The formula that relates the length of a ladder, L, that leans against a wall with distance d from the base of the wall and the height h that the ladder reaches up the wall is mc024-1.jpg. What height on the wall will a 15-foot ladder reach if it is placed 3.5 feet from the base of a wall?

Answers

Answer 1

Answer: We will use the Pythagorean theorem to determine the height: $h^(2)=15^(2) - 3.5^(2)$ $h^(2) =225 - 12.25=212.75$ Finally: $h= √(212.75)=14.5859$
Answer Ladder will reach the height of 14.59 feet ( to the nearest hundredths).

Answer 2

Answer:

Answer: it's 14.6 feet

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If the perimeter of a square is 208 what ia the length of one side

Answers

208/4= 52
the answer is 52

how do you find the least common multiple of these two expressions. 10x^5v^8 and 25x^4v^7u^2

Answers

$10x^5v^8=5x^4v^7\cdot2xv\n\n25x^4v^7u^2=5x^4v^7\cdot5u^2\n\nLCM(10x^5v^8;\ 25x^4v^7u^2)=5x^4v^7\cdot2xv\cdot5u^2=50x^5v^8u^2$

$10x^(5) v^(8)= 1*2*5*x*x*x*x*x*v*v*v*v*v*v*v*v \n 25 x^(4) v^(7) u^(2)=1*5*5*x*x*x*x*v*v*v*v*v*v*v*u*u \n$
Underline all the numbers which are common in both the factorisations. Write them down:
$5 x^(4) v^(7)$
There, you have your LCM of both the expressions.

Pretty stuck on this paper,someone help out? an explanation would be appreciated as well!

Answers

I can help you with graphing quadratics in intercept form. Here's a step-by-step guide:

Step 1: Identify the intercepts

The intercepts are the points where the parabola crosses the x-axis and y-axis. In intercept form, the x-intercepts are given by the factors of the quadratic expression. For example, in the equation f(x) = 2(x+4)(x+6), the x-intercepts are -4 and -6. To find the y-intercept, set x = 0 and solve for y.

Step 2: Find the vertex

The vertex is the point where the parabola reaches its maximum or minimum value. The x-coordinate of the vertex is the average of the x-intercepts. In the equation f(x) = 2(x+4)(x+6), the x-intercepts are -4 and -6, so the x-coordinate of the vertex is (-4 + -6)/2 = -5. To find the y-coordinate of the vertex, substitute the x-coordinate into the equation and solve for y.

Step 3: Plot the intercepts and vertex

Mark the intercepts and vertex on the coordinate plane.

Step 4: Sketch the parabola

Draw a smooth curve that passes through the intercepts and vertex. The parabola should be symmetric about the vertical line passing through the vertex.

Example:

Let's graph the equation f(x) = 2(x+4)(x+6).

Step 1: Identify the intercepts

The x-intercepts are -4 and -6. To find the y-intercept, set x = 0 and solve for y:

f(0) = 2(0+4)(0+6) = 48

So the y-intercept is (0, 48).

Step 2: Find the vertex

The x-coordinate of the vertex is (-4 + -6)/2 = -5. To find the y-coordinate of the vertex, substitute x = -5 into the equation:

f(-5) = 2(-5+4)(-5+6) = 2

So the vertex is (-5, 2).

Step 3: Plot the intercepts and vertex

Plot the intercepts (-4, 0), (-6, 0), and (0, 48), and the vertex (-5, 2) on the coordinate plane.

Step 4: Sketch the parabola

Draw a smooth curve that passes through the intercepts and vertex. The parabola should be symmetric about the vertical line passing through the vertex.

The graph of the equation f(x) = 2(x+4)(x+6) is a parabola that opens upwards and has intercepts at (-4, 0), (-6, 0), and (0, 48). The vertex of the parabola is at (-5, 2).

Select the correct answer.Mary deposited $350 in a bank account that promises 2.8 percent interest compounded continuously. Approximately how many years will it take to reach a balance of $500?

A.
1.43 years

B.
2.80 years

C.
5.55 years

D.
12.77 years