Based on relative bond strengths, classify these reactions as endothermic or exothermic.
Answers
Exothermic Reactions are those that release energy and thus heat. These are given in the oxidation reactions which, by being very intense, produce fire.
Endothermic Reactions are those that require heat energy to be produced. The most common reactions are those that transform matter from liquid to gas or solid to liquid.
Related Questions
Heelp plsWhich element has the lowest electronegativity? nitrogen (N) lithium (Li) bromine (Br) potassium (K)
Classify wine and beef stew as homogeneous or heterogeneous.
Atomic radiusa. increases across a period and increases down a group. b. decreases across a period but increases down a group. c. increases across a period but decreases down a group. d. decreases across a period and decreases down a group.
How many atoms of oxygen in this equation : 3Ni(OH)2
Answers
Answer:
Explanation:
A chemical change, as the name suggests, must result from a change in the chemical makeup and new substances are produced. A very common example is metal rusting.
A physical change can be observed without a change in chemical composition. No new substances are produces. Ripping paper and an ice cube melting are physical changes.
A rubber band stretching is a physical change. No new substances are made and the chemical makeup remains the same.
Answer:
physical
Explanation:
this is a physical action to create a change. does not involve chemicals or elements
Answers
Answer:
0.01917 m^3/kg.
Explanation:
Given:
P = 15 MPa
= 1.5 × 10^4 kPa
T = 350 °C
= 350 + 273
= 623 K
Molar mass of water, m = (2 × 1) + 16
= 18 g/mol
= 0.018 kg/mol
R = 0.4615 kPa·m3/kg·K
Using ideal gas equation,
P × V = n × R × T
But n = mass/molar mass
V = (R × T)/P
V/M = (R × T)/P × m
= (0.4615 × 623)/1.5 × 10^4
= 0.01917 m^3/kg.
Final answer:
The specific volume of superheated water vapor under the conditions of 15 MPa pressure and 350°C temperature, using the ideal gas equation, is approximately 0.01919 cubic meter per kilogram.
Explanation:
The question is asking to calculate the specific volume of superheated water vapor using the ideal gas equation P = ρRT, where P is the pressure, ρ is the density (inverse of specific volume), R is the gas constant, and T is the temperature.
To find the specific volume (v), we need to rearrange the ideal gas equation to v = RT/P. Given that the pressure P = 15 MPa = 15000 kPa, the gas constant R = 0.4615 kPa.m³/kg.K, and the temperature T = 350°C = 623.15 K (adding 273 to convert °C to K), we can substitute these values into our rearranged equation balance to calculate for v.
The specific volume v = (0.4615 kPa.m³/kg.K * 623.15 K) / 15000 kPa = 0.01919 m³/kg. So, the specific volume of superheated water vapor under the given conditions is approximately 0.01919 cubic meter per kilogram.
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Answers
2C8H18+25O2----> 16CO2+18H2O when balanced. 10/114.229 g/mol = .087543... mol, converting to moles by dividing by molar mass. The ratio is 25/2, using the integers in front of the molecules in the balanced equation. so you just multiply .087543... by the ratio. That's 1.09429, which you multiply by the molar mass of O2, 31.9988 g/mol. The answer is 35.02 g O2
35.2 grams of oxygen are required to react with 10.0 grams of octane
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Hydrocarbon combustion reactions (specifically alkanes)
For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:
Balancing C atoms, H and last atoms O atoms
Octane combustion reaction
C₈H₁₈ + O₂ ---> CO₂ + H₂O
To equalize the reaction equation we give the reaction coefficients with variables a, b and c while the most complex compounds, namely Octane, we give the number 1
So the reaction becomes
C₈H₁₈ + aO₂ ---> bCO₂ + cH₂O
C atom on the left 8, right b, so b = 8
left H atom = 18, right 2c so 2c = 18 ---> c = 9
Atom O on the left 2a, right 2b + 2c, so 2a = 2b + 2c
2a = 2.8 + 9
2a = 16 + 9
2a = 25
a = 25/2
The equation becomes:
C₈H₁₈ + 25/2O₂ ---> 8CO₂ + 9H₂O or be
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
To find the mass O2, we find the mole first from the mole ratio with Octane
- 1. We are looking for the octane mole
Mr. octane = 8.Ar C + 18.Ar H
Mr. octane = 8.12 + 18.1
Mr octane = 96 + 18
Mr octane = 114
known octane mass: 10 grams then the mole:
mol = gram / Mr
mol = 10/ 114
mol = 0.088
- 2. We look for the O₂ mole
because of the ratio of the reaction coefficient between O2 and octane = 25: 2 then the mole of O₂ =
25/2 x 0.088 = 1,1
So that the mass O₂ =
mole. Mr = 1.1 32
mass = 35.2 grams
a combustion reaction
the type of chemical reaction
The combustion of alkanes, alkenes, and alkynes
Complete combustion of a sample of a hydrocarbon
Keywords: Complete combustion of Hydrocarbons, alkanes, equalize the reaction equation
Answers
Here it is how to solve.
Molecular mass of Ar = 40
Molecular mass of Ne = 20
Number of moles of Ar = 9.59/40 = 0.239
Number of moles of Ne = 11.12/20= 0.556
Mole fraction of argon = 0.239/ ( 0.239 + 0.556) = 0.3
Answers
Answer: 1,88×10²³ atoms of Br in 25g of Br
Explanation:
25g Br
1 mol of Br =79,9g Br
Number of Avogadro: 6,022×10²³ = 1 mol
25gBr× 1molBr/79,9gBr =
6,022×10²³ atoms of Br/1 mol Br =
1,88×10²³ atoms of Bromine
energy from sunlight?
A. Vacuole
B. Nucleus
C. Chloroplast
D. Cell Membrane
Answers
Answer:
Chloroplast
Explanation: