The product of two consecutive odd integers is 2,115. Find the integers. Which of the following quadratic equations could be used to solve the word problem?a. x² + x - 2,115 = 0
b. x² + 2x - 2,115 = 0
c. x² + 2x + 2,115 = 0

Answers

Answer 1
Answer: Hello,

Answer B


Let x the first number
 x+2 the second

x*(x+2)=2115
==>x²+2x-2115=0
==>x=45 or x=-47
==>(x=45 and x+2=47)  or (x=47 and x+2=-45)


Answer 2
Answer:

Answer:

x² + 2x - 2,115 = 0

Step-by-step explanation:

Two consecutive odd integers looks like x+2. consecutive numbers are x+1. (odd numbers skip by 2 numbers. like between 5 and 7 is 2. )

SOOOO....

Now we can start. The product of two consecutive odd integers looks like

x(x+2) and it equals 2, 115 ---> x(x+2)=2,115

solve left side: x^2 +2x = 2,115

then move 2115 to left side to have a quadratic equation (make it equal to zero)

now we have:

x^2 +2x -2,115=0

that is you answer!

Hope it helps! ;)


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Four times a number, x, plus five times a number, y, equals 79. Ten times x minus 5 times y equals 5. Find the numbers by setting up a system of linear equations and solving the system using the elimination method.a) x = 7, y = 9 b) x = 6, y = 11 c) x = 8, y = 10 d) x = -10, y = 7
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HELPPP ASAPPP! PLZWhich system has no solution? A.4y = 2x – 6 B.3x + 5y = 7 4x = 2y – 5 C.2y = 4x + 2 D.2x = 5y + 4 15y = 6x – 12
21 years 8 months =months?

Solve -5(3 n + 4) = 40.

Answers

the answer is n=-4 because you need to solve for n
-5(3 n + 4) = 40
-15n-20=40
-15n=40+20
-15n=60
  n=-4

This is relay hard i need help 19 point available

Answers

order of operations
PEMDAS
parenthaseees
exponents
multiplication or division whichever comes first
addition or subtraction whichever comes first

parenthases first
inner to outer
left to right
treat a/b as (a)/(b) so simplify the fraction top and bottom as much as possible
the parenthaseese we have to simplify are
(20-5^2), (16+2^2), (3*2^2)

(20-5^2)
exponents first
5^2=25
now we have
(20-25)
subtract
20-25=-5
other parenthasees

16+2^2
exponent,
2^2=4
16+4=20

next
3*2^2
exponent
2^2=4
3*4=12

so the equaiton we have now is
((-5)(20))/(-2^(3)+(12))

exponents
-2^3 =-1 times 2^3
exponent first
2^3=8
-1 times 8=-8

now we hav
((-5)(20))/(-8+(12))
treat the numberator and denomenator as if they are in parenthasees so try to simplify them next
(-5)(20)=-100
-8+12=4

now we have
(-100)/(4)
division
-100/4=-25

Please help with this

Answers

Answer:

Step-by-step explanation:

y = mx + b

Take any two points and set up 2 equations with 2 unknowns.

I'll start with the first two

y = 4x + b

410 = 4x + b                    (1)

440 = 6x + b                   (2)

Subtract (1) from (2)

440 = 6x + b

410 = 4x + b            Subtract

30  = 2x                  Divide by 2

30/2 = 2x/2

x = 15

440 = 6(x) + b

440 = 6*15 + b

440 = 90   + b

b = 350

Now here is what you found.

Her base salary is 350 dollars

Each television she sells brings her an addition 15.

A bus and a car leave from the same city traveling in opposite directions. The bus leaves 2 hours before the car does. The bus travels at a steady speed of 50 mph while the car travels at 70 mph. After how many hours will the bus and car be 800 miles apart?

Answers


Normally, I would pass right by this question, because it is so complicated
and there are so many numbers in it.  But I've allowed myself to become
seduced by the bounty of a full 5 points waiting at the end of the rainbow,
and I decided to rush in where more reasonable people would rightly fear
to tread.

The answer is a number, that represents "after how many hours".  So we
need to know how many hours AFTER WHAT.  The question is not very
clear on when the beginning of time is, so I need to decide.  I'm going to
say that the time when the bus leaves is the beginning of time.  And I'm
going to call  ' H '  the number of hours AFTER the bus leaves.

-- The bus covers 50 miles every hour.  So 'H' hours after the bus leaves,
the bus is  50H  miles away from the city, in some direction.

-- The car leaves 2 hours later.  So 'H' hours after the bus leaves, the car
has only been traveling for  (H-2)  hours.

-- The car covers 70 miles every hour.  So 'H' hours after the bus leaves,
the car is  (70)x(H-2)  miles away from the city, in the OTHER direction.

-- Since the bus and the car are moving in opposite directions, the distance
between the bus and the car is the SUM of the distances each one covers.

     'H' hours after the bus leaves, they are  (50H) plus (70)(H-2) miles apart.

What we need to figure out is:  When is that distance 800 miles ?


The distance between them at 'H' hours after the bus leaves is

                                                            (50H) plus (70)(H-2) miles

Eliminate the first parentheses:             50H  +  (70)(H-2)

Eliminate the rest of the parentheses:   50H  +  70H - 140

Combine the terms with 'H' in them:         120H - 140

So here's the equation:                            120H - 140 = 800

Add  140  to each side:                            120H          =  940

Divide each side by  120 :                             H  =  7.8333 hours
                                                                           =  7 and 5/6 hours
                                                                           =  7 hours and 50 minutes
                                                                                 after the bus leaves.

Check:

Assume that  H = 7 hrs 50 minutes  (7 and 5/6 hours)
The bus has covered  (50 x 7-5/6) = 391 and 2/3 miles.
 
The car has been traveling for only  5 and 5/6 hours
The car has covered   (70) x (5-5/6) =  408 and 1/3 miles

How far apart are they ?   (391-2/3) + (408-1/3) =  800 miles !           YAY!   


Note:  If the book or the homework sheet wants to count the hours
after the CAR leaves, then the answer is  5-5/6 hours, not 7-5/6 . 

Complete the comparison: 3 + 7 > ?
A. 8+2
B. 10- 2
C. 7+3
D.9+4

Answers

3+7>10-2
This is because this simplifies to;
10>8
Answer is B. 3+7>10-2
The Answer is D! Because > means that the number on the right hand side is more than the left just think of it as an arrow! —>

Amanda’s dad is twice as old as she is today. The sum of their ages is 66. Find the ages of Amanda and her dad.

Answers

Let amanda's age be x and her dad's age be y.

Amanda’s dad is twice as old as she,  therefore 2x=y

The sum of their ages is 66, therefore x+y=66

x+y=66

2x=y,

substitute.

2x+x=66

3x=66

Divide.

x=22.

plug it back in, 22+y=66, y=44.

Amanda's age is 22 and her dad's age is 44.