A ten mile area of trees is removed from the tropical rainforest. How will this affect the amount of water and the amount of oxygen in the area?

Answers

Answer 1
Answer: We know that the roots of the trees would absorb the water under the ground. This is necessary for photosynthesis. Photosynthesis would produce food for the tree and as by product, oxygen is produced. Removing the tree would decrease the water consumption but would also decrease the oxygen production. 
Answer 2
Answer:

Removing the tree would decrease the water consumption but would also decrease the oxygen production.

What is a tropical rainforest?

Tropical rainforests are found in Central and South America, western and central Africa, western India, Southeast Asia, the island of New Guinea, and Australia.

Sunlight strikes the tropics almost straight on, producing intense solar energy that keeps temperatures high, between 21° and 30°C (70° and 85°F).

Deforestation has an adverse affect on air by reducing the amount of oxygen and increasing the amount of carbon dioxide as well as contributing to global warming.

Photosynthesis would produce food for the tree and as by - product, oxygen is produced.

Removing the tree would decrease the water consumption but would also decrease the oxygen production.

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At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)

Answers

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

Final answer:

The temperature needed for a sample of gas to occupy 91.3 L, when originally it occupied 45.0 L at 70.0°C at constant pressure, is about 423.71°C.

Explanation:

This question pertains to the ideal gas law equation (P1V1/T1 = P2V2/T2, where P is pressure, V is volume, and T is temperature), we must first convert our temperatures to Kelvin (K) since the ideal gas law uses absolute temperature. To convert from degrees Celsius to K, add 273.15, thus 70.0°C becomes 343.15K. As the problem states pressure is constant, we can ignore that component of the equation and it simplifies to V1/T1 = V2/T2.

By rearranging the equation to solve for V2, we get V2 = V1 (T2/T1). Given the volume of the gas at the initial temperature (V1 = 45.0 L), and temperature T2 with unknown value, we rewrite the equation as T2 = (V2 * T1) / V1. Substituting the given values into the equation gives T2 = (91.3 L * 343.15K) / 45.0 L, which calculates to approximately 696.86K, converting back to Celsius gives us around 423.71°C.

So, your sample of gas would need to be heated to approximately 423.71°C in order for it to occupy a volume of 91.3 L at constant pressure.

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