Which are acceptable names for the plane?Choose all answers that are correct.

A. Plane AU

B. Plane JAU

C. Plane R

D. Plane ABC

Answers

Answer 1

Answer: I would say C.) and B.) would be the answer

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Cos3x=4cos^3x-3cosx prove

Answers

$\bf cos(\alpha + \beta)= cos(\alpha)cos(\beta)- sin(\alpha)sin(\beta)\n\n\n\textit{also recall that }cos(2\theta)=\begin{cases}cos^2(\theta)-sin^2(\theta)\n1-2sin^2(\theta)\n\boxed{2cos^2(\theta)-1}\end{cases}\n\n\nand\qquad sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\n\n-------------------------------$

$\bf cos(3x)=4cos^3(x)-3cos(x)\n\n-------------------------------\n\ncos(3x)\implies cos(2x+x)\implies cos(2x)cos(x)-sin(2x)sin(x)\n\n\n\[2cos^2(x)-1]cos(x)-[2sin(x)cos(x)]sin(x)\n\n\n2cos^3(x)-cos(x)~~~~-~~~~2sin^2(x)cos(x)\n\n\n2cos^3(x)-cos(x)~~~~-~~~~2[1-cos^2(x)]cos(x)\n\n\n2cos^3(x)-cos(x)~~~~-~~~~[2cos(x)-2cos^3(x)]\n\n\n2cos^3(x)-cos(x)~~~~-~~~~2cos(x)+2cos^3(x)\n\n\n4cos^3(x)-3cos(x)$

There are 5 roads from Allen to baker, 7 roads from baker to Carlson, and 4 roads from Carlson to dodge. How many different routes from Allen to dodge by way of baker and Carlson are possible?

Answers

Answer:

140 routes

Total Number of roads from allen to dodge through baker and Carlson is 140 routes.

Step-by-step explanation:

Given;

Number of roads from Allen to baker = 5

Number of roads from baker to Carlson = 7

Number of roads from Carlson to dodge = 4

Total Number of routes from allen to dodge through baker and Carlson is;

N = 5×7×4

N = 140 routes

Answer:

140 different routes

Step-by-step explanation:

The first path (Allan to Baker) has 5 different options, so there are 5 possibilities. After that, there are 7 possibilities from Baker to Carlson. Then, there are 4 possibilities from Carlson to Dodge. To find the total number of possibilities, we just need to multiply the number of possibilities of each track, so:

5 * 7 * 4 = 140 possibilities, that is, 140 different routes.

Here is a picture of a math problem.

Answers

y = 3x-5
(3, ) - your x is 3 in that case, y = 3*3-5 = 4 - answer (3,4)
(4, ) - your x is 4, y = 4*3-5 = 7 - answer (4,7)
( ,10) - your y is 10:
10 = 3x - 5
3x = 15
x = 5 - answer (5, 10)

Solution pairs - (3, 4); (4, 7); (5, 10)

What is 194 in radical form

Answers

The radical form of 194 = √2 x √97

To find the radical form of 194,

we need to factorize it into its prime factors.

So, let's start by dividing 194 by the smallest prime factor, which is 2,

⇒ 194 ÷ 2 = 97

We can see that 97 is a prime number,

so we can't divide it any further.

Therefore, the prime factorization of 194 is,

⇒ 194 = 2 x 97

Now, we can write the radical form of 194,

⇒√194 = √(2 x 97)

We can simplify this expression by breaking it down into the product of two separate square roots:

⇒ √(2 x 97) = √2 x √97

⇒The radical form of 194 is √2 x √97.

To learn more about radical form visit:

brainly.com/question/29052172

#SPJ6

194 in radical form is just √194. I don't believe any square roots go into it. Hope that helps. :)

Use the following number line to determine if the expressions are true or false.

Answers

Answer:

${ \tt{a < b→true}} \n { \bf{reason :because \: - 1 \: is \: less \: than \: 4.5 }}\n \n { \tt{ |a| > b →false}} \n { \bf{reason :1 \: is \: not \: greater \: than \: 4.5 }}\n \n { \tt{a < |b| →true}}$