY HIGH SCHOOL

State, in terms of the arrangement of atoms, the difference in hardness between diamond and graphite.

Answers

Answer 1
Answer:

The difference in hardness between diamond and graphite is that diamond has an ordered arrangement of atoms within its structure that makes it harder and stronger than graphite. This is due to the high pressure and high temperature that it went.
Answer 2
Answer:

Final answer:

Diamond is significantly harder than graphite due to its tightly packed arrangement of atoms, while graphite is soft and slippery because of its layered structure.

Explanation:

The difference in hardness between diamond and graphite can be explained by their arrangement of atoms. In diamond, each carbon atom is bonded to four neighboring carbon atoms in a tetrahedral arrangement, creating a rigid and tightly packed structure. This arrangement gives diamond its hardness. On the other hand, in graphite, each carbon atom is bonded to only three neighboring carbon atoms, forming layers that are held together by weak forces called van der Waals forces. These layers can slide past each other easily, making graphite soft and slippery.

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Complete the following equations by correctly matching the appropriate product.

Answers

Answer: _(82)^(206)\textrm {Pb}

Explanation:

Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

The general alpha decay reaction is given as:

_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)\textrm{Y}+_2^4\alpha

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

Thus the balanced reaction is :

_(84)^(210)\textrm{Po}\rightarrow _(82)^(206)\textrm{Pb}+_2^4\alpha
the first equation we are emitting an alpha particle so we take the top number and decrease it by 4 from 210 to 206 and the bottom number by 2 from 84 to 82.  so that would match with Pb-206 (the 206 is the top number)

the second equation the 218 will drop to 214 and the 84 to 82 leaving us with Pb-214

A sample of 0.3257 g of an ionic compound containing the bromide ion (Br−) is dissolved in water and treated with an excess of AgNO3. If the mass of the AgBr precipitate that forms is 0.7165 g, what is the percent by mass of Br in the original compound?

Answers

Answer:

Explanation:

Given parameters:

Mass of ionic compound = 0.3257g

Mass of AgBr precipitate = 0.7165g

Unknown:

Percent mass of Br in the original compound.

Solution

The percent mass of Br in original compound = (mass of  Br  in the sample)/(mass of sample)

Now we have to find the mass of Br⁻:

We must note that the same mass of Br⁻ would move through the ionic sample to form the precipitate.

Mass of Br in AgBr = (Atomic mass of Br)/(Molar mass of AgBr)  x mass of precipitate

Mass of Br =  (80)/(80 + 108)  x 0.7165

Mass of Br = 0.426 x 0.7165 = 0.305g

Percent mass of Br = (0.305)/(0.3257) x 100 = 93.7%

How many mole of chlorine gas react with 0.100 mol of metal iron?
Fe+Cl2-> FeCl2

Answers

                       2 mol Cl
.100 mol Fe  x ------------- = .05 mol Cl
                        1 mol Fe 

What is the change in heat energy when 64.82 g of aluminum metal at 100.0oC is cooled to 82.0 °C? The specific heat of aluminum is 0.897 J /g °C.

Answers

Given:

64.82 g of aluminum metal

100.0oC is cooled to 82.0 °C

specific heat of aluminum is 0.897 J /g °C.

Required:

Change in heat energy

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

The specific heat of the water is 4.18 J/g-K

Plugging in the values into the equation

H = mCpT

H = (64.82) (0.897 J /g °C) (82 – 100)

H = -1,046.6 J

35g of HF was prepared by reacting 112g of CaF2 with an excess of H2SO4 calculate the percentage yield

Answers

Answer: 61%


The reaction equation should be

CaF2 + H2SO4 → 2HF + CaSO4

For every 1 molecule CaF2 used, there will be 2 molecules of HF formed. The molecular mass of CaF2 is 78/mol while the molecular mass of HF is 20g/mol. If the yield is 100%, the amount of HF formed by 112g CaF2 would be: 112g/(78g/mol) * 2 * (20g/mol)=57.43g

The percentage yield of the reaction would be: 35g/57.43g= 60.94%

Rainforests are typically responsible for global oxygen turnover

Answers

false...........................................

Answer:

false

Explanation:
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