What is the value of 3x2 - 5xy + 5y2 for x = -6 and y = 2?
Answers
Related Questions
Water is being pumped to empty a swimming pool.At 6 a.m , the water level is 150 cm . Every 2 hours , the water level drops by 30 cm. what is the earliest time when the pool will be empt ??A)10 A.M.B)11 A.M.C) 4 P.M. D) 5 P.M.
What is the coefficient of x in the division (18x^3 + 12x^2 – 3x) / 6x^2?A) 3 B) 2 C) -0.5 D) -3
Which is the graph of f(x) = -(x + 3)(x + 1)?
123b is 0.4 of what number
2:45 p.m.
3:15 a.m.
3:00 p.m.
Answers
11:45 a.m. + 3 hours and 15 minutes = 12:00 p.m. + 3 hours = 15:00 p.m. = 3:00 p.m.
The correct result would be 3:00 p.m.
Answer:
300 pm
Step-by-step explanation:
Answers
Answer:
The answer is
-36-8= - 44
Answers
Answers
Answer:
Neither SSS nor SAS apply.
Step-by-step explanation:
SSS (Side-Side-Side)-
If three pairs of sides of two triangles are equal in length, then the triangles are congruent.
SAS (Side-Angle-Side)-
If two pairs of sides of two triangles are equal in length, and the included angles are equal in measurement, then the triangles are congruent.
It given in the picture that,
- AC = AD (Side)
- BC = DE (Side)
- m∠BAC = m∠EAD (Angle)
So, ΔABC and ΔAED will not be congruent by either SSS or SAS.
Answers
Solving quadratic equation 16 t² -60t -100=0 formed by Projectile Motion Formula and given conditions it is found that it takes t = 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.
What is a quadratic equation?
Quadratic equation is an equation which contains one unknown variable and the highest power of this unknown variable is 2. Let x be the unknown variable then the standard quadratic equation in x is given by
ax²+bx+c =0, where a, b, c are constants and a≠0
We can solve this equation by factorizing ax²+bx+c and putting those factors equal to zero to solve for x.
Projectile Motion Formula h = -16 t² + v t + s,
where t = time in seconds
h = height of the projectile
v = initial velocity
s= starting height of fall
Given s = 1000 feet, v= 60 feet per second, h = 900 ft
And t we have to find.
Projectile motion equation becomes:
900 = -16 t² + 60 t + 1000
⇒16 t² -60t + 900-1000=0
⇒16 t² -60t -100=0, which is a quadratic equation in variable t
Factorizing this quadratic equation
⇒ 16t² - 80t + 20t -100 =0
⇒16t(t -5) + 20( t - 5 ) =0
⇒ (16t +20) ( t-5)=0
Putting these factors equal to zero
16t +20 =0 ⇒ t = -20/16, which is neglected as time cannot be negative.
t-5 = 0⇒ t =5
Therefore it takes 5 seconds to fall from 1000 feet to 900 feet before the parachute opens.
Also, Learn more about the quadratic equations from the link below:
#SPJ1
Answer:It will take 5 sec for a parachute to open.I did it on a piece of paper for u to show u more information
Step-by-step explanation:
Answers
Answer:
y = -4/5x - 5
Step-by-step explanation:
4x + 5y = 45
we need to write it in slope intercept form, so:
5y = -4x + 45
y = -4/5x + 45/5
y = -4/5x + 9
The line is parallel so the slope will be -4/5x, point ( -5 -1 )
y = mx + b
-1 = -4/5(-5)+b
-1 = 4 + b
-1 - 4 = b
-5 = b
y = -4/5x - 5
The equation of the line that passes through the point (-5, -1) and is parallel to the line 4x + 5y = 45 is .
What is the equation of the parallel line?
Given the parameter:
Equation of the original line: 4x + 5y = 45
Point of the parallel line: (-5,-1)
First, we determine the slope of the original line:
4x + 5y = 45
4x - 4x + 5y = -4x + 45
5y = -4x + 45
y = (-4/5 )x + 45/5
y = (-4/5 )x + 9
Hence, the slope is -4/5.
Since the slope of the parallel line will be the same as that of the original line.
Plug the slope m = -4/5 and point (-5,-1) into the point-slope formula and simplify.
( y - y₁ ) = m( x - x₁ )
Therefore, the equation of the parallel line is .
Learn more about equation of line here: brainly.com/question/2564656
#SPJ3