out of barium, chlorine, iodine, and strontium which atom has the strongest attraction for electrons in a bond formation?

Answers

Answer 1

Answer: Out of the choices given, the correct answer would be chlorine. It is the atom with the strongest attraction for electrons in a bond formation. This is because it has the highest electronegativity among the choices.

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In a titration of 0.5 M HCl and an unknown concentration NaOH, 25.0 ml of NaOH was required to completely neutralize 25.0 ml of HCl. What is the concentration of the NaOH?

How many fluorine atoms bond with calcium to form calcium fluoride?

Answers

Answer;

2 fluorine atoms

Explanation;

Calcium, a Group 2 metal, commonly forms a calcium ion (Ca2+). On the other hand, fluorine, a Group 7 non-metal, commonly forms a fluoride ion (F-). The necessity of electrical neutrality ensures that 2 Fluoride ions (F-) binds to one Ca2+
The charge on calcium is 2+ and the charge on fluoride ions is 1-. It therefore requires 2 fluoride ions to make the compound electrically neutral.

2 charge on calcium is 2+ and the charge on fluorideions is 1-. It therefore requires 2 fluoride ions to make the compound ..

The temperature of 15 grams of water increases by 3.0 degress. how much heat was absorbed by water?

Answers

The amount of heat absorbed by water is 188.28 J.

we know that, specific heat capacity is the amount of heat required to raise the temperature of 1 g of substance by 1 .0C

C = Q /W*ΔT

Q= C*W*ΔT

C= specific heat capacity

Q= amount of heat absorbed

W = weight of substance

ΔT = change in temperature

Specific heat capacity of water = 4.18 J/g.0C

Given that,

W = 15 g

ΔT = 3.0C

Q= C*W*ΔT

Q =4.184J/g. 0C*15g*3.0C

Q= 188.28 J

Thus, we can conclude that, the amount of heat absorbed by water is 188.28 J.

Learn more about heat capacity here:

brainly.com/question/22991121

Heat = Mass of water * specific heat of water * temperature rise=
15 g * 4.18 J/g K * 3K = 188J

Using the half-reaction method, balance the following redox reaction occurring in acidic solution:Ag + NO3- -> Ag+ + NO

Answers

to solve this half-reaction method, we divide the reaction into two equations- reduction and oxidation side. The oxidation is simply Ag= Ag+ + e-. The reduction side is 4H+ + NO3-+e-=NO+2H20. H2O is used to balance O and H+ is used to balance H. Hence the final equation is Ag+4H+ + NO3-= NO+2H2O.

A crucible contains 6.4 g of copper, Cu. How many moles does this amount contain? [Given: Cu=64]

Answers

Use this formula:
Mass = moles x RFM

(RFM = Relative Formula Mass, or the total mass of a substance or element for example Cu=64)

Rearrange the formula to find the number of moles
Moles = mass/RFM
=6.4/64
= 0.1

The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ. 2Na2O2(s) + 2H2O(l) → 4NaOH(s) + O2(g) The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with water is __________ kJ. 2Na2O2(s) + 2H2O(l) → 4NaOH(s) + O2(g) 40.4 80.8 -126 67.5 20.2

Answers

The amount of heat that is released by the chemical reaction of 25.0 g of $Na_(2)O_2$ with water is -20.223 Joules.

Given the following data:

Mass of $Na_(2)O_2$ = 25.0 grams

Enthalpy of combustion = -126 kJ/mol

To find the amount of heat that is released by the chemical reaction of 25.0 g of $Na_(2)O_2$ with water:

First of all, we would determine the number of moles of $Na_(2)O_2$ in this chemical reaction:

$2Na_2O_2_((s)) + 2H_2O_((l))$ ------> $4NaOH_((s)) + O_2_((g))$

$Number\;of\;moles \;(Na_(2)O_2)= (Mass\; of\;Na_(2)O_2)/(Molar\;mass\;of\;Na_(2)O_2)$

Substituting the values into the formula, we have;

$Number\;of\;moles \;(Na_(2)O_2)= (25.0)/(77.98)$

Number of moles ( $Na_(2)O_2$ ) = 0.321 moles.

Now, we can find the quantity of heat released when $Na_(2)O_2$ reacts with water:

2 mole of $Na_(2)O_2$ = -126 kJ/mol

0.321 mole of $Na_(2)O_2$ = X kJ/mol

Cross-multiplying, we have:

$2X = 0.321$ × $(-126)$

$2X = -40.446\n\nX = (-40.446)/(2)$

X = -20.223 Joules.

Answer : The amount of heat released by the reaction is, 20.2 kJ

Explanation :

First we have to calculate the number of moles of $Na_2O_2$ .

$\text{Moles of }Na_2O_2=\frac{\text{Mass of }Na_2O_2}{\text{Molar mass of }Na_2O_2}$

Molar mass of $Na_2O_2$ = 77.98 g/mole

$\text{Moles of }Na_2O_2=(25.0g)/(77.98g/mole)=0.320mole$

Now we have to calculate the heat released during the reaction.

The balanced chemical reaction is:

$2Na_2O_2(s)+2H_2O(l)\rightarrow 4NaOH(s)+O_2(g)$

From the reaction we conclude that,

As, 2 moles of $Na_2O_2$ releases heat = 126 kJ

So, 0.320 moles of $Na_2O_2$ releases heat = $(0.320)/(2)* 126=20.2kJ$

Therefore, the amount of heat released by the reaction is, 20.2 kJ

NaOH + H2SO4 =NaOH + HNO3 =
Cu(OH)2 + HCl =
H2SO4 =
HNO3 =

Answers

$2NaOH+H_2SO_4\Rightarrow\ Na_2SO_4+2H_2O\n NaOH+HNO_3\Rightarrow\ NaNO_3+H_2O\n Cu(OH)_2+2HCl\Rightarrow\ CuCl_2+2H_2O\n Cu(OH)2+H_2SO_4\Rightarrow\ CuSO_4+2H_2O\n Cu(OH)_2+2HNO_3\Rightarrow\ Cu(NO_3)_2+2H_2O$

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