The inverse of the function f(x) = x + 10 is shown.h(x) = 2x –

What is the missing value?

Answers

Answer 1
Answer:

we have

f(x) = (1)/(2)x + 10

Step 1

Let

y=f(x)

y = (1)/(2)x + 10

Exchange the variable x for y and variable y for x

x = (1)/(2)y + 10

Clear variable y

Multiply by 2 both sides

2x = y + 20

y = 2x-20

Let

f(x)^(-1) =y

f(x)^(-1)=2x-20

therefore

the answer is

the inverse of the function is f(x)^(-1)=2x-20

the missing value is 20



Answer 2
Answer:

Answer:

The Given function is

y= x + 10

To find the inverse of function , we use the following procedure

x=y-10

Now, replace x by y and y by x, we get the inverse of function

y=x -10 , is the inverse of the function, y=x+10.

As, it is given that inverse of f(x) is h(x)

Also, h(x)= 2 x - k-------(1)

Inverse of f(x)=x+10 is ,y= x-10, that is 2 y=2 x- 20------(2)

Comparing 1 and 2, gives

h(x)=2 y

-k=-20

k=20


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-1.5 __ -1.05 Is it < or >

(5x2 + 2x + 11) − (7 + 4x − 2x2)

Answers

The difference between the polynomials 5x² + 2x + 11 and  7 + 4x - 2x² is  7x² - 2x + 4 option (D)7x² - 2x + 4 is correct.

What is polynomial?

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n

The complete question is:

FIND THE DIFFERENCE:

(5x² + 2x + 11) - (7 + 4x - 2x²)

  • A. 9 - 2x - 2x²
  • B. 3x² - 2x + 4
  • C. 3x² + 6x + 4
  • D.7x² - 2x + 4

We have two polynomials:

5x² + 2x + 11 and  7 + 4x - 2x²

We have subtract the polynomial 7 + 4x - 2x² from the polynomial 5x² + 2x + 11

= (5x² + 2x + 11) - (7 + 4x - 2x²)

Using distributive property:

= 5x² + 2x + 11 - 7 - 4x + 2x²

= 7x² - 2x + 4

The difference is 7x² - 2x + 4

Thus, the difference between the polynomials 5x² + 2x + 11 and  7 + 4x - 2x² is  7x² - 2x + 4 option (D)7x² - 2x + 4 is correct.

Learn more about Polynomial here:

brainly.com/question/17822016

#SPJ4

the answer would end up being 12x+4

I'll give 100 pts and brainliest if you answer this!!!thank you for the help boo

Perform the operation. Write the answer in standard form.
1. (6 − i) + (9 + 5i)
2. (7 + 3i) + (11 + 2i)
3. (12 + 4i) − (2 − 15i)
4. (3 − 7i) − (3 + 5i)
5. 7 − (2 − 3i) + 6i
6. −16 + (3 + 4i) − 4i
7. 3i(6 − 5i)
8. −2i(8 + 2i)
9. (−5 + i)(8 − 6i)
10. (3 − 6i)(−1 + 7i)
11. (2 + 5i)(2 − 5i)
12. (−3 − i)(−3 + I)
13. (4 + i) 2
14. (5 − 9i) 2
Thank you again <3

Answers

Answer:

1. 4i+15

2. 5i+18

3. -11i+10

4. -2i

5. 9i+5

6. -13

7. -15i^(2)+18i

8. -4i^2-16i

9. -6i^2+38i-40

10. -42i^2+27i-3

11. -25i^2+4

12. -i^2+9

13. 2i+8

14. -18i+10

Step-by-step explanation:

Standard form means to put the terms in order based on their exponent (x³ -> x² -> x -> constant)

1. (6 - i) + (9 + 5i)

4i+15

2. (7 + 3i) + (11 + 2i)

5i+18

3. (12 + 4i) - (2 - 15i)

-11i+10

4. (3 - 7i) - (3 + 5i)

-2i

35i^2+6i-9

5. 7 - (2 - 3i) + 6i

7 - 2 + 3i + 6i

9i+5

6. -16 + (3 + 4i) - 4i

-16 + 3 + 4i - 4i

-13

7. 3i(6-5i)

18i-15i^2

-15i^2+18i

8. -2i(8+2i)

-16i+-4i^2

-4i^2-16i

9. (-5 + i)(8 - 6i)

-40+30i+8i-6i^2

-6i^2+38i-40

10. (3 - 6i)(-1 + 7i)

-3+21i+6i-42i^2

42i^2+27i-3

11. (2 + 5i)(2 - 5i)

4-10i+10i-25i^(2)

-25i^2+4

12. (-3 - i)(-3 + i)

9 -3i + 3i -i^2

-i^2+9

13. (4 + i) * 2

2i+8

14. (5 - 9i) * 2

-18i+10

:p when I first started answering this I thought the parentheses were being multiplied every time and did 100x more work .-.

