What Is Oxidation Reaction

Answers

Answer 1

Answer:

Oxidation reaction is a type of reaction wherein there is a loss of electrons. An oxidation reaction may also be a reducing agent. Example is the reaction Zn + 2H+ = Zn2+ + H2. When you separate them by their half cell reaction, you have 2H+ 1e- = H2. H here is the reducing agent and has lost 1 electron in the process.

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Which of the following is a product formed when NaCl decomposes? A. Na2 B. Nac2 C. cl2

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What is true of the rate of radioactive decay? A. The rate is constant. B. The rate is continuously accelerating. C. The rate is continuously decelerating. D. The rate is exponentially accelerating.

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The truest of the rate of radioactive decay is that the rate is exponentially accelerating. The answer is letter D. The rate is constant, the rate is continuously accelerating, the rate is continuously decelerating do not answer the question above.

Answer:

its a) the rate of decay is constant.

An object has a density of 1.75 g/mL. Will it float on water? Why?

Answers

Answer:

The object will not float in water because the density of the object is greater than that of water.

Explanation:

Density of object = 1.75 g/mL

Density of water = 1 g/mL

The Density of the object is 1.75 g/mL and that of water is 1 g/mL. This implies that the object is denser (i.e heavier) than water. Therefore, the object will not float in water, rather it will sink in water since it's density is greater than that of water.

A student determines that according to the reaction N2(g) + 3H2(g) --> 2NH3(g), if 34g of nitrogen gas is reacted with excess hydrogen, 41g of ammonia can be produced. When the actual reaction was complete, only 38g of ammonia formed. Determine the percent yield for the reaction.

Answers

Answer:

The percent yield of this reaction is 92.7 %

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 34.0 grams

Mass of ammonia (NH3 produced = 41.0 grams

Molar mass of N2 = 28.0 g/mol

Molar mass of NH3 = 17.02 g/mol

Actual yield of ammonia = 38 grams

Step 2: The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 34.0 grams / 28.0 g/mol

Moles N2 = 1.214 moles

Step 4: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 1.214 moles N2 we'll have 2* 1.214 = 2.428 moles NH3

Step 5: Calculate mass NH3

Mass NH3 = moles * molar mass

Mass NH3 = 2.428 moles * 17.02 g/mol

Mass NH3 = 41 grams

Step 6: Calculate percent yield for the reaction

Percent yield = (actuald yield / theoretical yield) * 100 %

Percent yield = (38 grams / 41 grams ) * 100 %

Percent yield = 92.7 %

The percent yield of this reaction is 92.7 %

Answer:

$Y=92\%$

Explanation:

Hello,

In this case, by considering the given chemical reaction, with given mass of nitrogen, one could compute the theoretical yield of ammonia as shown below and considering their 1 to 2 molar relationship in the chemical reaction:

$m_(NH_3)^(theoretical)=34gN_2*(1molN_2)/(28gN_2)*(2molNH_3)/(1molN_2)*(17gNH_3)/(1molNH_3) \nm_(NH_3)^(theoretical)=41.3gNH_3$

In such a way, the percent yield is obtained as shown below:

$Y=(m_(NH_3)^(actual))/(m_(NH_3)^(theoretical)) *100\%=(38g)/(41.3g) *100\%\n\nY=92.0\%$

Best regards.

A student adds 0.40g of sodium hydroxide to a clean, dry 250 mL beaker and leaves the beaker and leaves the beaker on the lab table. The mass of the empty beaker is 112.58g. After 24 hours, the student observes that the beaker contains a dry, solid white residue. The total mass of the beaker and its contents is 113.09g. Following are three possible chemical reactions that could have occured: Sodium Hydroxide (solid) + Carbon Dioxide (gas) rightarrow Sodium Bicarbonate (solid) Sodium Hydroxide (solid) + Carbon Dioxide (gas) rightarrow Sodium Carbonate (solid) + Water (gas) Sodium Oxide (solid) rightarrow Sodium Oxide (solid) + Water (gas) Use your knowledge of stoichiometry to determine which chemical reaction occurred. Show your work, and explain your reasoning whenever needed.

Answers

2 NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

Explanation:

The most probably chemical reaction is:

2 NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

Sodium Hydroxide (solid) + Carbon Dioxide (gas) → Sodium Carbonate (solid) + Water (gas)

In this reaction the water you obtain have to be in liquid form because the reaction takes place at room temperature. However because the student left the beaker for 24 hours, the water have a plenty of time to evaporate, so in the end only sodium carbonate (Na₂CO₃) remained in the beaker.

number of moles = mass / molar weight

number of moles of NaOH = 0.4 / 40 = 0.01 moles

Taking in account the chemical reaction, we devise the following reasoning:

if 2 moles of NaOH produce 1 mole of Na₂CO₃

then 0.01 moles of NaOH produce X mole of Na₂CO₃

X = (0.01 × 1) / 2 = 0.005 moles of Na₂CO₃

mass = number of moles × molar weight

mass of Na₂CO₃ = 0.005 × 106 = 0.53 g

mass of Na₂CO₃ = mass of beaker and its contents after 24h - mass of empty beaker

mass of Na₂CO₃ = 113.09 - 112.58 = 0.51 g which is close the theoretical value of 0.53 g.

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number of moles