MATHEMATICS HIGH SCHOOL

Pleaseeee help me I really need it Which technique is most appropriate to use to solve each equation? Drag the name of the technique into the box to match each equation.

(x+4)(x−9)=0 completing the square
square root property
4x² = 20
zero product property

Answers

Answer 1

Answer:

Answer:

i) Zero product property

ii) Square root property

Step-by-step explanation:

(x + 4)(x -9) = 0

Here we are equating each factor equal to zero and find the solutions.

Therefore it is Zero product property.

4x^2 = 20

To find the value of x, we take the square root on both sides.

So it is square root property.

Hope this will helpful.

Thank you.

Answer 2

Answer:

Answer:

The person above be is correct

Step-by-step explanation:

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Solve this using substitution y=4x-8 and y=2x+10

Answers

$\left\{\begin{array}{ccc}y=4x-8\ny=2x+10\end{array}\right\n\n4x-8=2x+10\n4x-2x=10+8\n2x=18\ \ \ /:2\nx=9\n\ny=4\cdot9-8=36-8=28\n\nAnswer:x=9\ and\ y=28$

Subtract 3 from 4/9 of 20

Answers

Answer:

5 8/9

Step-by-step explanation:

20*4/9=8 8/9

8 8/9–3=5 8/9

Los Angeles Airport bears 140 degrees from San Francisco Airport and is 540 km away. A pilot is planning a direct flight from San Francisco Airport to Los Angeles Airport to leave at 2 P.M. The plane's air speed will be 640 km/h, and there will be a 60 km/hwind blowing from 290 degrees. What should the compass heading be,and what is the plane's estimated time of arrival (ETA) to the nearest minute?

Answers

Create a triangle starting with the length of 540 coming out of SF to LA bearing 140.
This looks like it leaves SF in IV quadrant and enters LA in II quadrant. The wind will take the plane more to the east (right). Therefore the pilot must aim to the west (left) in order for the wind to push it to the intended destination of LA. The second side of the triangle should come out of LA from the II quadrant bearing 290. The length of this side is 60t (60 km/h * t = time flying). The third side of the triangle connects the first two. There for it comes out of SF at some unknown angle > 140 and connects with the 60t side. The length of this third leg is 640t. (640 km/h * t = time flying). The angle between the 540 side and the 60t side is 30. This is found because the 540 side enters LA in 2nd quadrant as 130 angle . The 60t side enters LA in 2nd quadrant as 160 angle. Using law of sin's: sin 30/640t = sin x/60t. The t's cancel and you are left with sin x = 3/64. When solving for the angle x you get x = 2.6867 degrees. Adding this to the bearing of 140, the compass bearing should be 142.6867 or 142.7 degrees. To find the value of t, you use the law of sin's to get sin 30/640t = (sin (180 - 30 - 2.6867))/540. Solving for t gives you: t = .7811. This is in hours. To convert to minutes multiply by 60 to get t = 46.87 minutes. Add this to the 2pm departure time to get 2:47 pm arrival time.

Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches. 80 in² 135 in² 160 in²

Answers

Answer:

Option 1st is correct

area of a triangle is, 80 in²

Step-by-step explanation:

Area of triangle(A) is given by:

$A = (1)/(2) b \cdot h$

where,

b is the base

h is the height or altitude of the triangle respectively.

As per the statement:

Base of a triangle(b) = 10 inches and

Height = altitude(h) = 16 inches

Substitute these in [1] we get:

$A = (1)/(2)(10) \cdot 16$

⇒ $A = 5 \cdot 16 = 80$ in²

Therefore, the area of a triangle is, 80 in²

10 × 16 = 160
160 / 2 = 80

Your answer would be 80in²

Hope that helps!

Mikey and some of his friends went to play paintball yesterday. The park where they played charges $5.59 per game they play for each person. If Mikey brought 7 friends with him, and the total amount they paid was $178.88, how many games of paintball did they play?A. 32
B. 5
C. 4
D. 22