There was frost on the ground overnight because the temperature dropped. In addition, there was cold, damp moisture in the air. This may mean that there is a good chance of _____ in the morning. precipitation fog sunshine thunderstorms

Answers

Answer 1
Answer:

Answer: Fog

Explanation:

Fog can be defined as the clouds on ground. Fog is made of condensed air and that is being cooled down to the point where it cannot hold more water.

The frost overnight forms fog. During the long nights the air gets cooled down and the the moisture in the air also adds to the formation of fog.

Thus, the correct answer is fog.

Answer 2
Answer: The answer would be fog.

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The _______ is the time required for one complete wave oscillation to occur.

Is oil less dense than water

Answers

Yah oil is less dence

I'm taking physics and trying to figure out the 4 questions to this problem.

Answers

Answer:

Explanation:

At t = 1 velocity = 0

At t = 3 velocity = 3

slope of the line = 3-0 / 3-1 = 3/2

At t = 2

velocity = 3/2 x ( 2 - 1 )

= 1.5 m /s

velocity at t = 2 is 1.5 m /s

Position at t = 2 :

displacement at t = 2

area of graph upto  t = 2

= 1 / 2 x 1 x 1.5 = .75

position at t = 2 :

= initial position + displacement

= 10 + .75 = 10.75 m

position at 6 s :

displacement at t = 6

area of curve upto  t = 6

= 1 / 2 x 2 x 3 +  3 x 3 + 1/2 x 3 x ( 4.5 - 3 )

= 3 + 9 + 2.25

= 14.25 m

position at t = 6

= initial position + displacement

= 10 + 14.25 = 24.25 m

position at 9 s :

displacement at t = 9

area of curve upto  t = 9

= 1 / 2 x 2 x 3 +  4 x 3 + 1/2 x 4 x ( 5 - 3 )- 1/2 x 2 x 1.5

= 3 + 12 + 4 - 1.5

= 17.5  m

position at t = 9

= initial position + displacement

= 10 + 17.5 = 27.5  m

Four resistors , R1=12ohms, R2= 15 ohms , R3= 18 ohms and R4=10 ohms are connected to 6 v battery in series what is the total resistance in the circuit?

Answers

Answer:

55 ohms

Explanation:

if it was series circuit, then you just need to add all the resistances

Why does a balloon when robbed on a wall sticks to the wall

Answers

Answer:

static electricity

Explanation:

The amoeba is a protozoan that moves with _____. flagella
cilia
pseudopodia
none of the above

Answers

The amoeba is a protozoan that moves with the pseudopodia. Pseudopodia is known as the false foot. Thus, the correct option is C.

What is Pseudopodia?

A pseudopod or pseudopodia is a temporary arm-like projection of a eukaryotic cell membrane such as algae that is emerged in the direction of movement of the organism. These are filled with cytoplasm. Pseudopodia primarily consist of the actin filaments and may also contain microtubules and other intermediate filaments.

Pseudopodia are responsible for the amoeboid movement, which includes sliding or crawling-like form of locomotion. This motion is visible in amoeba. The formation of cytoplasmic projections, or pseudopodia, on the cell surface, pulling the cell along in the direction of food, is a characteristic of the microscopic unicellular protozoans known as amoeba.

Therefore, the correct option is C.

Learn more about Amoeba here:

brainly.com/question/28367813

#SPJ6

The amoeba is a protozoan that moves with pseudopodia.

Answer: P
seudopodia

A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit of Mercury), at which point its speed is 9.5 104 m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6 1012 m from the Sun? (This is the approximate distance of Pluto from the Sun.)

Answers

Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7* 10^(10) m

v_i=9.5* 10^4 m/s

d_2=6* 10^(12) m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

(1)/(2)mv^2_i-(GmM)/(d_1)=(1)/(2)mv^2_f-(GmM)/(d_2)

(1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2)=(1)/(2)v^2_f

v^2_f=2((1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2))

v_f=\sqrt{2((1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2))}

Using the formula

v_f=\sqrt{v^2_i+2GM((1)/(d_2)-(1)/(d_1))}

v_f=\sqrt{(9.5* 10^4)^2+2* 6.7* 10^(-11)* 1.98* 10^(30)((1)/(6* 10^(12))-(1)/(4.7* 10^(10)))

Where mass of sun=M=1.98* 10^(30) kg

G=6.7* 10^(-11)

v_f=58515.9 m/s