In a triangle, a segment is drawn joining the midpoint of two sides. What is true about this segment? It is parallel to the 3rd side. Its length is twice the 3rd side. Its length is equal to the 3rd side. It is to the 3rd side.

Answers

Answer 1
Answer: The right answer for the question that is being asked and shown above is that: "Its length is twice the 3rd side." In a triangle, a segment is drawn joining the midpoint of two sides. The statement that is true about this segment is that Its length is twice the 3rd side.
Answer 2
Answer:

Answer:

The midpoint theorems says that the line made by joining the two midpoints of the two sides of a triangle is always parallel to the third side of the triangle. The length of the midsegment is half the length of the third side.

Step-by-step explanation:


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Alaina bought a square frame for her desk that has an area of 81 square inches. What is the perimeter of the frame? (answer should be a number only)

Answers

Given:

Area of a square frame = 81 square inches.

To find:

Perimeter of the frame.

Solution:

Let length of each side of the frame = a inches.

Area of square frame is

Area=a^2

81=a^2

Taking square root on both sides,

\pm√(81)=a

\pm 9=a

Side length cannot be negative. So, a=9 inches.

Perimeter of frame is

Perimeter=4a

Perimeter=4(9)

Perimeter=36

Therefore, the perimeter is 36 inches.

Final answer:

The perimeter of the frame is 36 inches.

Explanation:

To find the perimeter of a square, we need to know the length of its sides. Since the area of the frame is given as 81 square inches, we can find the length of one side by taking the square root of the area. The square root of 81 is 9, so each side of the frame measures 9 inches.

Since a square has four equal sides, we can find the perimeter by multiplying the length of one side by 4. Therefore, the perimeter of the frame is 9 inches x 4 = 36 inches.

Learn more about Perimeter here:

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Solve and SHOW YOUR WORK for the equation 4m + 2(m + 1) = 9m + 5Solve and SHOW YOUR WORK for the equation 3(4x – 2) = 9 + 2x + 5

Answers

4m + 2(m + 1) = 9m + 5

What we need to do here is combine like terms, then apply the inverse operation, and finally, isolate the variable. 

Here's how it's done: 

4m + 2m + 2 = 9m + 5
4m and 2m are like terms, so add them together. 
4m + 2m = 6m 

6m + 2 = 9m + 5
-6m         -6m

2 = 3m + 5
-5          -5

3m = -3
3m/3 = -3/3
m = -1 should be your answer.


Next one: 
3(4x – 2) = 9 + 2x + 5
12x - 6 = 9 + 2x + 5
 -2x              -2x

10x - 6 = 9 + 5
10x - 6 = 14
        +6   +6

10x = 20
x = 2 should be your answer.

Please HELPPPP
Ill offer over 15 BRANLIST!! PLEASSEEEE

Answers

Answer:

Dilation by a scale factor of 2 followed by a reflection over the y axis.

Step-by-step explanation:

The Y-axis is the vertical axis. So that cancels out the two about the x-axis. Then I counted the length of both triangles bases. Luckily for this one their bases aren't tilted but just flat. The big one is 6 and the small 3. Since it is going from one to the other you must find what number completes their equation. 3x = 6.

2

So that's how I got the last part of the problem

Sorry if this doesn't make sense. It seems just like ramble but it should help.

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Answers

Answer:

77 180-26=154 sence its iscosolice dived that by 2 154/2=77

Step-by-step explanation:

if brainiest is earned its greatly apprieciated

Answer:

i think its x= 18 degrees but i dont know so i apologize if its wrong

Step-by-step explanation:

Let a=x^2+4. Use a to find the solutions for the following equation: (x^2+4)^2+32=12x^2+48. Which one of the following are solutions for x? Select any/all that apply. -8, -2, 4, 0, 2, -4, 8

Answers

(x^2+4)^2+32=12x^2+48 \n(x^2+4)^2+32=12(x^2+4) \ \ \ |-12(x^2+4) \n(x^2+4)^2-12(x^2+4)+32=0 \n\hbox{substitute a for } x^2+4: \na^2-12a+32=0 \na^2-4a-8a+32=0 \na(a-4)-8(a-4)=0 \n(a-8)(a-4)=0 \na-8=0 \ \lor \ a-4=0 \na=8 \ \lor \ a=4 \n \n\hbox{substitute 8 and 4 for a and solve for x:} \na=8 \n\Downarrow \n8=x^2+4 \ \ \ |-4 \n4=x^2 \nx=-2 \ \lor \ x=2 \n \na=4 \n\Downarrow \n4=x^2+4 \ \ \ |-4 \n0=x^2 \nx=0 \n \n\boxed{x=-2 \hbox{ or } x=0 \hbox{ or } x=2}

The solutions for x are -2, 0, 2.

Answer:

-2,0,2

Step-by-step explanation:

The given equation is:

(x^2+4)^(2)+32=12x^2+48

(x^2+4)^(2)+32=12(x^2+4)

Substituting (x^2+4)=a in the above equation, we get

a^(2)+32=12a

a^2-12a+32=0

a^2-4a-8a+32=0

a(a-4)-8(a-4)=0

(a-8)(a-4)=0

a=8,4

Now,  (x^2+4)=a, then substituting the value of a in this equation,

x^(2)+4=8 and x^2+4=4

x^(2)+4=8

x={\pm}2 and

x^(2)+4=4

x=0

Thus, the value of x are -2,0 and 2.

Factorise p^-6p+8

Explanation would be helpful too. Thank you so much.

Answers

assuming you meant
p^2-6p+8
then
find what 2 numbes multiply to get 8 and add to get -6
numbers are -2 and -4
(p-2)(p-4)
(p-4)(p-2)

The 2 numbers have to add up to make the -6
-2+-4=-6
and they have to multiply together to make 8
-2 x -4 = 8

hope this helps!