Hope it helps <3 :D

The Waverly Brush Company issued 4,000 shares of common stock worth $200,000.00 total. What is the par value of each share?

Answers

what you have to do for this is to divide the total worth ($200,000.00) by the number of shares.

So this means that we need to count:

200 000 ÷4 000

here's a trick:
if you divide two numbers with many 0s at the end, you can always erase the SAME mount of 0s at the end (this is equivalent to dividing by 10).

so
200 000 ÷4 000

is equivalent to :

200 ÷4

which is 50! (4*50=200)

so the answer is that each share was worth 50 dollars.


The par value of each share is \boxed{\$ 50} if the Waverly Brush Company issued 4,000 shares of common stock worth $200,000.00 total.

Further Explanation:

Given:

The Waverly Brush Company issued 4,000 shares.

The common stock worth is \$ 200000.

Calculation:

The given worth of the common stock is \$ 200000.

The total number of shares that Waverly Brush Company issued is 4,000.

The par value of each share can be calculated as follows,

\begin{aligned}{\text{Par value}} &= \frac{{200000}}{{4000}}\n&= \frac{{200}}{4}\n&= \$ 50\n\end{aligned}

The value of each share is \$ 50.

The par value of each share is \boxed{\$ 50} if the Waverly Brush Company issued 4,000 shares of common stock worth $200,000.00 total.

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  2. Suppose that you find the volume of all the oceans to be 1.4×109km3 in a reference book. to find the mass, you can use the density of water, also found in this reference book, but first you must convert the volume to cubic meters. what is this volume in cubic meters?brainly.com/question/1446243.

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Conic sections

Keywords: company, issue, 4000 share, shares, common stock, stock amount, par value share amount, worth, Waverly Brush Company, market value, par value.

Please help, timed! Will Mark brainliest!!
Which could be the function graphed below?

Answers

I believe the answer is the first choice. If I’m correct, the numbers outside of the square root are the y intercept, the graph is clearly starting in the negatives, it could be -2 (it being the y intercept). I hope this is right, my apologies if it isn’t.

Tourist: "How many birds and lions do you have in your zoo?" Zookeeper:"There are 30 heads and 100 feet." Find the number of each animal. I need to know how to set this problem up in a system of linear equations. Thank you.

Answers

Each lion has 1 head.  The number of lion heads is L .
Each bird has 1 head.  The number of bird heads is B.
The total number of heads of all species is (L + B) = 30

Each lion has 4 feet.  The number of lion feet is 4L .
Each bird has 2 feet.  The number of bird feet is 2B .
The total number of feet of all species is (4L + 2B) = 100

The system of linear equations is:

         L +   B =  30
       4L + 2B = 100 .

Maureen has a net spendable income of $2,100 per month. She sets up the following transportation budget for herself. Transportation (15% - 20%) 350 a. Car payments 150
b. Gas/Oil 120
c. Insurance 60
d. License/Registration 2
e. Taxes 5
f. Maintenance/Repair 50
what has she done wrong?


A: She budgeted more than the maximum recommended amount of money for transportation.

b: She has more money in the main category than she budgeted for in the subcategories.

c: She has more money in the subcategories than she budgeted for in the main category.

d: She budgeted less than the minimum recommended amount of money for transportation.

Answers

Answer:

c. She has more money in the subcategories than she budgeted for the main category

Explanation:

First, let's check the budget she set for the main category:

We are given that Maureen has net spendable income of $2,100.

The minimum amount she budgeted for transportation is 15% which can be calculated as follows:

Minimum budget for transportation = 15% * 2,100 = 0.15 * 2,100 = $315

Then, let's check her subcategories:

$150 for car payments, $120 for gas/oil, $60 for insurance, $2 for licence/registration, $5 taxes and $50 for maintenance/repair

This means that:

Minimum amount she will spend = 150 + 120 + 60 + 2 + 5 + 50 = $387

Now, let's compare:

Minimum budget set by Maureen is $315

Minimum amount she needs to spend on subcategories is $387

It is obvious that the minimum amount she needs is higher than the minimum budget she set for transportation, i.e., she has more money in subcategories than she budgeted in the main category.

This means that she needs either to increase her minimum budget for transportation or to lower the minimum amount she needs to spend.

Hope this helps :)


Answer:

Option C is correct.

Step-by-step explanation:

Given information is :

Net monthly spendable income = $2100

Transportation budget set up = $350 that lies between 15 to 20 percent of the net spendable.

Now adding her subcategories budget we get:

150+120+60+2+5+50=387

But Maureen has set $350 for this category. It clearly shows that the subcategories have more budget. So, either Maureen can increase her main category budget(this option is not given) or she can cut few of her subcategory budget to fall under $350.

Hence, Option c: She has more money in the subcategories than she budgeted for in the main category - is correct.