PHYSICS HIGH SCHOOL

A textbook of mass 2.09 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.190 m, to a hanging book with mass 3.08 kg. The system is released from rest, and the books are observed to move a distance 1.26 m over a time interval of 0.800 s.

Answers

Answer 1

Answer:

Answer:

The tension in the part of the cord attached to the textbook is 6.58 N.

Explanation:

Given that,

Mass of textbook = 2.09 kg

Diameter = 0.190 m

Mass of hanging book = 3.08 kg

Distance = 1.26 m

Time interval = 0.800 s

Suppose,we need to calculate the tension in the part of the cord attached to the textbook

We need to calculate the acceleration

Using equation of motion

$y=ut+(1)/(2)at^2$

$a=(2y)/(t^2)$

Put the value into the formula

$a=(2*1.26)/(0.800)$

$a=3.15\ m/s^2$

We need to calculate the tension

When the book is moving with acceleration

Using formula of tension

$T=ma$

$T=2.09*3.15$

$T=6.58\ N$

Hence, The tension in the part of the cord attached to the textbook is 6.58 N.

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Answers

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Explanation: it is C

If a substance forms crystals when it solidifies, its _______ points are the same. a. melting and freezing
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Answers

I think the correct answer is A. If a substance forms crystals when it solidifies, its melting and freezing points are the same. For most substances, it is known that the freezing and the melting points are equal. Freezing happens by crystallization, formation of crystals from the liquid form.

Answer:

Option (a): Melting point and freezing point are will be the same when crystallization.

Explanation:

When crystals form from the mechanism of crystal growth, it’s known as crystallization. A crystal is a solid type of material which is having a regular pattern of atoms and molecules.

Temperature of a compound which changes its physical state from solid state to liquid state is known as melting point temperature.

Temperature of a compound which changes its physical state from liquid state to solid state is known as the freezing point temperature.

Most of the liquids are freeze by the method of crystallization. The temperature of the system remains nearly equal to melting point.

Further Explanation:

Basically there are two types of crystallization processes. They are the cooling and evaporation crystallization.

Salts, sugar and gemstones are some examples for crystals.

Crystallization consists with two steps; Nucleation and Crystal growth. In nucleation; solute molecules dispersed in the solvent are gather in to clusters. These clusters need to reach a critical size to become stable nuclei, by factors such as temperature and super saturation.

After nucleation, crystal growth happens. In this process the nuclei increases its size to a critical cluster size.

In crystal growth solute molecules precipitate out of solution. Then they dissolve back into solution.

Learn more:

1. Freezing point brainly.com/question/155317 (answer byTenishaTon)

2. Melting point brainly.com/question/13688040 (answer by olowookereboyede)

Keywords:

Melting point, freezing, crystallization

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Answers

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Answers

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Answers

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Answers

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Explanation:

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