Given that the molar mass of CO2 is 44.01 g/mol, how many liters of oxygen is required at STP to produce 88.0 g of CO2 from this reaction?
44.8 L
45.00 L
89.55 L
89.6 L
89.6 L of O₂
The balanced chemical equation is as,
CH₄ + 2 O₂ → CO₂ + 2 H₂O
As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,
44 g ( 1 mol) CO₂ is produced by = 44.8 L (2 mol) of O₂
So,
88 g CO₂ will be produced by = X L of O₂
Solving for X,
X = (88 g × 44.8 L) ÷ 44 g
X = 89.6 L of O₂
B. The neutrons do not affect the mass or stability of an atom's nucleus, but they are involved in most interactions between two atoms.
C. The neutrons do not affect how the atom interacts with other atoms, but they do have an effect on the mass and stability of the nucleus.
b. Heat the polonium until it becomes a gas.
c. Expose the polonium sample to light.
d. Increase the amount of polonium.
Increase the amount of Polonium
The concentration of the resulting solution is 0.33 M. The correct option is 3. 0.33 M
From the question, we are to determine the concentration of the resulting solution
From the dilution law,
M₁V₁ = M₂V₂
Where M₁ is the initial concentration
V₁ is the initial volume
M₂ is the final concentration
V₂ is the final volume
From the given information
M₁ = 1.0 M
V₁ = 20 mL
M₂ = ?
V₂ = 60 mL
Then,
1 × 20 = M₂ × 60
20 = M₂ × 60
Therefore,
M₂ = 20 ÷ 60
M₂ = 0.33 M
Hence, the concentration of the resulting solution is 0.33 M. The correct option is 3. 0.33 M
Learn more on Dilution here: brainly.com/question/5685564
B.2.2 newton
C2.5 newton
D.3.5 newton
yes 2.5 is correct for plato!
Assuming the other part of the question is;
A solid mixture consists of 44.2g of KNO3 (potassium nitrate) and 7.8g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water. (Assume KNO3 has a solubility of 14 g solute/ 100 g water)
Answer;
26 g
Solution;
-X g of KNO3/ 130 g water= 14 g of KNO3/ 100 g water
X= 18.2 g (this is the amount of solute that dissolves at 0 degrees C in 130 g water).
if you have 44.3g of KNO3 in 130 g of water at 0 degrees celsius and only 18.2 can dissolve then
44.2g - 18.2g = 26 g left undisolved which gives you the amount that would crystallize
KNO3 of 10g will undergo crystallization at 0 °
Because the heavier the KNO3 mass will require a higher temperature in the dissolution process.
Potassium nitrate is a nitrate salt compound from potassium with the molecular formula KNO3. Potassium nitrate salt can be made by reacting potassium chloride with sodium nitrate. If the saturated solution each of the solution is mixed with each other, then it will form sodium chloride salt because NaCl in water is small, the salt will settle. By cooling the filtered filtrate KNO3 will undergo crystallization
This compound decomposes with oxygen evolution at 500 ° C according to the reaction equation:
2 NaNO3 (s) -> 2NaNO 2 (s) + O2 (g)
Crystallization is separation by forming crystals so that the mixture can be separated. A gaseous or liquid substance can cool or condense and form crystals because it undergoes a crystallization process. Crystals will also form from a solution that will be saturated with a certain solvent. The more the number of crystals, the better, because the less likely to be polluted by dirt.
Potassium Nitrate has a physical white powder that is easily soluble in water and odorless. Meanwhile, to analyze the structure and characteristics of Potassium Nitrate MM2 data processing is used in the Chemoffice 15.0 application. This data processing is used to determine the shape of compounds, types of bonds in molecular movement compounds and other parts that can not be observed directly by the eye without the aid of tools. And for the form of compounds in 2 dimensions and 3 dimensions used Chemdraw 15.0 and Chem3D 15.0 applications
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Potassium nitrate brainly.com/question/10847775
Crystallization brainly.com/question/2575925
Details
Grade: High School
Subject: Chemistry
Keyword: kno3, nitrate, crystallization