In the laboratory a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction. A student heats 62.08 grams of magnesium to 97.96 °C and then drops it into a cup containing 77.81 grams of water at 23.19 °C. She measures the final temperature to be 35.60 °C. The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.79 J/°C. Assuming that no heat is lost to the surroundings calculate the specific heat of magnesium.

Answers

Answer 1
Answer:

Answer:

The specific heat of magnesium is 1.04 J/g°C.

Explanation:

Heat lost by the magnesium = Q

Mass of the magnesium = m  = 62.08 g

Heat capacity of  magnesium= c = ?

Initial temperature of the magnesium = T_1=97.96^oC

Final temperature of the magnesium= T  = 35.60 °C

Q=mc* (T-T_1)

Heat absorbed by coffee cup calorimeter  = Q'

Heat capacity of coffee cup calorimeter = C = 1.79 J/°C

Initial temperature of coffee cup calorimete =T_2 = 23.19°C

Final temperature of coffee cup calorimete = T  = 35.60 °C

Q'=C* (T-T_2)

Heat absorbed by the water = q

Mass of water = m' = 77.81 g

Heat capacity of water = c' = 4.18 J/g°C

Initial temperature of water =T_2 = 0°C

Final temperature of water = T

q=m'* c'* (T_2-T)

According law of conservation of energy , energy lost by coffee will equal to heat required to raise temperature of water and coffee cup calorimeter.

-Q=Q'+q

-(mc* (T-T_1))=C* (T-T_2)+m'* c'* (T-T_2)

62.08 g* c(97.96^oC-35.60^oC)=1.79 J/^oC* (35.60^oC-23.19^oC)+77.81g* 4.18 J/g^oC* (35.60^oC-23.19^oC)

On solving we get:

c = 1.04 J/g°C

The specific heat of magnesium is 1.04 J/g°C.


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A 3.25 L solution is prepared by dissolving 285 g of BaBr2 in water. Determine the molarity.

Answers

Answer:

0.295 mol/L

Explanation:

Given data:

Volume of solution = 3.25 L

Mass of BaBr₂ = 285 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Number of moles of solute:

Number of moles = mass/ molar mass

Molar mass of BaBr₂ = 297.1 g/mol

Number of moles = 285 g/ 297.1 g/mol

Number of moles= 0.959 mol

Molarity:

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M = 0.295 mol/L

Final answer:

The question is about calculating the molarity of a solution. First, convert the given mass of solute into moles using the molar mass. Then, using the molarity formula, divide the moles of solute by the volume of the solution in liters.

Explanation:

In order to determine the molarity of the solution, we will divide the amount of solute (in moles) by the volume of the solution (in liters). The formula for molarity (M) is:

M = moles of solute/volume of solution in liters

First, we need to convert the mass of BaBr2 into moles. The molecular weight of BaBr2 is 297.14 g/mol. So, 285 g of BaBr2 is equal to 285/297.14 = 0.959 moles.

 

The volume of the solution is given as 3.25 L. So, plugging these values into the formula gives us the molarity of the solution:

 

M = 0.959 moles/3.25 L = 0.295 M

So, the molarity of the solution is 0.295 M.

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