8.00*10^-5 mol was diluted to 500ml what is the concentration in Mol/L?

Answers

Answer 1

Answer: Make sure all units are consistent. Convert ml to L first. (500ml = 0.5L). Then divide the mole by the volume which would result to 1.6*10^-4mol/L. This can also be expressed as interms of molarity (M). 1 M = 1 mol/L hence the final answer is 1.6*10^-4 M.

Answer 2

Answer:

Answer : The concentration in mol/L is $1.6* 10^(-4)mol/L$

Explanation : Given,

Moles = $8.00* 10^(-5)mol$

Volume of solution = 500 mL

Formula used :

$\text{Concentration}=\frac{\text{Moles of solute}* 1000}{\text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Concentration}=(8.00* 10^(-5)mole* 1000)/(500mL)=1.6* 10^(-4)mol/L$

Therefore, the concentration in mol/L is $1.6* 10^(-4)mol/L$

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You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute below? (Ar:H51,Li57,N514,O516,Mg524,S532.)a lithium sulfate, Li2SO4

Answers

Answer:

0.045 L or 45 mL

Explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L

What happens when the kinetic energy of molecules increases so much that electrons are released by the atoms, creating a swirling gas of positive ions and negative electrons?

Answers

the answer is d in this case

Answer:

it's C

Explanation:

How many significant digits are in the volume measurement 0.100 L? (a) 1 (b) 2 (C) 3 (d) 4 (e) none of the above

Answers

C is the answer. The 1 and the two zeros behind the one are significant digits.

Final answer:

The volume measurement 0.100 L consists of 3 significant digits, counting the non-zero digit and the zero after the decimal point.

Explanation:

In the volume measurement 0.100 L, there are 3 significant figures. Significant figures represent the precision of a measured value. In this case, the zeroes after the decimal point are 'leading zeroes' which are not counted as significant. The '1' is a non-zero digit, which is always significant. And the zero after '1' is a 'trailing zero' that comes after a decimal point, so it is also counted as significant. Therefore, the number of significant figures in 0.100 L is 3.

Learn more about Significant Figures here:

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How does chlorine react with ethene?By substituting hydrogen with chlorine.
By breaking a carbon double bond and adding chlorine.
By removing hydrogen because of chlorine’s attraction to hydrogen’s nucleus.
Chlorine and ethene do not react spontaneously.

Answers

Answer : Option B) By breaking a carbon double bond and adding chlorine.

Explanation : When chlorine reacts with ethene it forms dicholoroethane. It reacts spontaneously to form product. The halogenation reaction takes place in ethene across the double bonds and removes the hydrogen from ethene and two chlorine atoms gets attached in their place; which results in dichloroethane as the product.

Answer: option B m

Explanation:

It is an example for Electrophilic Addition of Halogen. And addition of Cl2 to Alkene is always Trans Addition. That means both cl atoms should add opposite side of double bond and results vicinal 1,2-dichloroethane as a product.

CH2=CH2 + Cl2-------> ClCH2CH2Cl

6) At elevated temperatures, methylisonitrile (CH3NC) isomerizes to acetonitrile (CH3CN):CH3NC (g)  CH3CN (g)At the start of an experiment, there are 0.200 mol of reactant and 0 mol of product in the reaction vessel.After 25 min, 0.108 mol of reactant (CH3NC) remain. There are mol of product (CH3CN) in thereaction vessel.A) 0.200 B) 0.540 C) 0.022 D) 0.092 E) 0.308

Answers

Answer: The moles of product present in the vessel is 0.092 moles

Explanation:

For the given chemical equation:

$CH_3CN(g)\rightleftharpoons CH_3CN(g)$

We are given:

Initial moles of reactant = 0.200 moles

Unreacted moles of reactant = 0.108 moles

Reacted moles of reactant = 0.200 - 0.108 = 0.092 moles

By Stoichiometry of the reaction:

1 mole of reactant produces 1 mole of product

So, 0.092 moles of reactant will produce = $\frac{1}[1}* 0.092=0.092mol$ of product

Hence, the moles of product present in the vessel is 0.092 moles

The image is of the formation of a fault-block mountain.Which of these most likely occurs to result in the
formation of these mountains?
O The crust is compressed
O The crust does not spread apart
The center block is forced upward.
The hanging walls from the two parallel faults slip down

Answers

The Formation of these mountains will be caused by

The crust does not spread apart
The center block is forced upward.
The hanging walls from the two parallel faults slip down

Options B, C, and D is correct.

What are mountains?

Generally, a mountain is simply defined as a body that rises dramatically above its surroundings and is distinguished by steep slopes.

In conclusion, Mountains are formed from the formation of rocks over years in an Environment.