MATHEMATICS HIGH SCHOOL

What is the product of d – 9 and 2d2 + 11d – 4?A=2d3 – 7d2 – 103d + 36
B=2d3 – 7d2 – 95d + 36
C=2d3 + 7d2 – 95d + 36
D=2d3 + 7d2 – 103d + 36

Answers

Answer 1

Answer:

Answer:

$2d^3-7d^2-103d+36$

A is the correct option.

Step-by-step explanation:

We have to find the product

$(d-9)(2d^2+11d-4)$

Using the distributive property (term by term multiplication), we have

$d\cdot2d^2+d\cdot11d+d\cdot(-4)-9\cdot2d^2-9\cdot11d-9\cdot(-4)$

On multiplying, we get

$2d^3+11d^2-4d-18d^2-99d+36$

Combine like terms

$2d^3-7d^2-103d+36$

A is the correct option.

Answer 2

Answer:

Answer:

(A) $2d^3-7d^2-103d+36$

Step-by-step explanation:

It is given that there are two functions that are $(d-9)$ and $2d^2+11d-4$ and

We have to find the product of $(d-9)$ and $2d^2+11d-4$ , therefore we can write as:

$(d-9)(2d^2+11d-4)$

$2d^3-18d^2+11d^2-99d-4d+36$

$2d^3-7d^2-103d+36$

which is the required product.

Thus, Option A is correct.

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A student uses the substitution method to solve the system of equations below algebraically.2x - y = 5 3x + 2y = -3 Which equivalent equation could be used?
The floor of a rectangular deck has an area of 600 sq. ft. The floor is 20 ft. wide. How long is the floor?

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Answers

Answer: b

Step-by-step explanation:

because it is

Which relation is a function?

Answers

Of the provided graphs, the second would be the correct answer.

Functions occur when the input only has one possible output (though the output can be recieved through multiple inputs)

The relation shown in the 2nd diagram is a function. The reason for this is that one and only one y-value is associated with each x-value.

Note that this is not true of the first diagram. If x=0, there are two separate y vaues associated: -1 and 2. This clearly states that the first diagram does not represent a function.

a boy flies a kite with a 100 foot long string. the angle of elevation of the string is 48 degrees. how high is the kite from the ground?

Answers

we know that
in a right triangle
sin ∅=opposite side angle ∅/hypotenuse
opposite side angle ∅=hypotenuse*sin ∅

in this problem
angle ∅=48°
hypotenuse=100 ft
opposite side angle ∅=?----> height of the kite from the ground

opposite side angle ∅=100*sin 48°------> 74.31 ft

the answer is
74.31 ft

Find the supplement of each, (a) 136 degreeâ€‹

Answers

Answer:

supplement is 44°

Step-by-step explanation:

supplementary angles , sum to 180°

the angles are the supplement of each other.

then the supplement of 136° = 180° - 136° = 44°

Final answer:

The supplement of an angle is what you would need to add to it to equal 180 degrees. So, to find the supplement of 136 degrees, you would subtract 136 from 180, which gives 44 degrees.

Explanation:

In Mathematics, two angles are said to be supplementary if their measurements add up to 180 degrees. Hence, to find the supplement of an angle, we subtract the given angle from 180 degrees.

In your case, to find the supplement of 136 degrees, you would subtract 136 from 180. The equation would look something like this: 180 - 136 = 44. Hence, the supplement of a 136 degree angle is 44 degrees.

Learn more about Supplementary Angles here:

brainly.com/question/31741214

#SPJ11

How to factor: a^2+11a+18

Answers

$a^2+11a+18\n\n-----------------------------\n\n11=9+2\n18=9\cdot2\n\n-----------------------------\n\na^2+11a+18=(a+9)(a+2)$

$a^2+11a+18=a^2+2a+9a+18=a(a+2)+9(a+2)=\n\n=(a+2)(a+9)$

How can I factorise (2x cubed - 5x + 3) ?

Answers

$2x^3-5x+3=2x^3-2x-3x+3\n\n=2x(x^2-1)-3(x-1)\n\n=2x\underbrace{(x^2-1^2)}_(use\ (*))-3(x-1)\ \ \ |(*)\ a^2-b^2=(a-b)(a+b)\n\n=2x\underbrace{(x-1)}_((**))(x+1)-3\underbrace{(x-1)}_((**))\n\n=(x-1)[2x(x+1)-3]\n\n=(x-1)\underbrace{(2x^2+2x-3)}_((***))\n\n(***)\ 2x^2+2x-3\to a=2;\ b=2;\ c=-3\n\nx=(b^2\pm√(b^2-4ac))/(2a)$

$therefore\nx=(-2\pm√(2^2-4(2)(-3)))/(2(2))=(-2\pm√(4+24))/(4)=(-2\pm√(28))/(4)=(-2\pm√(4\cdot7))/(4)=(-2\pm2\sqrt7)/(4)\n\n=(-1\pm\sqrt7)/(2)\n\nso,\ the\ answer:\n\n(x-1)\cdot2\left(x-(-1-\sqrt7)/(2)\right)\left(x-(-1+\sqrt7)/(2)\right)\n\n=\boxed{(x-1)(2x+1+\sqrt7)\left(x+(1-\sqrt7)/(2)\right)}=\boxed{(1)/(2)(x-1)(2x+1+\sqrt7)(2x+1-\sqrt7)}$

2x³ - 5x +3

P = Finding the divisors of the constant 3 : 1 and 3
Q = Finding the divisors of the master coefficient 2 : 1 and 2

Now verify the probably roots: +- p/q
+- 1/1 , +-1/2 , +-3/1 , +-3/2

+-1 , +-1/2 , +-3    , +- 3/2

x=1 is root: 2x³-5x+3 = 2(1)³-5(1)+3 = 0

If x=1 is root, so x-1=0

Divinding by (x-1)

2x³+0x²-5x+3 | x-1
-2x³+2x² 2x² +2x-3
  0 +2x²-5x
-2x²+2x
0 -3x +3
3x - 3
0 0

So,
2x³-5x+3 = (x-1)(2x²+2x-3)

(x-1)(2x²+2x-3)

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