What element was used to make the first atomic bomb

Answers

Answer 1
Answer: The element was uranium, it was made during World War II ( the first atomic bomb was dropped on Japan, Hiroshima )
For more information, a H-bomb ( Hydrogen bomb ) is more explosive ( the sun is made mostly by Hydrogen ) and North Korea declared that they just have one. 

Related Questions

There are more hydroxide ions in a solution than hydrogen ions. The solution is acidic basic neutral a salt
What is the best estimate for the capacity of the can of soda
Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 375 mL of insulin at a concentration of 40.0 mg/mL . What is the total mass of insulin in the bottle?
The strength of a weak base is indicated by its "ionization constant Kb." The greater the value of Kb, the _____ the base. a) Weaker b) Stronger c) More neutral d) Less reactive
What is the symbol for an atom containing 20 protons and 22 neutrons?

Which of these statements about mixtures is true?Mixtures are made up of elements bonded together.
Elements and compounds are types of mixtures.
Pure substances are made up of mixtures combined in specific ratios.
Mixtures are classified based on the distribution of particles in them.

Answers

Answer: Option (d) is the correct answer.

Explanation:

When two or more different substances are mixed together then it results in the formation of a mixture.

Mixture are of two types, that is, homogeneous mixture and heterogeneous mixture.

In homogeneous mixture, the constituent particles are distributed evenly throughout the mixture.

Whereas in heterogeneous mixture, the constituent particles are non-uniformly distributed.

Thus, we can conclude that mixtures are classified based on the distribution of particles in them.

The best answer from the choices would be the last option. Mixtures are classified based on the distribution of particles in them. The classification are called homogeneous and heterogeneous mixtures. The former type describes a mixture where all components are distributed evenly. The latter type is a mixture where the components do not have uniformity in the mixture.

How many mL of 0.100 m NaHCO3 are needed to prepare 750.0ml of a 0.0500 m NAHCo3 solution

Answers

Following the rule of thumb in dilution, the equation that can be used to solve this problem is:

C1V1 = C2V2

where:
C1 = concentration of solution 1
V1 = volume of solution 1
C2 = concentration of solution 2
V2 = volume of solution 2

(0.1)(V1) = (0.05)(750)
V1 = 375 mL

This shows that 375 mL of a 0.1 m NaHCO3 solution is needed in order to dilute it to a 0.05 m NaHCO3 solution of 750 mL.

All compounds containing carbon are organic.
a. True
b. False

Answers

False, not all compounds containing carbon is organic rather all organic compounds contain carbon and hydrogen. Some compounds containing carbon are considered to be inorganic like carbon dioxide, carbon tetrachloride and sodium bicarbonate.

CHEMISTRYWhich of the following properties of an element is least likely to change with beta decay?

A. the mass number
B. the period number
C. the atomic number
D. the name of the element

When a nucleus has too many protons, it can absorb an electron and create _________.

A. a proton
B. a neutron
C. an electron
D. an alpha ray

Which of the following occurs in beta decay?

A. A neutron of an atom emits a high energy proton.
B. A neutron of an atom emits a high energy electron.
C. An electron of an atom emits a high energy proton.
D. A neutron of an atom emits a second high energy neutron.

What kind of ray is given off after electron capture?

A. a beta ray
B. a delta ray
C. an alpha ray
D. a gamma ray

Answers

number 1.c
number 2.a
number 3.b
number 4.d

Answer:

Which of the following occurs in beta decay?

Answer: A neutron of an atom emits a high energy electron.

Explanation:

Via Educere/ Founder's Education

The percent by mass of carbon in HC2H3O2 is equal to__.

Answers

The percent mass of carbon is found by dividing the total mass of the carbon in the compound by the total mass of the compound itself. The mass of the compound is found by adding the molecular masses of the elements. The mas of the compund is 60 grams/mole. There are two Carbon atoms in the compound and each Carbon atom weighs 12 grams/mole, so two Carbon atoms weigh 24 grams/mole. The percent by mass of Carbon is (24grams/mole) divided by (60 grams/mole) times 100 which is equal to 40%. The correct answer is 40%.

Final answer:

The percent by mass of carbon in acetic acid (HC2H3O2) is calculated using the molar masses of its constituent elements. Upon calculation, it is determined that the percent by mass of carbon in acetic acid is 40.00%.

Explanation:

To calculate the percent by mass of carbon in acetic acid (HC2H3O2), we need to use the molar masses of the elements involved. The formula for acetic acid includes two carbon atoms, four hydrogen atoms, and two oxygen atoms. Using the given molar masses (carbon: 12.01 g/mol, hydrogen: 1.008 g/mol, oxygen: 16.00 g/mol), the molar mass of acetic acid can be calculated as follows:

  • Carbon: 2 × 12.01 g/mol = 24.02 g/mol
  • Hydrogen: 4 × 1.008 g/mol = 4.032 g/mol
  • Oxygen: 2 × 16.00 g/mol = 32.00 g/mol

Adding these together gives the molar mass of acetic acid as 60.052 g/mol.

To find the percent by mass of carbon, we take the total mass of carbon in the compound and divide it by the total molar mass of the compound:

(24.02 g/mol / 60.052 g/mol) × 100% = 40.00%

Therefore, the percent by mass of carbon in acetic acid is 40.00%.

46 What occurs at one of the electrodes in both an electrolytic cell and a voltaic ccl1?( I) Oxidation occurs as electrons arc gained at the cathode.
(2) Oxidation occurs as electrons are lost at the anode.(3) Reduction occurs as electrons are gained at the anode.
(4) Reduction occurs as electrons are lost at the cathode.

Answers

Oxidation occurs as electrons are lost at the anode at one of the electrodes in both an electrolytic cell and a voltaic cell. The answer is number 2. The rest of the choices does not answer the question given above.