Suppose a scientist made a claim that all spontaneous reactions are exothermic. Whic of the following would provide the strongest challenge to their claim? Suppose a scientist made a claim that all spontaneous reactions are exothermic. Which of the following would provide the strongest challenge to their claim? a. An exothermic reaction which is not spontaneous
b. An endothermic reaction that only proceeds when coupled to an exothermic reaction
c. An endothermic reaction that only proceeds when a catalytst is present
d. An endothermic reaction which is not spontaneous
e. All of the above

Answers

Answer 1
Answer:

Answer: Option (c) is the correct answer.

Explanation:

It is given that the scientist is claiming that all the spontaneous reactions are exothermic in nature.

And, it is known that when a reaction is spontaneous in nature then \Delta G is negative.

Now, the relation between Gibb's free energy, enthalpy and entropy is as follows.

               \Delta G = \Delta H - T \Delta S

So, when a catalyst is present in a chemical reaction then we do not need to give large amount of heat from outside. And, because of this the enthalpy of reaction will not be highly positive.

Hence, the value of \Delta G will result in a negative value which means the reaction is spontaneous.

Thus, we can conclude that an endothermic reaction that only proceeds when a catalytst is present, would provide the strongest challenge to their claim.


Related Questions

A compound is found to contain 18.28 % phosphorus , 18.93 % sulfur , and 62.78 % chlorine by mass. To answer the question, enter the elements in the order presented above. QUESTION 1: The empirical formula for this compound is . QUESTION 2: The molar mass for this compound is 169.4 g/mol. The molecular formula for this compound is
The correct electron configuration for magnesium is: 1s 22s 22p 63s 3 True False
Calculate the pH of the solution formed when 45.0 mL of 0.100M NaOH solution is added to 50.0 mL of 0.100M CH3COOH (Ka for acetic acid = 1.8 x10-5 ).
I have always enjoyed eating tuna fish. Unfortunately,a study of the mercury content of canned tuna in 2010 foundthat chunk white tuna contains 0.6 ppm Hg and chunk lighttuna contains 0.14 ppm. (S. L. Gerstenberger, A. Martinson,and J. L. Kramer, Environ. Toxicol. Chem. 2010, 29, 237.) TheU.S. Environmental Protection Agency recommends no morethan 0.1 mg Hg/kg body weight per day. I weigh 68 kg. Howoften may I eat a can containing 6 ounces (1 lb 5 16 oz) ofchunk white tuna so that I do not average more than 0.1 mgHg/kg body weight per day? If I switch to chunk light tuna,how often may I eat one can?
Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is 2.5 x 10-14. Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is a.2.5 x 10-14 M. b. 8.5 x 10-6 M c. 6.3 x 10-11 M d. 1.3 x 10-12 M e. 5.0 x 10-2 M f. 1.8 x 10-5 M

How does a pharmaceutical percolator work

Answers

Final answer:

A pharmaceutical percolator is a device used to extract active compounds from plants or herbs. It works by passing a solvent through the material to dissolve the desired components. The process involves maceration, percolation, and filtration.


Explanation:

A pharmaceutical percolator is a device used in the pharmaceutical industry to extract active compounds from plants or herbs. It works on the principle of percolation, which involves passing a solvent through a solid material to dissolve the desired components. The percolation process involves three main steps:

  1. Maceration: The plant material is crushed or ground and mixed with a suitable solvent, such as ethanol or water. This mixture is then allowed to stand for a specific period, usually several hours or days, to allow the solvent to dissolve the active compounds.
  2. Percolation: The macerated mixture is then transferred to the percolator, which is a vessel with a perforated plate or bottom. The solvent is poured onto the mixture, and gravity pulls it down through the solid material, dissolving the active compounds along the way.
  3. Filtration: The liquid containing the dissolved active compounds, known as the percolate, is collected at the bottom of the percolator and filtered to remove any solid particles or impurities. The resulting solution can then be further processed or used directly in the production of pharmaceutical products.

Learn more about pharmaceutical percolator here:

brainly.com/question/1183058


How is Hess's law used to measure enthalpy of a desired reaction?A. The enthalpy is obtained from the enthalpy of an intermediate
step.
B. The enthalpy is determined from the enthalpy of similar reactions.
C. The enthalpy from the final equation in a series of reactions is
used
D. Intermediate equations with known enthalpies are added together.

Answers

Hess's law is used to measure the enthalpy of a desired chemical reaction because: D. Intermediate equations with known enthalpies are added together.

What is Hess's Law?

