A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 42 states. What is the probability that she selects the route of four specific​ capitals? Is it practical to list all of the different possible routes in order to select the one that is​ best?P(she selects the route of four specific ​capitals): _____.
Is it practical to list all of the different possible routes in order to select the one that is​ best?
A.
​Yes, it is practical to list all of the different possible routes because the number of possible permutations is very small.
B.
​Yes, it is practical to list all of the different possible routes because the number of possible permutations is very large.
C.
No, it is not practical to list all of the different possible routes because the number of possible permutations is very small.
D.
No, it is not practical to list all of the different possible routes because the number of possible permutations is very large.

This question is not complete, I got the complete one from google as below:

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded.

The summary statistics are as follows.

Type A                                   Type B

x1 = 76.3 hrs                       x2 = 65.1 hrs

s1 = 4.5 hrs                          s2 = 5.1 hrs

n1 = 11                                  n2 = 9

The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:

4.90 hrs < μ1 - μ2 < 17.50 hrs

What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

C. The confidence interval includes only positive values which suggests that the two population means might be equal. There​ doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answer:

Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Step-by-step explanation:

The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.

Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Answer:

i think x=-1 and y=3. ....

Answer:

x = -1 ,  y = 3

Step-by-step explanation:

2x+5y = 13

-x+4y = 13

Decide whether to add or subtract the two equations by using Different Add Same Subtract (DASS)   or in case below as its SUBTRACT

i apply (SDSS).  

We subtract 5y as this is easier equation either positive prioritises or if both positive then easier number becomes priory.

Results to SDSS  before substituting Y if 5y etc was subtracted

2x+5y = 13             Subtract -5  

2x+5y -5y = 13 -5y  

2x= 13 - 5y             then Divide by 2

2x / 2 = 13/2 - 5y/2          Show then

x = 13 - 5y  / 2  + 4y = 13     Simplify

simplify  13 - 13y  / 2   as   y = 3  

as 13/2 = 6.5 and 2.5 +4 = 6.5

y = 3

Substitute y = 3

13-5y )3) / 2

13-5 (3)  / 2

BODMAS Brackets first Multiplying only for y substitute 5y = 5 x 3

-5 (3) = 15

13-15 = -2

-2/2 = -1

x = -1

Answer:

I think its 20.696

sorry if its wrong

Step-by-step explanation:

Answer: Dimes= 20, Nickels= 15

Step-by-step explanation:

Since we are looking for the amount of coins, we can use system of equations to solve for the amount of coins.

Equation 1:

0.1x+0.05y=2.75

This equation comes from the total cost. x stands for dimes and y stands for nickels. 0.1 is the worth of a dime and 0.05 is the worth of a nickel.

Equation 2:

x=2y-10

This equation comes from 10 less than twice the number of nickels.

We can use substitution to find x and y.

0.1(2y-10)+0.05y=2.75

0.2y-1+0.05y=2.75

0.25y-1=2.75

0.25y=3.75

y=15

There are 15 nickels.

Now that we have y, we can plug it back into the equation to find x.

x=2(15)-10

x=30-10

x=20

There are 20 dimes.

Answer:

4 and 8/21

Step-by-step explanation:

w-5/7=3 2/3

Find 3 2/3 + 5/7

3 2/3 + 5/7 = 3 14/21 + 15/21 = 3 29/21 = 4 8/21

W= 4 8/21

Answer:

w = 92/21

Step-by-step explanation:

Step 1:  Convert into improper fractions

5/7 -> 5/7

3 2/3 -> 3 * 3/3 + 2/3 -> 9/3 + 2/3 -> 11/3

Step 2:  Make common denominator

5/7 * 3/3 -> 15/21

11/3 * 7/7 -> 77/21

Step 3:  Add 15/21 to both sides

w - 15/21 + 15/21 = 77/21 + 15/21

w = 92/21

Answer:  w = 92/21