Hydrogen sulfide burns form sulfur dioxide:2H2S(g) +3O2(g) → 2SO2(g) + 2H2O(g) ΔH= -1036 kJ
Calculate the enthalpy change when burning 26.7 g of hydrogen sulfide in kJ
pls help
Answers
Answer: 404.04 kJ.
Explanation:
To calculate the moles, we use the equation:
moles of
According to stoichiometry :
2 moles of on burning produces = 1036 kJ
Thus 0.78 moles of on burning produces =
Thus the enthalpy change when burning 26.7 g of hydrogen sulfide is 404.04 kJ.
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Answers
Answer:
1.33%
Explanation:
In an aqueous solution, a weak acid such as acetic acid, will be in equilibrium with its conjugate base, acetate ion, thus:
CH₃CO₂H(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CH₃CO₂⁻(aq )
Where dissociation constant, ka, is defined as the ratio of concentrations of products and reactants:
Ka = 1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]
H₂O is not taken into account in the equilibrium because is a pure liquid
When a solution of acetic acid becomes to equilibrium, the original concentration of the acid decreases producing more H₃O⁺ and CH₃CO₂⁻.
The concentrations at equilibrium when a 0.100M solution of acetic acid reaches this state, is:
[CH₃CO₂H] = 0.100M - X
[H₃O⁺] = X
[CH₃CO₂⁻] = X
Where X is reaction coordinate.
Replacing in Ka expression:
1.8x10⁻⁵ = [H₃O⁺] [CH₃CO₂⁻] / [CH₃CO₂H]
1.8x10⁻⁵ = [X] [X] / [0.100M - X]
1.8x10⁻⁶ - 1.8x10⁻⁵X = X²
1.8x10⁻⁶ - 1.8x10⁻⁵X - X² = 0
Solving for X:
X = -0.00135 → False solution. There is no negative concentrations.
X = 0.00133 → Right solution.
That means concentration of acetate ion is:
[CH₃CO₂⁻] = 0.00133M.
Now, percent ionization is defined as 100 times the ratio between weak acid that is ionizated, [CH₃CO₂⁻] = 0.00133M, per initial concentration of the acid, [CH₃CO₂H] = 0.100M. Replacing:
% Ionization = 0.00133M / 0.100M × 100 =
1.33%
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Answers
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Answers
? ----------- 9.02x10²³ molecules
9.02x10²³ * 1 / 6.02x10²³
9.02x10²³ / 6.02x10²³
= 1.4983 moles
hope this helps!
Answers
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Answers
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The water molecules speed up, attractions between them become weaker, and the molecules spread out.
The water molecules speed up, new bonds are formed, and the new molecules are pulled closer together.
Answers
Answer:
The water molecules slow down, stronger attractions form between them, and the molecules stop flowing around.
Explanation:
imagine how the solids (so ice) are structured: atoms are very close to each other and vibrate on the spot.