Answer:
CH2 --> sp2 hybridization.
C-C-C --> sp hybridization.
Explanation:
The CH2 has two simple bonds to the H and one double bond to another C. This means that in the hybridization of this C are involved 3 orbitals: 1 s and 2 p, resulting in a sp2 hybridization.
The C-C-C central carbon has two double bonds, one to each C. This means that in the hybridization of this C are involved 2 orbitals: 1 s and 1 p, resulting in a sp hybridization.
The hybridization of the CH2 carbon is 'sp2' and the middle CCC carbon's hybridization in all mentioned molecules is 'sp'.
The carbon in CH2 in all the three molecules, H2CCH2, H2CCCH2, and H2CCCCH2 is always connected to two other atoms: a carbon and a hydrogen. Therefore, its hybridization is
sp2
. The middle carbon in ccc sequence is also linked to two other carbons only. Its hybridization is also
sp
. To summarize, the CH2 carbon's hybridization in all the molecules is
sp2
and the middle CCC carbon's hybridization in all the molecules is
sp
.
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3.14 × 10²⁴ Formula Units
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (formula units) contained by 5.23 moles of NaNO₃, we will use following relation,
Moles = Number of F. Units ÷ 6.022 × 10²³ F. Units.mol⁻¹
Solving for Number of F. Units,
Number of F. Units = Moles × 6.022 × 10²³ F. Units.mol⁻¹
Putting values,
Number of F. Units = 5.23 mol × 6.022 × 10²³ Molecules.mol⁻¹
Number of F. Units = 3.14 × 10²⁴ F. Units
Hence,
There are 3.14 × 10²⁴ Formula Units present in 5.23 moles of NaNO₃.
0.75 mole of H2CO3 = 47 g
3.42 moles CO = 95.8 g
4.1 moles Li2O = 94 g
Answer:
4.1 moles Li2O = 94 g (incorrect)
4.1 mole of Li2O = 122.6g(correct)
Explanation:
1. Molar mass of O2 = 32
0.2 mole of 32 = 0.2×32 = 6.4g (correct)
2. Molar mass of H2CO3 = 62.03
0.75 mole of 62.03 = 0.75×62.03 = 46.5g (47 is correct)
3. Molar mass of CO = 28
3.42 moles of 30 = 3.42×28 = 95.76 (95.8 is correct)
4. Molar mass of Li2O = 29.9
4.1 mole of Li2O = 4.1×29.9 = 122.59g (94g is incorrect)
Answer:
It's 4.1 moles Li2O = 94 g on Odyssey ware
Answer:
No
Explanation:
Hello,
Since the sealed glass container is isolated (closed system) no escape of boiled water (steam) was presented, so it is obvious that the alchemists were wrong, it is impossible that the water turns into "earth" because it has components that water does not have by itself (metallic and nonmetallic ions and molecular compounds) that is why the solid residue could have come from suspended solids or simply solids that were initially dissolved and due to the boiling of water, they remained at the bottom of the flask. Nevertheless, the experiment done by Lavoisier was more precise because the conclusion based on the initial and final masses, accounts for the boiling process; besides, the mass agreement substantiates that no mass was removed due to the isolation of the flask.
Best regards.
b. period number.
c. number of protons.
d. number of valence electrons.
The chemical properties of an element are largely determined by the number of valence electrons. Thus option D is correct.
Valence electrons an atom is defined as the number of electron which lose or gain the nearest noble gas or inert gas electronic configuration.
The valence electrons are the main part of chemical reactions as these contain more energy as compared to the electrons present in inner orbits.
The number of valence electrons present helps to determine the chemical properties of element like valence or valency, bonds with other elements.
It also show a picture of the mechanism of bond formation of an atom, the number of unpaired electrons and how many atoms can take part.
Learn more about valence electron, here:
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