Hess's Law is also known as Hess's law of constant heat summation (enthalpy) and it was named after a Swiss-born Russian chemist called Germain Hess.

Hess's Law states that the energy change (enthalpy) experienced in a desired chemical reaction is equal to the sum of the energy changes (enthalpies) in each chemical reactions that it is made up of or contains.

Read more on Hess's Law here: brainly.com/question/9328637

The amount of heat required to melt 2 lbs of ice is twice the amount of heat required to melt 1 ib of ice. is this observation a macroscopic or microscopic description of chemical behavior? Explain your answer.

Answers

The observation in this instance relates to the quantity of heat needed to melt ice, and it is expressed in terms of weights (2 lbs and 1 lb) and a comparison (twice the amount).

Without going into detail into the different molecules or their interactions, it concentrates on the general behaviour and characteristics of the substance (ice) as a whole.

A microscopic description, on the other hand, would describe the behaviour in terms of the molecular or atomic interactions that take place at the particle level. It would go into ideas such as the amount of heat required to dissolve the intermolecular interactions between water molecules.

Therefore, the observation regarding how much heat is needed to melt ice is a macroscopic description since it ignores the underlying molecular interactions in favour of the substance's general behaviour and qualities.        

Learn more about Molecules, refer to the link:

brainly.com/question/32298217

#SPJ12

The observation that melting 2 lbs of ice requires twice the heat of melting 1 lb is a macroscopic description, focusing on observable properties and behavior without exploring microscopic details.

This observation is a macroscopic description of chemical behavior. Macroscopic descriptions involve the properties and behavior of substances on a large scale that can be observed directly, without delving into the molecular or atomic details. In this case, the statement refers to the amount of heat required to melt a certain quantity of ice, and it is expressed in terms of macroscopic, measurable quantities (pounds of ice and the associated heat).

The macroscopic observation does not provide insight into the molecular or atomic interactions within the ice but rather focuses on the overall behavior of the substance. The concept that the amount of heat required to melt 2 lbs of ice is twice that needed for 1 lb of ice is a statement about the material's behavior at a larger scale.

This observation aligns with the macroscopic principles of heat and phase transitions, where the heat required for a phase change is directly proportional to the mass of the substance undergoing the transition. The macroscopic perspective is concerned with observable properties and measurements, making it a practical and accessible way to describe chemical behavior without delving into microscopic details.

For more such information on: melting

brainly.com/question/40140

#SPJ6

A solution is dilute when?A. it has a lot of solute
B. has little solvent
C. it has a lot of solvent
D. has maximum solute

Answers

The answer to your equation is C. Hope this Helps!
C. It has more solvent
To dilute a solution means to add more solvent without the addition of more solute

One way to experimentally measure the heat capacity of a Styrofoam cup calorimeter would be to melt a known mass of ice in warm water and measure hte temperature change. Use the data below to determine the experimental heat capacity of the calorimeter. Use the literature heat of fusion for ice in your calculations. Assume the ice added is at 0.00 c.Mass of ice added: 17.69gMass of water in calorimeter: 98.67gT-Initial of water: 28.7T-Final of water after melting ice: 12.9C

Answers

Answer:

4.88 Cals per degree celsius

Explanation:

We have taken heat of fusion of ice = 80 cals / g

We have taken speciic heat of water = 1 cal/g per degree celsius

In this experiment ,  let the heat capacity of calorimeter be X.

Heat gained by ice

heat gained in melting + heat gained in getting warmed

= mass x latent heat + mass x specific heat x rise in temperature

= 17.69 x 80 + 17.69 x 1 x ( 12.9 - 0 )

= 1643.4 Cals

Heat lost by water

=  mass x specific heat x fall in temperature

98.67 x 1 x ( 28.77 - 12.9 )

= 1565.89 Cals

Heat lost by calorimeter

heat capacity x fall in temperature

X x ( 28.77 - 12.9 )

Heat gained = heat lost

1643.4 = 1565.89 +15.87X

X = 4.88 Cals per degree celsius

How many moles of argon are in 4.80x10^24 atoms of argon

Answers

Answer:

7.97 mol Ar

Explanation:

Use Avogadro's number to convert atoms to moles.  This number is the number of atoms in one mole.  There are 6.022 × 10²³ atoms in one mole.

Divide the number of atoms given by Avogadro's number.

(4.80 × 10²⁴)/(6.022 × 10²³) = 7.97 mol

There are 7.97 moles of argon.

Answer:

3.0 moles  (A P E X)

Explanation: