3.3 kg aluminum chromate

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Answer 1
Answer: this is not a question

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Explain how methane (ch4) and ethane (c2h6) demonstrate the law of definite composition and the law of multiple proportions

Answers

Methane and ethane demonstrate the law of definite composition and the law of multiple proportions as these both compounds have the exact atoms but in different ratios.  

As for methane, it can be seen that every methane molecule contains 4 hydrogen atoms and 1 carbon atom. Where masses of carbon and hydrogen are in ratio - 12 g C / 4 g H -- reduce to 3g C/ 1 g H .

Ethane contains 2 carbon atoms and 6 hydrogen atom and their mass ratio will be  - 24 g C / 6 g H -- reduce to 4 g C/ 1 g H .

So both ethane and methane demonstrate the law of definite composition and the law of multiple proportions.

Law of definite composition: The elements which are present in the compound is combined in the same proportion by mass.

Law of multiple proportion: When two or more compounds are formed by the combination of two elements then the mass ratio of one element is combined with the fixed mass of the other element.

In case of methane, it consist of one carbon atoms and four hydrogen atoms implies that has definite composition. In terms of mass, in methane, carbon and hydrogen atoms are combined in a definite ratio i.e. 12 g C/ 4 g H. Thus, methane has definite composition.  

Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to 4/3 ratio for the formation of ethane (hydrocarbon). Thus, law of multiple proportion followed.

Similarly, in case of ethane, this compound also consist of exact atoms but in different ratios.

In case of ethane, it consist of two carbon atoms and six hydrogen atoms implies that has definite composition. In terms of mass, in ethane, carbon and hydrogen atoms are combined in a definite ratio i.e. 24 g C/ 6 g H. Thus, methane has definite composition.  

Now, carbon and hydrogen combines to give a class i.e. hydrocarbon. In this case, for every constant mass of carbon the ratio of hydrogen will always reduce to a specific ratio for the formation of methane (hydrocarbon). Thus, law of multiple proportion followed.


You walk in the front door of your home. You smell an onion that someone is cutting in the kitchen. Explain why you are able to smell it, what this process is called, and what other types of substances exhibit this behavior.

Answers

Answer: We are able to smell it because the particles move from their high concentration to low concentration and mix with the gases present in the atmosphere and thus we are able to smell it.

Diffusion is a process in which a movement of substance takes place from a high concentration area to a low concentration area due to the random movement of the particles. Diffusion happens in gases more faster than liquids and solids because of the random movement of their particles.

Other substances exhibiting this behavior is perfume, incense sticks and cooking of food etc.



This is the process of diffusion and is exhibited by gases. The compounds responsible for the smell of onions are released into the air and diffuse through out the house due to random molecular movement. This allows you to smell them at the entrance of your house.

The balanced equation below represents a molecule of bromine separating into two bromine atoms.Br2-->Br + Br
What occurs during this change?
(1) Energy is absorbed and a bond is formed.
(2) Energy is absorbed and a bond is broken.
(3) Energy is released and a bond is formed.
(4) Energy is released and a bond is broken.

Answers

(4) Energy is released and a bond is broken. This happens because when the bromine molecule splits, the energy that was holding the two atoms together is released.

Answer is: (2) Energy is absorbed and a bond is broken.

This energy is called bond-dissociation energy.

Bond-dissociation energy is the measure of bond strength in a chemical bond.

Bond energy of bromine molecule (sigma bond) is energy needed for breaking up one molecule of bromine into two bromine atoms.

When two bromine atoms (Br) form molecule of bromine (Br₂), than energy is released and bond is formed.


1.34 milligrams is the same as _____ kg and _____g. here are some answers you can pick from for Kg the choices below are the same for G
A. 13.4
B. 0.0134
C. 0.00000134

Answers

answer C is for kg and but it's .00134 for grams
1.34 milligrams in kg is C. 0.00000134 whereas 1.34 milligrams  in gm is 0.00134. 

Why am i not good enough :,(

Answers

You are good enough. Times are tough know but believe it’ll get better.

there is no answer

because everyone is perfect in their own way

;)

How many moles of H2 are needed to react with 1 mole off N2?

Answers

3 H + N = 2 NH

3 moles H₂ ------- 1 mole N₂
? moles H₂ -------- 1 mole N₂

H₂ = 1 * 3 / 1

H₂ = 3 / 1

= 3 moles of H₂

hope this helps!