What is potential energy?

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Answer 1
Answer: Potential Energy is a type of energy that is "possessed" by a body of its position, electrical charge, etc.
Answer 2
Answer:

Answer:

potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

Explanation:


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When creating any map, what four basic elements should you include?

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You must include a key, title, date of publication, and scale.
Title,Scale,Date of Publication,North Arrow (Legend,Location Information,and Source of Information)

Older auto-focus cameras sent out a pulse of sound and measured the time interval required for the pulse to reach an object, reflect off of it, and return to be detected. Can air temperature affect the camera's focus? New cameras use a more reliable infrared system.

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Temperature is also a condition that affects the speed ofsound. Heat, like sound, is a form of kinetic energy. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly. so the higher the air temperature the faster it will focus.

Answer:

ITS C!!

Explanation:I PROMISE!!

I GOT IT CORRECT!!!

JUST DO IT!!

Given a 3.00 μF capacitor, a 7.75 μF capacitor, and a 5.00 V battery, find the charge on each capacitor if you connect them in the following ways. (a) in series across the battery 3.00 μF capacitor μC 7.75 μF capacitor μC (b) in parallel across the battery 3.00 μF capacitor μC 7.75 μF capacitor μC.

Answers

Answer:

a) Q1= Q2= 11.75×10^-6Coulombs

b) Q1 =15×10^-6coulombs

Q2 = 38.75×10^-6coulombs

Explanation:

a) For a series connected capacitors C1 and C2, their equivalent capacitance C is expressed as

1/Ct = 1/C1 + 1/C2

Given C1 = 3.00 μF C2 = 7.75μF

1/Ct = 1/3+1/7.73

1/Ct = 0.333+ 0.129

1/Ct = 0.462

Ct = 1/0.462

Ct = 2.35μF

V = 5.00Volts

To calculate the charge on each each capacitors, we use the formula Q = CtV where Cf is the total equivalent capacitance

Q = 2.35×10^-6× 5

Q = 11.75×10^-6Coulombs

Since same charge flows through a series connected capacitors, therefore Q1= Q2=

11.75×10^-6Coulombs

b) If the capacitors are connected in parallel, their equivalent capacitance will be C = C1+C2

C = 3.00 μF + 7.75 μF

C = 10.75 μF

For 3.00 μF capacitance, the charge on it will be Q1 = C1V

Q1 = 3×10^-6 × 5

Q1 =15×10^-6coulombs

For 7.75 μF capacitance, the charge on it will be Q2 = 7.75×10^-6×5

Q2 = 38.75×10^-6coulombs

Note that for a parallel connected capacitors, same voltage flows through them but different charge, hence the need to use the same value of the voltage for both capacitors.

a friend tells you that his family always complains about the noise when he practices his electric guitar in his room. write at least three recommendations for how our friend might reduce the sound that escapes from his room. why do these changes to the room help reduce noise?

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